Skip to content
ME-502 · Mechanical Vibrations/Quick Revision Short Notes

Mechanical Vibrations (ME-502) - Unit 5 Short Notes

UNIT 5: MECHANICAL VIBRATIONS


I. FUNDAMENTALS & SINGLE DEGREE OF FREEDOM (SDOF) SYSTEMS

Degrees of Freedom (DOF)

  • Definition: Minimum number of independent coordinates required to define the system's configuration.

  • Types:

    • Translational DOF: Linear motion (e.g., mass on a spring).

    • Rotational DOF: Angular motion (e.g., pendulum, torsional system).

  • Examples:

    • 1-DOF: Simple spring-mass system, simple pendulum.

    • 2-DOF: Two masses connected by springs, vehicle model (heave & pitch).

    • Multi-DOF: Multi-story building, complex machinery.

Equation of Motion (EOM) for SDOF

  • Standard Form:

$$m\ddot{x} + c\dot{x} + kx = F(t)$$

where $m$ = mass, $c$ = damping constant, $k$ = stiffness, $F(t)$ = external force.
  • Derivation via Newton's Second Law (FBD):

    1. Draw Free Body Diagram (FBD) of mass.

    2. Apply $$\displaystyle \sum F = m\ddot{x} $$: $$\displaystyle -k x - c\dot{x} + F(t) = m\ddot{x} $$.

    3. Rearrange to standard form.

  • Derivation via Rayleigh's Energy Method (Frequently asked):

    • Total Energy: $$\displaystyle T + V = \text{constant} $$ (for conservative, undamped systems).

    • Kinetic Energy: $$\displaystyle T = \frac{1}{2}m\dot{x}^2 $$.

    • Potential Energy: $$\displaystyle V = \frac{1}{2}kx^2 $$.

    • Differentiate: $$\displaystyle \frac{d}{dt}(T+V) = 0 \Rightarrow m\dot{x}\ddot{x} + kx\dot{x} = 0 $$.

    • Divide by $\dot{x}$ (assuming $\dot{x} \neq 0$): $$\displaystyle m\ddot{x} + kx = 0 $$.

    [!TIP] Rayleigh's method is energy-based and avoids drawing FBDs. It's valid for conservative systems without non-conservative forces like damping or explicit forcing.

Free Vibration of Undamped SDOF

  • EOM: $$\displaystyle m\ddot{x} + kx = 0 $$.

  • Solution: $$\displaystyle x(t) = A\sin(\omega_n t) + B\cos(\omega_n t) $$.

  • Natural Frequency:

$$\omega_n = \sqrt{\frac{k}{m}} \quad \text{(rad/s)}$$

$$f_n = \frac{\omega_n}{2\pi} \quad \text{(Hz)}$$

  • Natural Frequency of Systems with Multiple Springs:

    • Series: $$\displaystyle \frac{1}{k_{eq}} = \frac{1}{k_1} + \frac{1}{k_2} + \cdots $$

    • Parallel: $$\displaystyle k_{eq} = k_1 + k_2 + \cdots $$

    • Apply $$\displaystyle \omega_n = \sqrt{k_{eq}/m} $$.

Free Vibration of Damped SDOF

  • Viscous Damping:

    • Model: Damping force $$\displaystyle F_d = c\dot{x} $$, proportional to velocity.

    • EOM: $$\displaystyle m\ddot{x} + c\dot{x} + kx = 0 $$.

  • Coulomb (Dry Friction) Damping:

    • Model: Constant magnitude force $$\displaystyle F_d = \mu N \cdot \text{sign}(\dot{x}) $$, opposes motion.

    • Characteristics: Amplitude decreases linearly, frequency slightly less than $$\displaystyle \omega_n $$, motion is non-sinusoidal (saw-tooth).

  • Damping Ratio ($\zeta$):

$$\zeta = \frac{c}{c_c} = \frac{c}{2\sqrt{km}}$$

*   $$\displaystyle \zeta < 1 $$: Underdamped (oscillatory).

*   $$\displaystyle \zeta = 1 $$: Critically damped (fastest return to equilibrium without oscillation).

*   $$\displaystyle \zeta > 1 $$: Overdamped (slow return, no oscillation).
  • Critical Damping Constant ($$\displaystyle c_c $$):

$$c_c = 2\sqrt{km}$$

*   **Importance**: Boundary between oscillatory and non-oscillatory motion. Used as reference for damping ratio.
  • Damped Natural Frequency ($$\displaystyle \omega_d $$): For underdamped ($$\displaystyle \zeta < 1 $$):

$$\omega_d = \omega_n \sqrt{1 - \zeta^2}$$

  • Logarithmic Decrement ($\delta$):

    • Definition: $$\displaystyle \delta = \ln\left(\frac{x(t)}{x(t+T_d)}\right) $$, ratio of successive amplitudes.

    • Relation to $\zeta$:

$$\delta = \frac{2\pi\zeta}{\sqrt{1-\zeta^2}}$$

*   **Limitation**: Formula assumes underdamped motion ($$\displaystyle \zeta < 1 $$). For $\zeta \geq 1$, no oscillations occur, so $\delta$ is undefined.
  • Comparison: Underdamped vs. Coulomb Damped Free Vibration:
Feature Viscous (Underdamped) Coulomb Damped
Amplitude Decay Exponential: $$\displaystyle x \propto e^{-\zeta\omega_n t} $$ Linear: $x$ decreases by constant $$\displaystyle \frac{4\mu N}{k} $$ per half-cycle
Frequency $$\displaystyle \omega_d = \omega_n\sqrt{1-\zeta^2} $$ (slightly less than $$\displaystyle \omega_n $$) $$\displaystyle \omega_d \approx \omega_n \left(1 - \frac{2\mu N}{\pi k A_0}\right) $$ (depends on initial amplitude $$\displaystyle A_0 $$)
Motion Sinusoidal with decaying envelope Non-sinusoidal (sharp corners near turning points)

Forced Vibration of SDOF (Harmonic Force)

  • Forcing Function: $$\displaystyle F(t) = F_0 \sin(\omega t) $$.

  • Steady-State Response: $$\displaystyle x_{ss}(t) = X \sin(\omega t - \phi) $$.

  • Magnification Factor (Dynamic Magnification, $M$):

    • Definition: Ratio of dynamic amplitude to static deflection under $$\displaystyle F_0 $$.

$$M = \frac{X}{X_{st}} = \frac{X}{F_0/k}$$

  • Derivation & Expression:

    Substitute $$\displaystyle x_{ss} = X\sin(\omega t - \phi) $$ into EOM $$\displaystyle m\ddot{x}+c\dot{x}+kx=F_0\sin\omega t $$.

    After algebra:

$$\boxed{M = \frac{1}{\sqrt{(1 - r^2)^2 + (2\zeta r)^2}}}$$

where $$\displaystyle r = \omega / \omega_n $$ (frequency ratio).
  • Resonance:

    • Condition: $r \approx 1$ (for low $\zeta$).

    • Amplitude at Resonance ($$\displaystyle r=1 $$):

$$M_{res} = \frac{1}{2\zeta}$$

*   **Phase at Resonance**: $$\displaystyle \phi = \pi/2 $$.
  • Effect of Damping:

    • Resonance Peak: Decreases as $\zeta$ increases.

    • Bandwidth: Increases as $\zeta$ increases. Bandwidth $\Delta r \approx 2\zeta$ for small $\zeta$.

Special Cases & Applications of SDOF

  • Base Excitation / Vibration Isolation:

    • Setup: Base motion $$\displaystyle y(t) = Y \sin(\omega t) $$.

    • Relative Displacement: $$\displaystyle z = x - y $$.

    • EOM (in terms of $z$): $$\displaystyle m\ddot{z} + c\dot{z} + kz = -m\ddot{y} $$.

    • Transmissibility (Displacement):

$$T_d = \frac{X}{Y} = \frac{r^2}{\sqrt{(1-r^2)^2 + (2\zeta r)^2}}$$

*   **Transmissibility (Force)**: $$\displaystyle T_f = \frac{F_{trans}}{F_0} = \sqrt{1 + (2\zeta r)^2} \cdot T_d $$.

*   **Isolator Design**:

    *   For **isolation** ($$\displaystyle \omega > \omega_n $$), need $$\displaystyle r > \sqrt{2} $$.

    *   **Stiffness** from transmissibility requirement: $$\displaystyle k = m\omega_n^2 $$.

    *   **Maximum Isolator Deformation**: $$\displaystyle \delta_{max} = X_{max} + Y $$ (if base and mass move in phase).
  • Rotating Unbalance:

    • Equivalent Force: $$\displaystyle F_0 = m_e e \omega^2 $$, where $$\displaystyle m_e $$ = eccentric mass, $e$ = eccentricity.

    • Steady-State Amplitude:

$$X = \frac{m_e e \omega^2 / m}{\sqrt{(\omega_n^2 - \omega^2)^2 + (2\zeta\omega_n\omega)^2}} = \frac{m_e e}{m} \cdot \frac{r^2}{\sqrt{(1-r^2)^2+(2\zeta r)^2}}$$

*   **Critical Speed**: Speed at which $$\displaystyle \omega = \omega_n $$ (resonance). Must be avoided in rotating machinery.
  • Vehicle/Trailer Vibration on Sinusoidal Road (Jun 2025):

    • Model: Trailer as SDOF with base excitation from road profile $$\displaystyle y = Y \sin(\frac{2\pi}{\lambda} v t) $$, where $\lambda$ = wavelength, $v$ = speed.

    • Critical Speed: Occurs when forcing frequency $$\displaystyle \omega = \frac{2\pi v}{\lambda} = \omega_n $$.

$$v_{crit} = \frac{\lambda \omega_n}{2\pi}$$

*   **Amplitude at Speed $v$**: Use $$\displaystyle r = \omega/\omega_n $$ in transmissibility formula $$\displaystyle X = T_d Y $$.
  • Recoil Mechanisms (Jun 2025):

    • Model: Critically damped SDOF ($$\displaystyle \zeta=1 $$).

    • EOM: $$\displaystyle m\ddot{x} + c_c\dot{x} + kx = 0 $$, with $$\displaystyle c_c = 2\sqrt{km} $$.

    • Design for Maximum Recoil Distance $$\displaystyle x_{max} $$:

      Given initial recoil velocity $$\displaystyle v_0 $$, initial displacement $$\displaystyle x_0=0 $$.

      For critical damping, solution: $$\displaystyle x(t) = (A + Bt)e^{-\omega_n t} $$.

      Apply ICs: $$\displaystyle x(0)=0 \Rightarrow A=0 $$; $$\displaystyle \dot{x}(0)=v_0 \Rightarrow B=v_0 $$.

      Max displacement occurs at $$\displaystyle t=0 $$? Actually for $$\displaystyle \zeta=1 $$, $$\displaystyle x(t) = v_0 t e^{-\omega_n t} $$. Max at $$\displaystyle t=1/\omega_n $$.

$$x_{max} = \frac{v_0}{e \omega_n} \approx \frac{v_0}{2.718 \omega_n}$$

    Given $$\displaystyle x_{max} $$ and $$\displaystyle v_0 $$, solve for $$\displaystyle \omega_n $$, then $$\displaystyle k = m\omega_n^2 $$.

Total Response of SDOF

  • Principle of Superposition:

$$x(t) = x_h(t) + x_p(t)$$

*   $$\displaystyle x_h(t) $$: **Complementary (Transient) Solution** to homogeneous EOM ($$\displaystyle F(t)=0 $$). Depends on damping.

*   $$\displaystyle x_p(t) $$: **Particular (Steady-State) Solution** to forced EOM. Independent of ICs.
  • Initial Conditions: $$\displaystyle x(0) = x_0 $$, $$\displaystyle \dot{x}(0) = v_0 $$.

  • Complete Solution Forms:

    • Underdamped ($$\displaystyle \zeta<1 $$):

$$x(t) = e^{-\zeta\omega_n t} \left[ C_1 \sin(\omega_d t) + C_2 \cos(\omega_d t) \right] + X\sin(\omega t - \phi)$$

    Determine $$\displaystyle C_1, C_2 $$ from ICs.

*   **Critically Damped** ($$\displaystyle \zeta=1 $$):

$$x(t) = (C_1 + C_2 t) e^{-\omega_n t} + x_p(t)$$

*   **Overdamped** ($$\displaystyle \zeta>1 $$):

$$x(t) = C_1 e^{s_1 t} + C_2 e^{s_2 t} + x_p(t)$$

    where $$\displaystyle s_{1,2} = -\zeta\omega_n \pm \omega_n\sqrt{\zeta^2-1} $$.

II. MULTI DEGREE OF FREEDOM (MDOF) SYSTEMS

Modeling & Equations of Motion

  • Matrix Form:

$$\boxed{[M]\ddot{\mathbf{x}} + [C]\dot{\mathbf{x}} + [K]\mathbf{x} = \mathbf{F}(t)}$$

where $[M]$, $[C]$, $[K]$ are mass, damping, stiffness matrices; $\mathbf{x}$ is displacement vector.
  • Writing EOM: Use Newton's method or D'Alembert's principle. Draw FBD for each mass, write $$\displaystyle \sum F = m_i\ddot{x}_i $$, include internal forces from springs/dampers.

Free Vibration Analysis (Undamped)

  • Assumption: Harmonic motion $$\displaystyle \mathbf{x}(t) = \boldsymbol{\phi} \sin(\omega t + \phi) $$.

  • Eigenvalue Problem:

    Substitute into undamped EOM $$\displaystyle [M]\ddot{\mathbf{x}} + [K]\mathbf{x} = \mathbf{0} $$:

$$\left([K] - \omega^2 [M]\right) \boldsymbol{\phi} = \mathbf{0}$$

  • Natural Frequencies ($$\displaystyle \omega_i $$):

    • Roots of characteristic equation: $$\displaystyle \det([K] - \omega^2 [M]) = 0 $$.

    • For $n$-DOF system, $n$ eigenvalues $$\displaystyle \omega_1^2, \omega_2^2, \dots, \omega_n^2 $$ (ordered $$\displaystyle \omega_1 < \omega_2 < \dots $$).

  • Normal Modes / Mode Shapes ($$\displaystyle \boldsymbol{\phi}_i $$):

    • Definition: Deflected shape at which all points move sinusoidally at frequency $$\displaystyle \omega_i $$.

    • Amplitude Ratio: For a given mode $i$, ratio $$\displaystyle \phi_{j,i} / \phi_{k,i} $$ is constant (relative amplitudes of coordinates $j,k$).

    • Orthogonality Properties:

$$\boldsymbol{\phi}_i^T [M] \boldsymbol{\phi}_j = 0 \quad (i \neq j)$$

$$\boldsymbol{\phi}_i^T [K] \boldsymbol{\phi}_j = 0 \quad (i \neq j)$$

    Modes are orthogonal with respect to mass and stiffness matrices.
  • Modal Analysis Procedure:

    1. Form $[M]$, $[K]$.

    2. Solve $$\displaystyle \det([K] - \omega^2 [M]) = 0 $$ for $$\displaystyle \omega_i^2 $$.

    3. For each $$\displaystyle \omega_i $$, solve $$\displaystyle ([K] - \omega_i^2[M])\boldsymbol{\phi}_i = \mathbf{0} $$ for $$\displaystyle \boldsymbol{\phi}_i $$ (up to scale factor).

    4. Normalize mode shapes (e.g., $$\displaystyle \boldsymbol{\phi}_i^T[M]\boldsymbol{\phi}_i = 1 $$).

  • Example Systems: Two-mass, three-mass spring-damper systems. Use matrix formulation.

Principal Coordinates

  • Concept: Transform physical coordinates $\mathbf{x}$ to principal coordinates $\mathbf{q}$ such that EOMs decouple.

$$\mathbf{x} = [\Phi] \mathbf{q}$$

where $$\displaystyle [\Phi] = [\boldsymbol{\phi}_1, \boldsymbol{\phi}_2, \dots, \boldsymbol{\phi}_n] $$ is the modal matrix.
  • Decoupling: Pre-multiply by $$\displaystyle [\Phi]^T $$:

$$[\Phi]^T[M][\Phi]\ddot{\mathbf{q}} + [\Phi]^T[K][\Phi]\mathbf{q} = [\Phi]^T\mathbf{F}(t)$$

Due to orthogonality, $$\displaystyle [\Phi]^T[M][\Phi] $$ and $$\displaystyle [\Phi]^T[K][\Phi] $$ are diagonal matrices.

Result: $n$ independent SDOF equations:

$$m_i^* \ddot{q}_i + k_i^* q_i = f_i(t)$$

where $$\displaystyle m_i^* = \boldsymbol{\phi}_i^T[M]\boldsymbol{\phi}_i $$, $$\displaystyle k_i^* = \boldsymbol{\phi}_i^T[K]\boldsymbol{\phi}_i = \omega_i^2 m_i^* $$.
  • Determination: For a given spring-mass system, find $$\displaystyle \omega_i $$, $$\displaystyle \boldsymbol{\phi}_i $$ as above. Then $$\displaystyle \mathbf{q} = [\Phi]^{-1}\mathbf{x} $$. Since $[\Phi]$ is not necessarily orthogonal (only mass-orthogonal), use $$\displaystyle [\Phi]^T[M][\Phi] = [I] $$ if mass-normalized.

Torsional Systems

  • Modeling: Replace linear springs with torsional springs ($$\displaystyle k_t $$ in N·m/rad), masses with rotary inertias ($J$ in kg·m²).

  • EOM: $$\displaystyle J_i \ddot{\theta}_i + \sum k_t(\theta_i - \theta_j) = T_i(t) $$.

  • Natural Frequencies: Solve $$\displaystyle \det([K_t] - \omega^2 [J]) = 0 $$, where $$\displaystyle [K_t] $$ is torsional stiffness matrix, $[J]$ is diagonal inertia matrix.

  • Given Relationships: If $$\displaystyle k_0=2k_1 $$, $$\displaystyle J_2=2J_1 $$, substitute into matrices before solving eigenvalue problem.


III. SPECIAL SYSTEMS & APPLICATIONS

Continuous Systems (Approximate Methods)

  • Beams in Bending:

    • Natural Frequency of a beam with concentrated mass $m$ at a point:

      Use Rayleigh's method: Assume mode shape (e.g., static deflection curve under $m$). Then:

$$\omega_n^2 = \frac{k_{eq}}{m} = \frac{\text{Strain Energy}}{\text{Max Kinetic Energy}} = \frac{\int_0^L EI (y'')^2 dx}{m \cdot (\text{max deflection})^2}$$

    For a simply supported beam with mass at midspan, $$\displaystyle y(x) = \frac{m g}{2EI} \left( \frac{L}{2}x - x^2 \right) $$ for $0 \le x \le L/2$.

*   **Parameters**: $E$ = Young's modulus, $I$ = area moment of inertia, $l$ = length.
  • Shaft Whirling:

    • Critical Speed of Rotating Shaft: Rotational speed at which shaft deflection becomes very large (resonance).

    • Proof that Critical Whirling Speed = Natural Transverse Frequency:

      The equation for lateral vibration of a shaft with rotating disc is identical to that of a stationary beam with a concentrated mass, except the force is centrifugal $$\displaystyle m e \omega^2 $$. The critical condition occurs when forcing frequency $\omega$ equals the natural frequency $$\displaystyle \omega_n $$ of the shaft-disc system. Thus, critical whirling speed $$\displaystyle \omega_{crit} = \omega_n $$.

    • Safety Check (Nov 2022 - cantilever shaft):

      Given: shaft length $L$, rotor mass $m$, radius of gyration $k$, shaft $I$, $E$.

      1. Calculate $$\displaystyle \omega_n = \sqrt{\frac{EI}{m L^3}} $$ for cantilever with tip mass (approximate).

      2. Convert operating speed (rpm) to rad/s: $$\displaystyle \omega_{op} = \frac{2\pi N}{60} $$.

      3. Safe if $$\displaystyle \omega_{op} < 0.7 \omega_n $$ (typical margin). Or check if $$\displaystyle \omega_{op} \neq \omega_n $$.

    • Gyroscopic Effects: Briefly, for high-speed rotors, gyroscopic moments couple bending modes, splitting critical speeds.

Vibration Measurement & Instruments

  • Vibrometer / Seismometer:

    • Principle: Measures displacement. Natural frequency $$\displaystyle \omega_n $$ is very low ($\ll$ frequency of vibration). Mass is relatively large, spring very soft.

    • Frequency Response: For $$\displaystyle \omega \ll \omega_n $$, $$\displaystyle X_{mass} \approx Y $$ (base displacement). Output proportional to relative displacement $x - y \approx -y$.

  • Accelerometer:

    • Principle: Measures acceleration. Natural frequency $$\displaystyle \omega_n $$ is very high ($\gg$ frequency of vibration). Spring is very stiff, mass small.

    • Frequency Response: For $$\displaystyle \omega \gg \omega_n $$, $$\displaystyle m\ddot{x} \approx F(t) = -m\ddot{y} $$. So $\ddot{x} \approx \ddot{y}$. Output proportional to relative force $c\dot{z} \approx m\ddot{y}$.

  • Derivation (General):

    Relative displacement $$\displaystyle z = x - y $$.

    EOM: $$\displaystyle m\ddot{z} + c\dot{z} + kz = -m\ddot{y} $$.

    Steady-state: $$\displaystyle Z = \frac{m\omega^2 Y}{\sqrt{(k - m\omega^2)^2 + (c\omega)^2}} $$.

    • Seismometer ($$\displaystyle \omega \ll \omega_n $$): $Z \approx Y$ → $x \approx 0$, $z \approx -y$.

    • Accelerometer ($$\displaystyle \omega \gg \omega_n $$): $$\displaystyle Z \approx \frac{m}{k}\omega^2 Y $$ → $\ddot{z} \approx \ddot{y}$.

Dynamic Vibration Absorber (Tuned Mass Damper - TMD)

  • Concept: Attach a secondary mass-spring-damper ($$\displaystyle m_a, k_a, c_a $$) to primary system to reduce vibration at specific frequency $\omega$.

  • Principle: Tune $$\displaystyle k_a $$ so that $$\displaystyle \omega_{na} = \omega $$ (the disturbing frequency). The absorber creates a force that cancels the force on the primary mass.

  • Force Transmissibility Optimization (May 2024 - air compressor):

    • For primary system $m,k$ with unbalance force $$\displaystyle F_0 \sin\omega t $$.

    • With absorber, transmitted force to foundation is:

$$F_{trans} = F_0 \cdot \frac{r^2 \left[ (1 - r_a^2)^2 + (2\zeta_a r_a)^2 \right]}{\left[ (1 - r^2)(1 - r_a^2) - r^2 r_a^2 \right]^2 + \left[ 2\zeta_a r_a (1 - r^2) - 2\zeta r r_a^2 \right]^2}$$

    where $$\displaystyle r = \omega/\omega_n $$, $$\displaystyle r_a = \omega_a/\omega_n $$.

*   **Design for Minimum Transmission**: Set $$\displaystyle r_a = 1 $$ (tune to $\omega$). Then optimize $$\displaystyle \zeta_a $$ for minimum $$\displaystyle F_{trans} $$ at $$\displaystyle r=1 $$:

$$\zeta_{a,opt} = \sqrt{\frac{3}{8} \frac{m}{m_a}}$$

*   **Result**: At $$\displaystyle r=1 $$, $$\displaystyle F_{trans} = F_0 \cdot \frac{2\zeta_a}{\zeta_{a,opt}} $$? Actually, with optimal tuning, transmission can be made very small if $$\displaystyle m_a $$ is significant fraction of $m$.

*   **For Given % Transmission**: Rearrange formula to find required $$\displaystyle m_a/m $$ and $$\displaystyle \zeta_a $$.

IV. DAMPING MECHANISMS & MATERIALS

Types of Damping

  • Viscous Damping:

    • Force: $$\displaystyle F_d = c\dot{x} $$.

    • Energy dissipated per cycle: $$\displaystyle E_D = \int_0^T c\dot{x}^2 dt = \pi c \omega X^2 $$ (for harmonic $$\displaystyle x=X\sin\omega t $$).

  • Coulomb (Dry Friction) Damping:

    • Force: $$\displaystyle F_d = \mu N \cdot \text{sign}(\dot{x}) $$.

    • Energy dissipated per half-cycle: $$\displaystyle E_D = 4\mu N A $$ (constant, independent of frequency).

  • Hysteresis / Solid Damping / Structural Damping:

    • Concept: Energy loss due to internal friction in material during cyclic loading. Stress-strain curve forms a hysteresis loop.

    • Area under Hysteresis Curve: Represents energy dissipated per unit volume per cycle.

    • Complex Stiffness Representation: Damping force in phase with velocity but modeled as imaginary stiffness:

$$F_d = i k^* x \quad \text{or} \quad k_{complex} = k(1 + i\eta)$$

    where $\eta$ = loss factor (damping ratio for structural damping: $$\displaystyle \zeta = \eta/2 $$ for small $\eta$).

Equivalent Damping

  • Concept: Express energy dissipation of non-viscous damper in terms of an equivalent viscous damping constant $$\displaystyle c_{eq} $$ that dissipates same energy per cycle.

$$\int_0^T c_{eq} \dot{x}^2 dt = E_{D,actual}$$

For harmonic $$\displaystyle x = X\sin\omega t $$, LHS = $$\displaystyle \pi c_{eq} \omega X^2 $$.

*   **For Coulomb Damping**: $$\displaystyle E_D = 4\mu N A \approx 8\mu N X $$ (since $A \approx X$). So:

$$c_{eq} = \frac{4\mu N}{\pi \omega X} \quad \text{(amplitude-dependent!)}$$

*   **For Structural Damping**: $$\displaystyle E_D = \pi \eta k X^2 $$. So:

$$c_{eq} = \frac{\eta k}{\omega}$$


V. VIBRATION ISOLATION & CONTROL

  • Isolation vs. Absorption:

    • Isolation: Prevent vibration from source to foundation (use isolators under machine).

    • Absorption: Add TMD to reduce vibration of structure.

  • Design of Vibration Isolators:

    1. Determine Requirements: Limit transmitted acceleration/force or displacement.

    2. Calculate $$\displaystyle \omega_n $$: From transmissibility formula. For isolation ($$\displaystyle r > \sqrt{2} $$), $$\displaystyle T_d \approx 1/r^2 $$ for high $r$.

    3. Select Stiffness $k$: $$\displaystyle k = m \omega_n^2 $$.

    4. Check Damping: Low $\zeta$ (0.05–0.1) gives better isolation at high $r$, but higher $\zeta$ reduces resonance peak. Trade-off.

  • Isolator Stiffness for Acceleration Limit (May 2024 - flow monitor):

    • Given: base acceleration amplitude $$\displaystyle Y\omega^2 $$, max allowed mass acceleration $$\displaystyle a_{max} $$.

    • Transmitted acceleration amplitude $$\displaystyle A = \omega^2 X $$.

    • From transmissibility: $$\displaystyle X = T_d Y $$, so $$\displaystyle A = \omega^2 T_d Y $$.

    • Set $$\displaystyle A \le a_{max} $$ → solve for $r$, then $k$.

    • Example: $$\displaystyle a_{max} = 5g $$, $$\displaystyle Y\omega^2 = ? $$ Given $Y$ and $\omega$, compute $r$ from $$\displaystyle T_d = A/(\omega^2 Y) $$, then $$\displaystyle k = m \omega_n^2 = m (\omega/r)^2 $$.

  • Maximum Displacement of Isolated System:

    $$\displaystyle X_{max} = T_d Y_{max} $$.

  • Maximum Isolator Deformation:

    $$\displaystyle \delta_{max} = |x - y|_{max} = |X - Y| $$ if in phase, or $X + Y$ if out of phase. Generally, $$\displaystyle \delta_{max} \approx X_{max} + Y_{max} $$ (worst case).


VI. NOISE & VIBRATION – ACOUSTICS (Frequently Tested)

Sound Fundamentals

  • Sound Pressure Level (SPL):

    • Definition: Logarithmic measure of RMS sound pressure $p$ relative to reference pressure $$\displaystyle p_{ref} = 20 \ \mu\text{Pa} $$ (threshold of hearing).

$$\boxed{SPL \ (\text{dB}) = 20 \log_{10}\left(\frac{p}{p_{ref}}\right)}$$

*   **0 dB SPL**: Means $$\displaystyle p = p_{ref} $$ (threshold of hearing), **not** zero sound pressure. It is a reference level.
  • Sound Power Level (SWL):

    • Definition: Logarithmic measure of acoustic power $W$ radiated by source relative to reference power $$\displaystyle W_{ref} = 10^{-12} \ \text{W} $$.

$$SWL \ (\text{dB}) = 10 \log_{10}\left(\frac{W}{W_{ref}}\right)$$

*   **Relationship with SPL**: For a point source in free field, SPL decreases with distance $r$: $$\displaystyle SPL = SWL - 20\log_{10}(r) - 11 \ \text{dB} $$ (for $r$ in meters). SPL is **pressure-based**, SWL is **power-based** (source strength).

Sound Analysis

  • Octave Band Analysis:

    • Purpose: Break down complex noise into frequency bands to identify dominant frequencies and assess human ear response (which is logarithmic).

    • Concept: Each band has upper frequency = 2 × lower frequency. Center frequency $$\displaystyle f_c $$ is geometric mean: $$\displaystyle f_c = \sqrt{f_1 f_2} $$.

      • Example: 31.5 Hz band: 22.4–45 Hz (center 31.5).
    • Use: Noise control (target dominant bands), compliance with standards (e.g., OSHA limits in octave bands), hearing protector selection.

Human Response & Conservation

  • Response of Human to Noise:

    • Physiological: Hearing damage (temporary/permanent threshold shift), stress, hypertension.

    • Psychological: Annoyance, reduced concentration, sleep disturbance.

    • Frequency Sensitivity: Human ear most sensitive 2–5 kHz (speech frequencies).

  • Hearing Conservation & Damage Risk Criteria:

    • Permissible Exposure Limits (PEL): Time-weighted average (TWA) noise exposure allowed.

      • OSHA: 90 dBA for 8 hours (5 dB exchange rate: 90 dBA/8h, 95 dBA/4h, 100 dBA/2h, etc.).

      • NIOSH: 85 dBA for 8 hours (3 dB exchange rate: more protective).

    • Precautions and Remedies (Nov 2023):

      1. Engineering Controls: Enclose noisy machines, use quieter processes, vibration isolation, mufflers.

      2. Administrative Controls: Rotate workers, limit exposure time, regular maintenance.

      3. Personal Protective Equipment (PPE): Earplugs, earmuffs (check Noise Reduction Rating - NRR).

      4. Hearing Protection Program: Audiometric testing, training, monitoring.

Sound Intensity & Pressure Calculations

  • Change in SPL with Distance (Inverse Square Law for point source in free field):

$$\Delta SPL = 20 \log_{10}\left(\frac{r_2}{r_1}\right)$$

*   **Doubling Distance**: $$\displaystyle r_2 = 2r_1 $$ → $$\displaystyle \Delta SPL = 20 \log_{10}(2) \approx 6 \ \text{dB} $$ decrease.
  • Conversion between SPL (dB) and Actual Pressure (May 2024):

    Given $$\displaystyle SPL = 11.23 \ \text{dB} $$, $$\displaystyle p_{ref}=20 \ \mu\text{Pa} $$.

$$p = p_{ref} \times 10^{SPL/20} = 20 \times 10^{-6} \times 10^{11.23/20}$$

$$10^{11.23/20} = 10^{0.5615} \approx 3.64$$

$$p \approx 20 \times 10^{-6} \times 3.64 = 72.8 \ \mu\text{Pa}$$

> [!TIP] Remember: 0 dB = $$\displaystyle p_{ref} $$, 20 dB = $$\displaystyle 10 p_{ref} $$, 40 dB = $$\displaystyle 100 p_{ref} $$, etc. (20 dB per factor 10 in pressure).

VII. MISCELLANEOUS & DEFINITIONS (Short Note Topics)

Work Done by Harmonic Force (Nov 2023)

  • Force: $$\displaystyle F(t) = F_0 \sin \omega t $$.

  • Displacement: $$\displaystyle x(t) = x_0 \sin(\omega t - \phi) $$.

  • Work over time $$\displaystyle t_1 $$ to $$\displaystyle t_2 $$:

$$W = \int_{t_1}^{t_2} F \dot{x} \ dt$$

  • First Cycle ($$\displaystyle t_1=0, t_2=T=2\pi/\omega $$):

$$W_{cycle} = \frac{\pi F_0 x_0}{2} \cos\phi$$

*   If $$\displaystyle \phi=0 $$ (in phase), $$\displaystyle W_{max} = \frac{\pi F_0 x_0}{2} $$.

*   If $$\displaystyle \phi=\pi/2 $$ (90° lag), $$\displaystyle W=0 $$ (no net work, energy stored/returned).
  • First Second: Plug limits $$\displaystyle t_1=0, t_2=1 $$ into integral. May not be integer cycles.

  • First Quarter Second: $$\displaystyle t_1=0, t_2=0.25 $$ s. Compute definite integral numerically or analytically if $\omega$ known.

Fourier Series Expansion of Non-Periodic/Impact Forces (Jun 2025)

  • Concept: Represent aperiodic force $F(t)$ (e.g., impact) as sum of sinusoidal components over a finite interval $[0, T]$, where $T$ is the "period" of the repeated pulse.

  • Fourier Series:

$$F(t) = a_0 + \sum_{n=1}^{\infty} \left[ a_n \cos(n\omega_0 t) + b_n \sin(n\omega_0 t) \right]$$

where $$\displaystyle \omega_0 = 2\pi/T $$.

Coefficients:

$$a_0 = \frac{1}{T} \int_0^T F(t) dt$$

$$a_n = \frac{2}{T} \int_0^T F(t) \cos(n\omega_0 t) dt$$

$$b_n = \frac{2}{T} \int_0^T F(t) \sin(n\omega_0 t) dt$$

  • Application: For forging hammer impact (rectangular pulse of force $$\displaystyle F_0 $$ duration $\tau$), compute integrals over $[0,T]$.

Node in Vibration (May 2024)

  • Definition: A point or line in a vibrating structure that remains stationary (zero displacement amplitude) during a particular mode of vibration.

  • Sketch: For a simply supported beam, first mode has one node at center? Actually, simply supported has no internal nodes for first mode. Fixed-fixed beam first mode has two nodes (points of zero displacement) between ends.

    DiagramCANVAS: Sketch of a fixed-fixed beam in first bending mode, showing endpoints fixed, maximum deflection at center, and two nodes (points of zero deflection) symmetrically located between center and ends.

  • Significance: Nodes indicate where structure does not move; useful for placing supports or isolators without affecting mode shape.

Whirling of Shafts (May 2024, Nov 2022)

  • Explanation: Whirling is the precession (rotating bending deflection) of a shaft rotating at high speed. The shaft centerline describes a circle.

  • Cause: Unbalance, gyroscopic moments, or external forces. At critical whirling speed, the rotational speed matches a natural bending frequency of the shaft-disc system, causing large amplitudes.

  • Critical Speed: $$\displaystyle \omega_{crit} = \omega_n $$ (natural transverse frequency). Must operate below ~0.7 $$\displaystyle \omega_{crit} $$ for safety.

Energy Method in Vibration Analysis (Nov 2023)

  • Rayleigh's Method:

    • Principle: For conservative system, max potential energy = max kinetic energy.

$$\frac{1}{2} k_{eq} (\text{max deflection})^2 = \frac{1}{2} m (\text{max velocity})^2$$

For assumed mode shape $y(x)$, compute strain energy $$\displaystyle V = \int \frac{1}{2} EI (y'')^2 dx $$ and kinetic energy $$\displaystyle T = \frac{1}{2} \omega^2 \int \rho A y^2 dx $$ (or with concentrated masses). Set $$\displaystyle V = T $$ to get $$\displaystyle \omega^2 $$.

*   **Use**: Approximate natural frequency; exact if assumed shape is exact mode shape.
  • Principle of Virtual Work / D'Alembert's Principle: Alternative to Newton's law for deriving EOM. Include inertial forces $-m\ddot{x}$ as "virtual" forces.

Distinction between Viscous and Coulomb Damping (Jun 2025)

  • Viscous:

    • Force proportional to velocity: $$\displaystyle F_d = c\dot{x} $$.

    • Energy dissipated per cycle: $$\displaystyle \pi c \omega X^2 $$ (depends on frequency $\omega$ and amplitude $X$).

    • Amplitude decay: Exponential.

    • Frequency of damped oscillation: Slightly less than $$\displaystyle \omega_n $$, depends on $\zeta$.

  • Coulomb:

    • Force constant magnitude, opposes motion: $$\displaystyle F_d = \mu N \cdot \text{sign}(\dot{x}) $$.

    • Energy dissipated per half-cycle: $4\mu N X$ (independent of $\omega$, proportional to $X$).

    • Amplitude decay: Linear (decreases by constant $$\displaystyle \Delta X = 4\mu N/k $$ per half-cycle).

    • Frequency: Approximately $$\displaystyle \omega_n $$, but slightly less and depends on initial amplitude.

    • Motion: Non-sinusoidal (sharp corners).


END OF UNIT 5 SHORT NOTES
Aligned with RGPV past papers (Jun 2025, May 2024, Nov 2023, Nov 2022).

Go to where you left off?

Quick Add to Notes

Save questions, your own notes and screenshots into notes filed by unit. It takes a free account.

Create free account

Have an account? Log in