UNIT 5: MECHANICAL VIBRATIONS
I. FUNDAMENTALS & SINGLE DEGREE OF FREEDOM (SDOF) SYSTEMS
Degrees of Freedom (DOF)
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Definition: Minimum number of independent coordinates required to define the system's configuration.
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Types:
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Translational DOF: Linear motion (e.g., mass on a spring).
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Rotational DOF: Angular motion (e.g., pendulum, torsional system).
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Examples:
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1-DOF: Simple spring-mass system, simple pendulum.
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2-DOF: Two masses connected by springs, vehicle model (heave & pitch).
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Multi-DOF: Multi-story building, complex machinery.
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Equation of Motion (EOM) for SDOF
- Standard Form:
$$m\ddot{x} + c\dot{x} + kx = F(t)$$
where $m$ = mass, $c$ = damping constant, $k$ = stiffness, $F(t)$ = external force.
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Derivation via Newton's Second Law (FBD):
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Draw Free Body Diagram (FBD) of mass.
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Apply $$\displaystyle \sum F = m\ddot{x} $$: $$\displaystyle -k x - c\dot{x} + F(t) = m\ddot{x} $$.
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Rearrange to standard form.
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Derivation via Rayleigh's Energy Method (Frequently asked):
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Total Energy: $$\displaystyle T + V = \text{constant} $$ (for conservative, undamped systems).
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Kinetic Energy: $$\displaystyle T = \frac{1}{2}m\dot{x}^2 $$.
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Potential Energy: $$\displaystyle V = \frac{1}{2}kx^2 $$.
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Differentiate: $$\displaystyle \frac{d}{dt}(T+V) = 0 \Rightarrow m\dot{x}\ddot{x} + kx\dot{x} = 0 $$.
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Divide by $\dot{x}$ (assuming $\dot{x} \neq 0$): $$\displaystyle m\ddot{x} + kx = 0 $$.
[!TIP] Rayleigh's method is energy-based and avoids drawing FBDs. It's valid for conservative systems without non-conservative forces like damping or explicit forcing.
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Free Vibration of Undamped SDOF
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EOM: $$\displaystyle m\ddot{x} + kx = 0 $$.
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Solution: $$\displaystyle x(t) = A\sin(\omega_n t) + B\cos(\omega_n t) $$.
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Natural Frequency:
$$\omega_n = \sqrt{\frac{k}{m}} \quad \text{(rad/s)}$$
$$f_n = \frac{\omega_n}{2\pi} \quad \text{(Hz)}$$
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Natural Frequency of Systems with Multiple Springs:
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Series: $$\displaystyle \frac{1}{k_{eq}} = \frac{1}{k_1} + \frac{1}{k_2} + \cdots $$
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Parallel: $$\displaystyle k_{eq} = k_1 + k_2 + \cdots $$
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Apply $$\displaystyle \omega_n = \sqrt{k_{eq}/m} $$.
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Free Vibration of Damped SDOF
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Viscous Damping:
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Model: Damping force $$\displaystyle F_d = c\dot{x} $$, proportional to velocity.
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EOM: $$\displaystyle m\ddot{x} + c\dot{x} + kx = 0 $$.
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Coulomb (Dry Friction) Damping:
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Model: Constant magnitude force $$\displaystyle F_d = \mu N \cdot \text{sign}(\dot{x}) $$, opposes motion.
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Characteristics: Amplitude decreases linearly, frequency slightly less than $$\displaystyle \omega_n $$, motion is non-sinusoidal (saw-tooth).
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Damping Ratio ($\zeta$):
$$\zeta = \frac{c}{c_c} = \frac{c}{2\sqrt{km}}$$
* $$\displaystyle \zeta < 1 $$: Underdamped (oscillatory).
* $$\displaystyle \zeta = 1 $$: Critically damped (fastest return to equilibrium without oscillation).
* $$\displaystyle \zeta > 1 $$: Overdamped (slow return, no oscillation).
- Critical Damping Constant ($$\displaystyle c_c $$):
$$c_c = 2\sqrt{km}$$
* **Importance**: Boundary between oscillatory and non-oscillatory motion. Used as reference for damping ratio.
- Damped Natural Frequency ($$\displaystyle \omega_d $$): For underdamped ($$\displaystyle \zeta < 1 $$):
$$\omega_d = \omega_n \sqrt{1 - \zeta^2}$$
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Logarithmic Decrement ($\delta$):
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Definition: $$\displaystyle \delta = \ln\left(\frac{x(t)}{x(t+T_d)}\right) $$, ratio of successive amplitudes.
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Relation to $\zeta$:
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$$\delta = \frac{2\pi\zeta}{\sqrt{1-\zeta^2}}$$
* **Limitation**: Formula assumes underdamped motion ($$\displaystyle \zeta < 1 $$). For $\zeta \geq 1$, no oscillations occur, so $\delta$ is undefined.
- Comparison: Underdamped vs. Coulomb Damped Free Vibration:
| Feature | Viscous (Underdamped) | Coulomb Damped |
|---|---|---|
| Amplitude Decay | Exponential: $$\displaystyle x \propto e^{-\zeta\omega_n t} $$ | Linear: $x$ decreases by constant $$\displaystyle \frac{4\mu N}{k} $$ per half-cycle |
| Frequency | $$\displaystyle \omega_d = \omega_n\sqrt{1-\zeta^2} $$ (slightly less than $$\displaystyle \omega_n $$) | $$\displaystyle \omega_d \approx \omega_n \left(1 - \frac{2\mu N}{\pi k A_0}\right) $$ (depends on initial amplitude $$\displaystyle A_0 $$) |
| Motion | Sinusoidal with decaying envelope | Non-sinusoidal (sharp corners near turning points) |
Forced Vibration of SDOF (Harmonic Force)
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Forcing Function: $$\displaystyle F(t) = F_0 \sin(\omega t) $$.
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Steady-State Response: $$\displaystyle x_{ss}(t) = X \sin(\omega t - \phi) $$.
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Magnification Factor (Dynamic Magnification, $M$):
- Definition: Ratio of dynamic amplitude to static deflection under $$\displaystyle F_0 $$.
$$M = \frac{X}{X_{st}} = \frac{X}{F_0/k}$$
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Derivation & Expression:
Substitute $$\displaystyle x_{ss} = X\sin(\omega t - \phi) $$ into EOM $$\displaystyle m\ddot{x}+c\dot{x}+kx=F_0\sin\omega t $$.
After algebra:
$$\boxed{M = \frac{1}{\sqrt{(1 - r^2)^2 + (2\zeta r)^2}}}$$
where $$\displaystyle r = \omega / \omega_n $$ (frequency ratio).
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Resonance:
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Condition: $r \approx 1$ (for low $\zeta$).
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Amplitude at Resonance ($$\displaystyle r=1 $$):
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$$M_{res} = \frac{1}{2\zeta}$$
* **Phase at Resonance**: $$\displaystyle \phi = \pi/2 $$.
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Effect of Damping:
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Resonance Peak: Decreases as $\zeta$ increases.
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Bandwidth: Increases as $\zeta$ increases. Bandwidth $\Delta r \approx 2\zeta$ for small $\zeta$.
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Special Cases & Applications of SDOF
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Base Excitation / Vibration Isolation:
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Setup: Base motion $$\displaystyle y(t) = Y \sin(\omega t) $$.
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Relative Displacement: $$\displaystyle z = x - y $$.
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EOM (in terms of $z$): $$\displaystyle m\ddot{z} + c\dot{z} + kz = -m\ddot{y} $$.
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Transmissibility (Displacement):
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$$T_d = \frac{X}{Y} = \frac{r^2}{\sqrt{(1-r^2)^2 + (2\zeta r)^2}}$$
* **Transmissibility (Force)**: $$\displaystyle T_f = \frac{F_{trans}}{F_0} = \sqrt{1 + (2\zeta r)^2} \cdot T_d $$.
* **Isolator Design**:
* For **isolation** ($$\displaystyle \omega > \omega_n $$), need $$\displaystyle r > \sqrt{2} $$.
* **Stiffness** from transmissibility requirement: $$\displaystyle k = m\omega_n^2 $$.
* **Maximum Isolator Deformation**: $$\displaystyle \delta_{max} = X_{max} + Y $$ (if base and mass move in phase).
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Rotating Unbalance:
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Equivalent Force: $$\displaystyle F_0 = m_e e \omega^2 $$, where $$\displaystyle m_e $$ = eccentric mass, $e$ = eccentricity.
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Steady-State Amplitude:
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$$X = \frac{m_e e \omega^2 / m}{\sqrt{(\omega_n^2 - \omega^2)^2 + (2\zeta\omega_n\omega)^2}} = \frac{m_e e}{m} \cdot \frac{r^2}{\sqrt{(1-r^2)^2+(2\zeta r)^2}}$$
* **Critical Speed**: Speed at which $$\displaystyle \omega = \omega_n $$ (resonance). Must be avoided in rotating machinery.
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Vehicle/Trailer Vibration on Sinusoidal Road (Jun 2025):
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Model: Trailer as SDOF with base excitation from road profile $$\displaystyle y = Y \sin(\frac{2\pi}{\lambda} v t) $$, where $\lambda$ = wavelength, $v$ = speed.
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Critical Speed: Occurs when forcing frequency $$\displaystyle \omega = \frac{2\pi v}{\lambda} = \omega_n $$.
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$$v_{crit} = \frac{\lambda \omega_n}{2\pi}$$
* **Amplitude at Speed $v$**: Use $$\displaystyle r = \omega/\omega_n $$ in transmissibility formula $$\displaystyle X = T_d Y $$.
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Recoil Mechanisms (Jun 2025):
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Model: Critically damped SDOF ($$\displaystyle \zeta=1 $$).
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EOM: $$\displaystyle m\ddot{x} + c_c\dot{x} + kx = 0 $$, with $$\displaystyle c_c = 2\sqrt{km} $$.
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Design for Maximum Recoil Distance $$\displaystyle x_{max} $$:
Given initial recoil velocity $$\displaystyle v_0 $$, initial displacement $$\displaystyle x_0=0 $$.
For critical damping, solution: $$\displaystyle x(t) = (A + Bt)e^{-\omega_n t} $$.
Apply ICs: $$\displaystyle x(0)=0 \Rightarrow A=0 $$; $$\displaystyle \dot{x}(0)=v_0 \Rightarrow B=v_0 $$.
Max displacement occurs at $$\displaystyle t=0 $$? Actually for $$\displaystyle \zeta=1 $$, $$\displaystyle x(t) = v_0 t e^{-\omega_n t} $$. Max at $$\displaystyle t=1/\omega_n $$.
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$$x_{max} = \frac{v_0}{e \omega_n} \approx \frac{v_0}{2.718 \omega_n}$$
Given $$\displaystyle x_{max} $$ and $$\displaystyle v_0 $$, solve for $$\displaystyle \omega_n $$, then $$\displaystyle k = m\omega_n^2 $$.
Total Response of SDOF
- Principle of Superposition:
$$x(t) = x_h(t) + x_p(t)$$
* $$\displaystyle x_h(t) $$: **Complementary (Transient) Solution** to homogeneous EOM ($$\displaystyle F(t)=0 $$). Depends on damping.
* $$\displaystyle x_p(t) $$: **Particular (Steady-State) Solution** to forced EOM. Independent of ICs.
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Initial Conditions: $$\displaystyle x(0) = x_0 $$, $$\displaystyle \dot{x}(0) = v_0 $$.
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Complete Solution Forms:
- Underdamped ($$\displaystyle \zeta<1 $$):
$$x(t) = e^{-\zeta\omega_n t} \left[ C_1 \sin(\omega_d t) + C_2 \cos(\omega_d t) \right] + X\sin(\omega t - \phi)$$
Determine $$\displaystyle C_1, C_2 $$ from ICs.
* **Critically Damped** ($$\displaystyle \zeta=1 $$):
$$x(t) = (C_1 + C_2 t) e^{-\omega_n t} + x_p(t)$$
* **Overdamped** ($$\displaystyle \zeta>1 $$):
$$x(t) = C_1 e^{s_1 t} + C_2 e^{s_2 t} + x_p(t)$$
where $$\displaystyle s_{1,2} = -\zeta\omega_n \pm \omega_n\sqrt{\zeta^2-1} $$.
II. MULTI DEGREE OF FREEDOM (MDOF) SYSTEMS
Modeling & Equations of Motion
- Matrix Form:
$$\boxed{[M]\ddot{\mathbf{x}} + [C]\dot{\mathbf{x}} + [K]\mathbf{x} = \mathbf{F}(t)}$$
where $[M]$, $[C]$, $[K]$ are mass, damping, stiffness matrices; $\mathbf{x}$ is displacement vector.
- Writing EOM: Use Newton's method or D'Alembert's principle. Draw FBD for each mass, write $$\displaystyle \sum F = m_i\ddot{x}_i $$, include internal forces from springs/dampers.
Free Vibration Analysis (Undamped)
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Assumption: Harmonic motion $$\displaystyle \mathbf{x}(t) = \boldsymbol{\phi} \sin(\omega t + \phi) $$.
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Eigenvalue Problem:
Substitute into undamped EOM $$\displaystyle [M]\ddot{\mathbf{x}} + [K]\mathbf{x} = \mathbf{0} $$:
$$\left([K] - \omega^2 [M]\right) \boldsymbol{\phi} = \mathbf{0}$$
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Natural Frequencies ($$\displaystyle \omega_i $$):
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Roots of characteristic equation: $$\displaystyle \det([K] - \omega^2 [M]) = 0 $$.
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For $n$-DOF system, $n$ eigenvalues $$\displaystyle \omega_1^2, \omega_2^2, \dots, \omega_n^2 $$ (ordered $$\displaystyle \omega_1 < \omega_2 < \dots $$).
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Normal Modes / Mode Shapes ($$\displaystyle \boldsymbol{\phi}_i $$):
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Definition: Deflected shape at which all points move sinusoidally at frequency $$\displaystyle \omega_i $$.
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Amplitude Ratio: For a given mode $i$, ratio $$\displaystyle \phi_{j,i} / \phi_{k,i} $$ is constant (relative amplitudes of coordinates $j,k$).
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Orthogonality Properties:
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$$\boldsymbol{\phi}_i^T [M] \boldsymbol{\phi}_j = 0 \quad (i \neq j)$$
$$\boldsymbol{\phi}_i^T [K] \boldsymbol{\phi}_j = 0 \quad (i \neq j)$$
Modes are orthogonal with respect to mass and stiffness matrices.
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Modal Analysis Procedure:
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Form $[M]$, $[K]$.
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Solve $$\displaystyle \det([K] - \omega^2 [M]) = 0 $$ for $$\displaystyle \omega_i^2 $$.
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For each $$\displaystyle \omega_i $$, solve $$\displaystyle ([K] - \omega_i^2[M])\boldsymbol{\phi}_i = \mathbf{0} $$ for $$\displaystyle \boldsymbol{\phi}_i $$ (up to scale factor).
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Normalize mode shapes (e.g., $$\displaystyle \boldsymbol{\phi}_i^T[M]\boldsymbol{\phi}_i = 1 $$).
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Example Systems: Two-mass, three-mass spring-damper systems. Use matrix formulation.
Principal Coordinates
- Concept: Transform physical coordinates $\mathbf{x}$ to principal coordinates $\mathbf{q}$ such that EOMs decouple.
$$\mathbf{x} = [\Phi] \mathbf{q}$$
where $$\displaystyle [\Phi] = [\boldsymbol{\phi}_1, \boldsymbol{\phi}_2, \dots, \boldsymbol{\phi}_n] $$ is the modal matrix.
- Decoupling: Pre-multiply by $$\displaystyle [\Phi]^T $$:
$$[\Phi]^T[M][\Phi]\ddot{\mathbf{q}} + [\Phi]^T[K][\Phi]\mathbf{q} = [\Phi]^T\mathbf{F}(t)$$
Due to orthogonality, $$\displaystyle [\Phi]^T[M][\Phi] $$ and $$\displaystyle [\Phi]^T[K][\Phi] $$ are diagonal matrices.
Result: $n$ independent SDOF equations:
$$m_i^* \ddot{q}_i + k_i^* q_i = f_i(t)$$
where $$\displaystyle m_i^* = \boldsymbol{\phi}_i^T[M]\boldsymbol{\phi}_i $$, $$\displaystyle k_i^* = \boldsymbol{\phi}_i^T[K]\boldsymbol{\phi}_i = \omega_i^2 m_i^* $$.
- Determination: For a given spring-mass system, find $$\displaystyle \omega_i $$, $$\displaystyle \boldsymbol{\phi}_i $$ as above. Then $$\displaystyle \mathbf{q} = [\Phi]^{-1}\mathbf{x} $$. Since $[\Phi]$ is not necessarily orthogonal (only mass-orthogonal), use $$\displaystyle [\Phi]^T[M][\Phi] = [I] $$ if mass-normalized.
Torsional Systems
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Modeling: Replace linear springs with torsional springs ($$\displaystyle k_t $$ in N·m/rad), masses with rotary inertias ($J$ in kg·m²).
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EOM: $$\displaystyle J_i \ddot{\theta}_i + \sum k_t(\theta_i - \theta_j) = T_i(t) $$.
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Natural Frequencies: Solve $$\displaystyle \det([K_t] - \omega^2 [J]) = 0 $$, where $$\displaystyle [K_t] $$ is torsional stiffness matrix, $[J]$ is diagonal inertia matrix.
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Given Relationships: If $$\displaystyle k_0=2k_1 $$, $$\displaystyle J_2=2J_1 $$, substitute into matrices before solving eigenvalue problem.
III. SPECIAL SYSTEMS & APPLICATIONS
Continuous Systems (Approximate Methods)
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Beams in Bending:
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Natural Frequency of a beam with concentrated mass $m$ at a point:
Use Rayleigh's method: Assume mode shape (e.g., static deflection curve under $m$). Then:
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$$\omega_n^2 = \frac{k_{eq}}{m} = \frac{\text{Strain Energy}}{\text{Max Kinetic Energy}} = \frac{\int_0^L EI (y'')^2 dx}{m \cdot (\text{max deflection})^2}$$
For a simply supported beam with mass at midspan, $$\displaystyle y(x) = \frac{m g}{2EI} \left( \frac{L}{2}x - x^2 \right) $$ for $0 \le x \le L/2$.
* **Parameters**: $E$ = Young's modulus, $I$ = area moment of inertia, $l$ = length.
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Shaft Whirling:
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Critical Speed of Rotating Shaft: Rotational speed at which shaft deflection becomes very large (resonance).
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Proof that Critical Whirling Speed = Natural Transverse Frequency:
The equation for lateral vibration of a shaft with rotating disc is identical to that of a stationary beam with a concentrated mass, except the force is centrifugal $$\displaystyle m e \omega^2 $$. The critical condition occurs when forcing frequency $\omega$ equals the natural frequency $$\displaystyle \omega_n $$ of the shaft-disc system. Thus, critical whirling speed $$\displaystyle \omega_{crit} = \omega_n $$.
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Safety Check (Nov 2022 - cantilever shaft):
Given: shaft length $L$, rotor mass $m$, radius of gyration $k$, shaft $I$, $E$.
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Calculate $$\displaystyle \omega_n = \sqrt{\frac{EI}{m L^3}} $$ for cantilever with tip mass (approximate).
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Convert operating speed (rpm) to rad/s: $$\displaystyle \omega_{op} = \frac{2\pi N}{60} $$.
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Safe if $$\displaystyle \omega_{op} < 0.7 \omega_n $$ (typical margin). Or check if $$\displaystyle \omega_{op} \neq \omega_n $$.
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Gyroscopic Effects: Briefly, for high-speed rotors, gyroscopic moments couple bending modes, splitting critical speeds.
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Vibration Measurement & Instruments
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Vibrometer / Seismometer:
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Principle: Measures displacement. Natural frequency $$\displaystyle \omega_n $$ is very low ($\ll$ frequency of vibration). Mass is relatively large, spring very soft.
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Frequency Response: For $$\displaystyle \omega \ll \omega_n $$, $$\displaystyle X_{mass} \approx Y $$ (base displacement). Output proportional to relative displacement $x - y \approx -y$.
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Accelerometer:
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Principle: Measures acceleration. Natural frequency $$\displaystyle \omega_n $$ is very high ($\gg$ frequency of vibration). Spring is very stiff, mass small.
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Frequency Response: For $$\displaystyle \omega \gg \omega_n $$, $$\displaystyle m\ddot{x} \approx F(t) = -m\ddot{y} $$. So $\ddot{x} \approx \ddot{y}$. Output proportional to relative force $c\dot{z} \approx m\ddot{y}$.
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Derivation (General):
Relative displacement $$\displaystyle z = x - y $$.
EOM: $$\displaystyle m\ddot{z} + c\dot{z} + kz = -m\ddot{y} $$.
Steady-state: $$\displaystyle Z = \frac{m\omega^2 Y}{\sqrt{(k - m\omega^2)^2 + (c\omega)^2}} $$.
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Seismometer ($$\displaystyle \omega \ll \omega_n $$): $Z \approx Y$ → $x \approx 0$, $z \approx -y$.
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Accelerometer ($$\displaystyle \omega \gg \omega_n $$): $$\displaystyle Z \approx \frac{m}{k}\omega^2 Y $$ → $\ddot{z} \approx \ddot{y}$.
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Dynamic Vibration Absorber (Tuned Mass Damper - TMD)
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Concept: Attach a secondary mass-spring-damper ($$\displaystyle m_a, k_a, c_a $$) to primary system to reduce vibration at specific frequency $\omega$.
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Principle: Tune $$\displaystyle k_a $$ so that $$\displaystyle \omega_{na} = \omega $$ (the disturbing frequency). The absorber creates a force that cancels the force on the primary mass.
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Force Transmissibility Optimization (May 2024 - air compressor):
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For primary system $m,k$ with unbalance force $$\displaystyle F_0 \sin\omega t $$.
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With absorber, transmitted force to foundation is:
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$$F_{trans} = F_0 \cdot \frac{r^2 \left[ (1 - r_a^2)^2 + (2\zeta_a r_a)^2 \right]}{\left[ (1 - r^2)(1 - r_a^2) - r^2 r_a^2 \right]^2 + \left[ 2\zeta_a r_a (1 - r^2) - 2\zeta r r_a^2 \right]^2}$$
where $$\displaystyle r = \omega/\omega_n $$, $$\displaystyle r_a = \omega_a/\omega_n $$.
* **Design for Minimum Transmission**: Set $$\displaystyle r_a = 1 $$ (tune to $\omega$). Then optimize $$\displaystyle \zeta_a $$ for minimum $$\displaystyle F_{trans} $$ at $$\displaystyle r=1 $$:
$$\zeta_{a,opt} = \sqrt{\frac{3}{8} \frac{m}{m_a}}$$
* **Result**: At $$\displaystyle r=1 $$, $$\displaystyle F_{trans} = F_0 \cdot \frac{2\zeta_a}{\zeta_{a,opt}} $$? Actually, with optimal tuning, transmission can be made very small if $$\displaystyle m_a $$ is significant fraction of $m$.
* **For Given % Transmission**: Rearrange formula to find required $$\displaystyle m_a/m $$ and $$\displaystyle \zeta_a $$.
IV. DAMPING MECHANISMS & MATERIALS
Types of Damping
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Viscous Damping:
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Force: $$\displaystyle F_d = c\dot{x} $$.
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Energy dissipated per cycle: $$\displaystyle E_D = \int_0^T c\dot{x}^2 dt = \pi c \omega X^2 $$ (for harmonic $$\displaystyle x=X\sin\omega t $$).
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Coulomb (Dry Friction) Damping:
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Force: $$\displaystyle F_d = \mu N \cdot \text{sign}(\dot{x}) $$.
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Energy dissipated per half-cycle: $$\displaystyle E_D = 4\mu N A $$ (constant, independent of frequency).
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Hysteresis / Solid Damping / Structural Damping:
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Concept: Energy loss due to internal friction in material during cyclic loading. Stress-strain curve forms a hysteresis loop.
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Area under Hysteresis Curve: Represents energy dissipated per unit volume per cycle.
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Complex Stiffness Representation: Damping force in phase with velocity but modeled as imaginary stiffness:
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$$F_d = i k^* x \quad \text{or} \quad k_{complex} = k(1 + i\eta)$$
where $\eta$ = loss factor (damping ratio for structural damping: $$\displaystyle \zeta = \eta/2 $$ for small $\eta$).
Equivalent Damping
- Concept: Express energy dissipation of non-viscous damper in terms of an equivalent viscous damping constant $$\displaystyle c_{eq} $$ that dissipates same energy per cycle.
$$\int_0^T c_{eq} \dot{x}^2 dt = E_{D,actual}$$
For harmonic $$\displaystyle x = X\sin\omega t $$, LHS = $$\displaystyle \pi c_{eq} \omega X^2 $$.
* **For Coulomb Damping**: $$\displaystyle E_D = 4\mu N A \approx 8\mu N X $$ (since $A \approx X$). So:
$$c_{eq} = \frac{4\mu N}{\pi \omega X} \quad \text{(amplitude-dependent!)}$$
* **For Structural Damping**: $$\displaystyle E_D = \pi \eta k X^2 $$. So:
$$c_{eq} = \frac{\eta k}{\omega}$$
V. VIBRATION ISOLATION & CONTROL
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Isolation vs. Absorption:
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Isolation: Prevent vibration from source to foundation (use isolators under machine).
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Absorption: Add TMD to reduce vibration of structure.
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Design of Vibration Isolators:
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Determine Requirements: Limit transmitted acceleration/force or displacement.
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Calculate $$\displaystyle \omega_n $$: From transmissibility formula. For isolation ($$\displaystyle r > \sqrt{2} $$), $$\displaystyle T_d \approx 1/r^2 $$ for high $r$.
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Select Stiffness $k$: $$\displaystyle k = m \omega_n^2 $$.
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Check Damping: Low $\zeta$ (0.05–0.1) gives better isolation at high $r$, but higher $\zeta$ reduces resonance peak. Trade-off.
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Isolator Stiffness for Acceleration Limit (May 2024 - flow monitor):
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Given: base acceleration amplitude $$\displaystyle Y\omega^2 $$, max allowed mass acceleration $$\displaystyle a_{max} $$.
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Transmitted acceleration amplitude $$\displaystyle A = \omega^2 X $$.
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From transmissibility: $$\displaystyle X = T_d Y $$, so $$\displaystyle A = \omega^2 T_d Y $$.
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Set $$\displaystyle A \le a_{max} $$ → solve for $r$, then $k$.
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Example: $$\displaystyle a_{max} = 5g $$, $$\displaystyle Y\omega^2 = ? $$ Given $Y$ and $\omega$, compute $r$ from $$\displaystyle T_d = A/(\omega^2 Y) $$, then $$\displaystyle k = m \omega_n^2 = m (\omega/r)^2 $$.
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Maximum Displacement of Isolated System:
$$\displaystyle X_{max} = T_d Y_{max} $$.
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Maximum Isolator Deformation:
$$\displaystyle \delta_{max} = |x - y|_{max} = |X - Y| $$ if in phase, or $X + Y$ if out of phase. Generally, $$\displaystyle \delta_{max} \approx X_{max} + Y_{max} $$ (worst case).
VI. NOISE & VIBRATION – ACOUSTICS (Frequently Tested)
Sound Fundamentals
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Sound Pressure Level (SPL):
- Definition: Logarithmic measure of RMS sound pressure $p$ relative to reference pressure $$\displaystyle p_{ref} = 20 \ \mu\text{Pa} $$ (threshold of hearing).
$$\boxed{SPL \ (\text{dB}) = 20 \log_{10}\left(\frac{p}{p_{ref}}\right)}$$
* **0 dB SPL**: Means $$\displaystyle p = p_{ref} $$ (threshold of hearing), **not** zero sound pressure. It is a reference level.
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Sound Power Level (SWL):
- Definition: Logarithmic measure of acoustic power $W$ radiated by source relative to reference power $$\displaystyle W_{ref} = 10^{-12} \ \text{W} $$.
$$SWL \ (\text{dB}) = 10 \log_{10}\left(\frac{W}{W_{ref}}\right)$$
* **Relationship with SPL**: For a point source in free field, SPL decreases with distance $r$: $$\displaystyle SPL = SWL - 20\log_{10}(r) - 11 \ \text{dB} $$ (for $r$ in meters). SPL is **pressure-based**, SWL is **power-based** (source strength).
Sound Analysis
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Octave Band Analysis:
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Purpose: Break down complex noise into frequency bands to identify dominant frequencies and assess human ear response (which is logarithmic).
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Concept: Each band has upper frequency = 2 × lower frequency. Center frequency $$\displaystyle f_c $$ is geometric mean: $$\displaystyle f_c = \sqrt{f_1 f_2} $$.
- Example: 31.5 Hz band: 22.4–45 Hz (center 31.5).
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Use: Noise control (target dominant bands), compliance with standards (e.g., OSHA limits in octave bands), hearing protector selection.
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Human Response & Conservation
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Response of Human to Noise:
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Physiological: Hearing damage (temporary/permanent threshold shift), stress, hypertension.
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Psychological: Annoyance, reduced concentration, sleep disturbance.
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Frequency Sensitivity: Human ear most sensitive 2–5 kHz (speech frequencies).
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Hearing Conservation & Damage Risk Criteria:
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Permissible Exposure Limits (PEL): Time-weighted average (TWA) noise exposure allowed.
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OSHA: 90 dBA for 8 hours (5 dB exchange rate: 90 dBA/8h, 95 dBA/4h, 100 dBA/2h, etc.).
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NIOSH: 85 dBA for 8 hours (3 dB exchange rate: more protective).
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Precautions and Remedies (Nov 2023):
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Engineering Controls: Enclose noisy machines, use quieter processes, vibration isolation, mufflers.
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Administrative Controls: Rotate workers, limit exposure time, regular maintenance.
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Personal Protective Equipment (PPE): Earplugs, earmuffs (check Noise Reduction Rating - NRR).
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Hearing Protection Program: Audiometric testing, training, monitoring.
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Sound Intensity & Pressure Calculations
- Change in SPL with Distance (Inverse Square Law for point source in free field):
$$\Delta SPL = 20 \log_{10}\left(\frac{r_2}{r_1}\right)$$
* **Doubling Distance**: $$\displaystyle r_2 = 2r_1 $$ → $$\displaystyle \Delta SPL = 20 \log_{10}(2) \approx 6 \ \text{dB} $$ decrease.
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Conversion between SPL (dB) and Actual Pressure (May 2024):
Given $$\displaystyle SPL = 11.23 \ \text{dB} $$, $$\displaystyle p_{ref}=20 \ \mu\text{Pa} $$.
$$p = p_{ref} \times 10^{SPL/20} = 20 \times 10^{-6} \times 10^{11.23/20}$$
$$10^{11.23/20} = 10^{0.5615} \approx 3.64$$
$$p \approx 20 \times 10^{-6} \times 3.64 = 72.8 \ \mu\text{Pa}$$
> [!TIP] Remember: 0 dB = $$\displaystyle p_{ref} $$, 20 dB = $$\displaystyle 10 p_{ref} $$, 40 dB = $$\displaystyle 100 p_{ref} $$, etc. (20 dB per factor 10 in pressure).
VII. MISCELLANEOUS & DEFINITIONS (Short Note Topics)
Work Done by Harmonic Force (Nov 2023)
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Force: $$\displaystyle F(t) = F_0 \sin \omega t $$.
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Displacement: $$\displaystyle x(t) = x_0 \sin(\omega t - \phi) $$.
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Work over time $$\displaystyle t_1 $$ to $$\displaystyle t_2 $$:
$$W = \int_{t_1}^{t_2} F \dot{x} \ dt$$
- First Cycle ($$\displaystyle t_1=0, t_2=T=2\pi/\omega $$):
$$W_{cycle} = \frac{\pi F_0 x_0}{2} \cos\phi$$
* If $$\displaystyle \phi=0 $$ (in phase), $$\displaystyle W_{max} = \frac{\pi F_0 x_0}{2} $$.
* If $$\displaystyle \phi=\pi/2 $$ (90° lag), $$\displaystyle W=0 $$ (no net work, energy stored/returned).
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First Second: Plug limits $$\displaystyle t_1=0, t_2=1 $$ into integral. May not be integer cycles.
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First Quarter Second: $$\displaystyle t_1=0, t_2=0.25 $$ s. Compute definite integral numerically or analytically if $\omega$ known.
Fourier Series Expansion of Non-Periodic/Impact Forces (Jun 2025)
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Concept: Represent aperiodic force $F(t)$ (e.g., impact) as sum of sinusoidal components over a finite interval $[0, T]$, where $T$ is the "period" of the repeated pulse.
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Fourier Series:
$$F(t) = a_0 + \sum_{n=1}^{\infty} \left[ a_n \cos(n\omega_0 t) + b_n \sin(n\omega_0 t) \right]$$
where $$\displaystyle \omega_0 = 2\pi/T $$.
Coefficients:
$$a_0 = \frac{1}{T} \int_0^T F(t) dt$$
$$a_n = \frac{2}{T} \int_0^T F(t) \cos(n\omega_0 t) dt$$
$$b_n = \frac{2}{T} \int_0^T F(t) \sin(n\omega_0 t) dt$$
- Application: For forging hammer impact (rectangular pulse of force $$\displaystyle F_0 $$ duration $\tau$), compute integrals over $[0,T]$.
Node in Vibration (May 2024)
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Definition: A point or line in a vibrating structure that remains stationary (zero displacement amplitude) during a particular mode of vibration.
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Sketch: For a simply supported beam, first mode has one node at center? Actually, simply supported has no internal nodes for first mode. Fixed-fixed beam first mode has two nodes (points of zero displacement) between ends.
DiagramCANVAS: Sketch of a fixed-fixed beam in first bending mode, showing endpoints fixed, maximum deflection at center, and two nodes (points of zero deflection) symmetrically located between center and ends. -
Significance: Nodes indicate where structure does not move; useful for placing supports or isolators without affecting mode shape.
Whirling of Shafts (May 2024, Nov 2022)
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Explanation: Whirling is the precession (rotating bending deflection) of a shaft rotating at high speed. The shaft centerline describes a circle.
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Cause: Unbalance, gyroscopic moments, or external forces. At critical whirling speed, the rotational speed matches a natural bending frequency of the shaft-disc system, causing large amplitudes.
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Critical Speed: $$\displaystyle \omega_{crit} = \omega_n $$ (natural transverse frequency). Must operate below ~0.7 $$\displaystyle \omega_{crit} $$ for safety.
Energy Method in Vibration Analysis (Nov 2023)
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Rayleigh's Method:
- Principle: For conservative system, max potential energy = max kinetic energy.
$$\frac{1}{2} k_{eq} (\text{max deflection})^2 = \frac{1}{2} m (\text{max velocity})^2$$
For assumed mode shape $y(x)$, compute strain energy $$\displaystyle V = \int \frac{1}{2} EI (y'')^2 dx $$ and kinetic energy $$\displaystyle T = \frac{1}{2} \omega^2 \int \rho A y^2 dx $$ (or with concentrated masses). Set $$\displaystyle V = T $$ to get $$\displaystyle \omega^2 $$.
* **Use**: Approximate natural frequency; exact if assumed shape is exact mode shape.
- Principle of Virtual Work / D'Alembert's Principle: Alternative to Newton's law for deriving EOM. Include inertial forces $-m\ddot{x}$ as "virtual" forces.
Distinction between Viscous and Coulomb Damping (Jun 2025)
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Viscous:
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Force proportional to velocity: $$\displaystyle F_d = c\dot{x} $$.
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Energy dissipated per cycle: $$\displaystyle \pi c \omega X^2 $$ (depends on frequency $\omega$ and amplitude $X$).
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Amplitude decay: Exponential.
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Frequency of damped oscillation: Slightly less than $$\displaystyle \omega_n $$, depends on $\zeta$.
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Coulomb:
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Force constant magnitude, opposes motion: $$\displaystyle F_d = \mu N \cdot \text{sign}(\dot{x}) $$.
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Energy dissipated per half-cycle: $4\mu N X$ (independent of $\omega$, proportional to $X$).
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Amplitude decay: Linear (decreases by constant $$\displaystyle \Delta X = 4\mu N/k $$ per half-cycle).
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Frequency: Approximately $$\displaystyle \omega_n $$, but slightly less and depends on initial amplitude.
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Motion: Non-sinusoidal (sharp corners).
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END OF UNIT 5 SHORT NOTES
Aligned with RGPV past papers (Jun 2025, May 2024, Nov 2023, Nov 2022).