UNIT 3: Comprehensive Study Notes (Based on RGPV Past Papers)
1. Fundamental Properties & Stress-Strain Relationships
Elastic Moduli:
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Young's Modulus (E): Ratio of normal stress to normal strain within elastic limit. $$\displaystyle E = \frac{\sigma}{\epsilon} $$.
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Shear Modulus (G) / Modulus of Rigidity: Ratio of shear stress to shear strain. $$\displaystyle G = \frac{\tau}{\gamma} $$.
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Bulk Modulus (K): Ratio of hydrostatic pressure to volumetric strain. $$\displaystyle K = -\frac{p}{\epsilon_v} $$.
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Relationship: $$\displaystyle G = \frac{E}{2(1+\nu)} $$ and $$\displaystyle K = \frac{E}{3(1-2\nu)} $$, where $\nu$ is Poisson's ratio.
Poisson's Ratio ($\nu$):
Definition: Ratio of lateral strain to longitudinal strain in the elastic region. For most metals, $$\displaystyle 0.25 < \nu < 0.35 $$.
Stress-Strain Curve Key Points:
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Proportional Limit: Stress is proportional to strain (Hooke's law valid).
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Elastic Limit: Maximum stress without permanent deformation.
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Yield Point: Stress at which material begins to deform plastically.
Strain Energy:
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Strain Energy (U): Work done by external load in straining a material.
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Strain Energy Density (u): Strain energy per unit volume.
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Gradual Loading: $$\displaystyle U = \frac{P^2 L}{2EA} $$ or $$\displaystyle U = \frac{1}{2} P \delta $$.
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Impact/Shock Loading: $$\displaystyle U = P(\delta_{st} + \delta_i) $$, where $$\displaystyle \delta_i = \delta_{st}\left(1 + \sqrt{1 + \frac{2h}{\delta_{st}}}\right) $$ for a falling weight.
Hooke's Law in 3D: For isotropic materials, generalized Hooke's law relates all six stress and strain components.
2. Axial Loading & Deformation
Uniform Bar:
$$\boxed{\delta = \frac{PL}{EA}}$$
Composite Bars (Different Materials in Series):
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Compatibility: Deformation of each segment is equal ($$\displaystyle \delta_1 = \delta_2 = ... $$).
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Equilibrium: Total load $$\displaystyle P = \sum P_i $$.
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Stress Calculation: Use $$\displaystyle \sigma_i = E_i \epsilon $$ and $$\displaystyle \sum \frac{P_i}{A_i E_i} = \frac{P}{E_{eq} A_{eq}} $$ approach.
Thermal Stresses in Composite Systems:
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Free Expansion: $$\displaystyle \delta_{th} = \alpha L \Delta T $$.
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Restrained Expansion: Stress develops. For a composite bar fixed at both ends:
$$\sum P_i = 0 \quad \text{and} \quad \frac{P_1 L}{A_1 E_1} + \alpha_1 \Delta T L = \frac{P_2 L}{A_2 E_2} + \alpha_2 \Delta T L$$
Solve for $$\displaystyle P_1, P_2 $$, then $$\displaystyle \sigma_1 = P_1/A_1 $$, $$\displaystyle \sigma_2 = P_2/A_2 $$.
Axially Varying Cross-Section (Tapered Bar - Circular):
For a bar tapering from diameter $D$ at $$\displaystyle x=0 $$ to $d$ at $$\displaystyle x=L $$:
$$d(x) = D - \left(\frac{D-d}{L}\right)x, \quad A(x) = \frac{\pi}{4} [d(x)]^2$$
$$\delta = \int_0^L \frac{P}{E A(x)} dx = \frac{4P}{\pi E (D-d)} \ln\left(\frac{D}{d}\right)$$
Statically Indeterminate Axial Problems:
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Use compatibility (deformation) conditions along with equilibrium.
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Example: Rigid plate with multiple bars → all bars have same deformation.
[!TIP] Common Pitfall: In composite bars, stresses are NOT equal; deformations are equal. Always write compatibility first.
3. Bending Stresses & Beam Deflection
Shear Force (V) & Bending Moment (M) Diagrams:
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Sign Convention: Sagging (+ve) BM, upward left of section (+ve) SF.
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Relationship: $$\displaystyle \frac{dM}{dx} = V $$, $$\displaystyle \frac{dV}{dx} = -w $$.
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Point of Contraflexure: Point where BM changes sign ($$\displaystyle M=0 $$).
Theory of Simple Bending:
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Assumptions:
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Material is homogeneous, isotropic.
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Beam is initially straight.
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Plane sections remain plane and perpendicular to neutral axis.
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Stress is proportional to strain (Hooke's law).
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Modulus of elasticity same in tension/compression.
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Flexure Formula:
$$\boxed{\sigma = \frac{My}{I}} \quad \text{or} \quad \boxed{\sigma_{max} = \frac{M}{Z}} \quad \text{where} \quad Z = \frac{I}{y_{max}}$$
Deflection of Beams - Methods:
| Method | Key Idea | Best For | Advantage |
|---|---|---|---|
| Double Integration | $$\displaystyle \frac{d^2y}{dx^2} = \frac{M}{EI} $$ | Simple loads, clear BCs | Direct, fundamental |
| Macaulay's Method | Uses step functions in M(x) | Point loads, multiple loads | Single expression for M(x) for whole beam |
| Area-Moment Method | Theorems: $$\displaystyle \theta_{AB} = \frac{1}{EI} \times (\text{Area of M diagram})_{AB} $$, $$\displaystyle y_B = \frac{1}{EI} \times (\text{Moment of area})_{AB} $$ | Cantilevers, SS beams, specific points | No integration needed for standard cases |
| Conjugate Beam | Replace real beam with "conjugate" where load = M/EI | Complex BCs | Converts deflection to shear/rotation in conjugate |
Standard Deflection Formulas (EI constant):
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Cantilever (Point load W at free end): $$\displaystyle y_{max} = \frac{WL^3}{3EI} $$ at free end, $$\displaystyle \theta_{free} = \frac{WL^2}{2EI} $$.
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Cantilever (UDL w over entire span): $$\displaystyle y_{max} = \frac{wL^4}{8EI} $$, $$\displaystyle \theta_{free} = \frac{wL^3}{6EI} $$.
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Simply Supported (Central point load W): $$\displaystyle y_{max} = \frac{WL^3}{48EI} $$ at center.
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Simply Supported (UDL w over entire span): $$\displaystyle y_{max} = \frac{5wL^4}{384EI} $$ at center.
[!TIP] Scaling Laws: For similar beams (same shape, different size L, h, b), deflection scales as $$\displaystyle y \propto \frac{L^3}{h} $$ if load is force per unit length, or $$\displaystyle y \propto \frac{L^4}{h^3} $$ if load is total force.
4. Shear Stresses in Beams
Shear Formula:
$$\boxed{\tau = \frac{VQ}{It}}$$
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$V$ = Shear force at section.
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$Q$ = First moment of area above/below the point about NA: $$\displaystyle Q = \bar{y} A' $$.
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$I$ = Second moment of area about NA.
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$t$ = Thickness of material at the point.
Distribution:
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Rectangular Section: Parabolic. $$\displaystyle \tau_{max} = \frac{3}{2} \tau_{avg} $$ at NA ($$\displaystyle y=0 $$). $$\displaystyle \tau=0 $$ at top/bottom.
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Circular Section: $$\displaystyle \tau = \frac{4V}{3A} \sqrt{1 - \left(\frac{2y}{d}\right)^2} $$. Max at NA.
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I-Section: Shear carried almost entirely by web. $$\displaystyle \tau_{web} \approx \frac{V}{A_{web}} $$. $$\displaystyle \tau_{flange} $$ is small.
Maximum Shear Stress: Occurs at the neutral axis for symmetric sections (rectangular, circular, I-section).
[!TIP] Key Insight: For thin-walled sections (I-beam), assume uniform shear stress across the web thickness.
5. Torsion
Circular Shafts (Solid & Hollow):
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Shear Stress:
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Solid: $$\displaystyle \tau = \frac{Tr}{J} $$, max at outer surface ($$\displaystyle r = R $$).
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Hollow: $$\displaystyle \tau_{max} = \frac{T r_o}{J} $$, $$\displaystyle \tau_{min} = \frac{T r_i}{J} $$.
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$$\boxed{J = \frac{\pi}{2} (r_o^4 - r_i^4)}$$
- Angle of Twist:
$$\boxed{\theta = \frac{TL}{GJ}} \quad (\text{in radians})$$
Power Transmission:
$$\boxed{P = \frac{2\pi N T}{60}} \quad \text{(Watts)}$$
where $N$ = rpm, $T$ = torque (N·m).
Solid vs. Hollow Shaft Comparison:
- Same Maximum Stress: Hollow shaft transmits more torque for same weight/material.
$$\frac{T_h}{T_s} = \frac{1 - \left(\frac{r_i}{r_o}\right)^4}{1 - \left(\frac{r_i}{r_o}\right)^2} \left(\frac{r_o}{r_o}\right)^2 \approx \left(1 - \left(\frac{r_i}{r_o}\right)^2\right)^{-1}$$
- Same Weight: $$\displaystyle T_h / T_s = (r_o/r_i)^2 $$ for thin-walled approximation.
Stepped Shafts:
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Compatibility: Total angle of twist $$\displaystyle \theta_{total} = \sum \frac{T_i L_i}{G_i J_i} $$.
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Given rotations at points (e.g., $$\displaystyle \phi_A, \phi_C, \phi_D $$), set up equations based on relative twists between sections to solve for internal torques $$\displaystyle T_i $$.
Combined Bending & Torsion:
- Principal Stresses:
$$\sigma_1, \sigma_2 = \frac{\sigma_b}{2} \pm \sqrt{\left(\frac{\sigma_b}{2}\right)^2 + \tau_t^2}$$
where $$\displaystyle \sigma_b $$ = bending stress (tensile +ve), $$\displaystyle \tau_t $$ = torsional shear.
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Equivalent Tensile Stress (for design):
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Max Shear Theory: $$\displaystyle \sigma_{eq} = \sqrt{\sigma_b^2 + 4\tau_t^2} $$.
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Von Mises: $$\displaystyle \sigma_{eq} = \sqrt{\sigma_b^2 + 3\tau_t^2} $$.
Design for $$\displaystyle \sigma_{eq} \leq \frac{\sigma_y}{n} $$.
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6. Stress Transformation & Mohr’s Circle
2D Stress Transformation (Plane at $\theta$):
$$\boxed{\sigma_n = \frac{\sigma_x + \sigma_y}{2} + \frac{\sigma_x - \sigma_y}{2} \cos 2\theta + \tau_{xy} \sin 2\theta}$$
$$\boxed{\tau_{nt} = -\frac{\sigma_x - \sigma_y}{2} \sin 2\theta + \tau_{xy} \cos 2\theta}$$
Principal Stresses & Planes:
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Principal Planes: Planes where $$\displaystyle \tau_{nt} = 0 $$.
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Principal Stresses:
$$\boxed{\sigma_{1,2} = \frac{\sigma_x + \sigma_y}{2} \pm \sqrt{\left(\frac{\sigma_x - \sigma_y}{2}\right)^2 + \tau_{xy}^2}}$$
- Orientation: $$\displaystyle \tan 2\theta_p = \frac{2\tau_{xy}}{\sigma_x - \sigma_y} $$.
Maximum Shear Stress:
$$\boxed{\tau_{max} = \sqrt{\left(\frac{\sigma_x - \sigma_y}{2}\right)^2 + \tau_{xy}^2}}$$
Occurs on planes at $$\displaystyle 45^\circ $$ to principal planes.
Mohr’s Circle:
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Construction:
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Plot $$\displaystyle X(\sigma_x, \tau_{xy}) $$ and $$\displaystyle Y(\sigma_y, -\tau_{xy}) $$.
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Center $$\displaystyle C = \left(\frac{\sigma_x+\sigma_y}{2}, 0\right) $$.
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Radius $$\displaystyle R = \sqrt{\left(\frac{\sigma_x-\sigma_y}{2}\right)^2 + \tau_{xy}^2} $$.
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Utility: Graphical determination of $$\displaystyle \sigma_n, \tau $$ on any plane, $$\displaystyle \sigma_{1,2} $$, $$\displaystyle \tau_{max} $$, and their orientations.
Obliquity of Resultant Stress ($\beta$):
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Angle between resultant stress $$\displaystyle \sigma_r $$ and normal to the plane.
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$$\displaystyle \tan \beta = \frac{\tau_{nt}}{\sigma_n} $$.
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Maximum Obliquity: Occurs when $$\displaystyle \frac{d}{d\theta}(\tan \beta) = 0 $$. $$\displaystyle \beta_{max} = \sin^{-1}\left(\frac{\tau_{max}}{\sigma_{avg} + \tau_{max}}\right) $$ or from Mohr's circle geometry.
Proof: Sum of normal stresses on two mutually perpendicular planes is constant.
$$\sigma_x + \sigma_y = \sigma_n + \sigma_{n-perp} = \text{constant}$$
7. Theories of Failure
Material Types:
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Ductile: Significant plastic deformation before failure (e.g., mild steel, Al, Cu). Fail by shear.
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Brittle: Little plastic deformation, fractures suddenly (e.g., cast iron, concrete). Fail by tensile on principal plane.
Failure Theories:
| Theory | Statement | Failure Criterion | Suitable For |
|---|---|---|---|
| Maximum Principal Stress (Rankine) | Failure occurs when max principal stress reaches yield stress in simple tension/compression. | $$\displaystyle \sigma_1 = \sigma_y $$ (tension) or $$\displaystyle \sigma_3 = -\sigma_y $$ (compression) | Brittle materials |
| Maximum Shear Stress (Tresca/Coulomb) | Failure occurs when max shear stress reaches shear yield stress in simple tension ($$\displaystyle \tau_y = \sigma_y/2 $$). | $$\displaystyle \tau_{max} = \tau_y = \frac{\sigma_y}{2} $$ | Ductile materials (conservative) |
| Maximum Distortion Energy (Von Mises/Hencky) | Failure occurs when distortion strain energy per unit volume reaches yield value. | $$\displaystyle \sigma_{eq} = \sqrt{\sigma_1^2 - \sigma_1\sigma_2 + \sigma_2^2} = \sigma_y $$ | Ductile materials (more accurate) |
Graphical Representation ($$\displaystyle \sigma_1 $$-$$\displaystyle \sigma_3 $$ plane):
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Rankine: Vertical lines at $$\displaystyle \sigma_1 = \sigma_y $$, $$\displaystyle \sigma_3 = -\sigma_y $$.
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Tresca: Hexagon with corners at $$\displaystyle (\sigma_y, \sigma_y) $$, $$\displaystyle (\sigma_y, -\sigma_y) $$, etc.
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Von Mises: Ellipse inscribed in Tresca hexagon.
Application to Combined Loading:
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Axial + Torsion (Bolt): $$\displaystyle \sigma_1 = \frac{P}{A} + \sqrt{\left(\frac{P}{2A}\right)^2 + \tau^2} $$, $$\displaystyle \sigma_2 = \frac{P}{2A} - \sqrt{...} $$.
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Bending + Torsion (Shaft): As in Section 5.
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Biaxial (Thin-walled pressure vessel): $$\displaystyle \sigma_1 = \frac{pr}{t} $$ (hoop), $$\displaystyle \sigma_2 = \frac{pr}{2t} $$ (axial), $$\displaystyle \sigma_3 = 0 $$.
Factor of Safety (FOS):
$$n = \frac{\text{Yield Stress } (\sigma_y)}{\text{Allowable Stress from theory}}$$
[!TIP] Quick Recall: Ductile → Tresca or Von Mises. Brittle → Rankine. Von Mises is generally more accurate for ductile metals.
8. Columns & Buckling
Buckling vs. Crushing:
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Buckling (Elastic Instability): Long, slender columns fail by lateral deflection at load < crushing strength.
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Crushing (Material Failure): Short, stocky columns fail by direct compression at load > proportional limit.
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Slenderness Ratio: $$\displaystyle \lambda = \frac{L_e}{r} $$, where $$\displaystyle r = \sqrt{I/A} $$ (radius of gyration), $$\displaystyle L_e $$ = effective length.
Euler’s Formula (Derivation - Both Ends Pinned):
Assumptions: Perfectly straight, elastic, axially loaded, no initial crookedness.
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Differential equation: $$\displaystyle EI \frac{d^2y}{dx^2} = -M = -P y $$.
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$$\displaystyle \frac{d^2y}{dx^2} + k^2 y = 0 $$, where $$\displaystyle k^2 = P/(EI) $$.
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General solution: $$\displaystyle y = A \sin kx + B \cos kx $$.
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BCs: $$\displaystyle y(0)=0 \Rightarrow B=0 $$; $$\displaystyle y(L)=0 \Rightarrow \sin kL = 0 \Rightarrow kL = n\pi $$.
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Critical load: $$\displaystyle P_{cr} = \frac{n^2 \pi^2 EI}{L^2} $$. Fundamental mode ($$\displaystyle n=1 $$) gives lowest $$\displaystyle P_{cr} $$.
$$\boxed{P_{cr} = \frac{\pi^2 EI}{L^2}}$$
Effective Length ($$\displaystyle L_e $$) for Different End Conditions:
| End Condition | Effective Length $$\displaystyle L_e $$ | $$\displaystyle P_{cr} $$ |
|---|---|---|
| Both ends pinned (hinged) | $L$ | $$\displaystyle \frac{\pi^2 EI}{L^2} $$ |
| Both ends fixed | $L/2$ | $$\displaystyle \frac{4\pi^2 EI}{L^2} $$ |
| One fixed, one free | $2L$ | $$\displaystyle \frac{\pi^2 EI}{4L^2} $$ |
| One fixed, one pinned | $0.7L$ | $$\displaystyle \frac{2\pi^2 EI}{L^2} $$ |
Critical Stress & Slenderness:
$$\sigma_{cr} = \frac{P_{cr}}{A} = \frac{\pi^2 E}{(L_e/r)^2} = \frac{\pi^2 E}{\lambda^2}$$
- Limitation of Euler: Valid only if $$\displaystyle \sigma_{cr} < \sigma_{proportional limit} $$ (i.e., $$\displaystyle \lambda > \lambda_{cr} = \pi \sqrt{E/\sigma_{pl}} $$).
Rankine’s Formula (Empirical, for all lengths):
$$\boxed{P_{cr} = \frac{\sigma_c A}{1 + a \left(\frac{L_e}{r}\right)^2}} \quad \text{or} \quad \boxed{P_{cr} = \frac{\sigma_c A}{1 + \frac{\sigma_c}{\pi^2 E} \left(\frac{L_e}{r}\right)^2}}$$
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$$\displaystyle \sigma_c $$ = crushing strength (compressive yield stress).
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$a$ = Rankine constant ($$\displaystyle a = 1/(\pi^2 E/\sigma_c) $$ for Euler limit).
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For long columns ($\lambda$ large): $$\displaystyle P_{cr} \to \frac{\pi^2 EI}{L_e^2} $$ (Euler).
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For short columns ($\lambda$ small): $$\displaystyle P_{cr} \to \sigma_c A $$ (crushing).
Safe Load:
$$P_{safe} = \frac{P_{cr}}{n}$$
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Use Euler if $$\displaystyle \lambda > \lambda_{cr} $$ (long).
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Use Rankine for intermediate $\lambda$.
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Use Direct Crushing ($$\displaystyle P_{safe} = \sigma_c A / n $$) for short columns ($\lambda$ very small).
Crippling Load: Synonym for critical buckling load ($$\displaystyle P_{cr} $$).
[!TIP] Exam Strategy: For a given column, first compute $$\displaystyle \lambda = L_e/r $$. Compare with critical slenderness $$\displaystyle \lambda_{cr} = \pi\sqrt{E/\sigma_{pl}} $$ to decide formula. For built-up columns, use transformed section to find $I$ and $r$.
9. Specialized & Recurring Topics
Curved Beams (Circular Section):
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Neutral axis does not pass through centroid. It shifts towards the center of curvature.
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Stress Formula (at fiber at distance $y$ from NA, radius of curvature $\rho$):
$$\boxed{\sigma = \frac{Mc}{A r (e + y/\rho)}}$$
where $c$ = distance from NA to outer fiber, $r$ = radius to centroid, $$\displaystyle e = \frac{R}{A} \int \frac{dA}{y} $$ (eccentricity of NA from center).
- Finding NA: For pure bending, $$\displaystyle \int \frac{dA}{y} = 0 $$ (where $y$ measured from assumed NA).
Strain Energy:
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Bending: $$\displaystyle U = \int \frac{\sigma^2}{2E} dV = \int \frac{M^2}{2EI} dx $$.
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Torsion: $$\displaystyle U = \int \frac{\tau^2}{2G} dV = \int \frac{T^2}{2GJ} dx $$.
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Max Strain Energy in Shaft: $$\displaystyle U_{max} = \frac{\tau_{max}^2}{2G} \times \text{Volume} $$.
Composite Beams (Different Materials - Transformed Section):
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Transform all materials to an equivalent section of a reference material using factor $$\displaystyle n_i = E_i / E_{ref} $$.
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Find neutral axis of transformed section.
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Bending stress in material $i$: $$\displaystyle \sigma_i = \frac{M y}{n_i I_{tr}} $$, where $$\displaystyle I_{tr} $$ = $I$ of transformed section about NA.
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Ensure stresses do not exceed allowable for each material.
Impact Loading (Falling Weight on Vertical Bar):
- Instantaneous Deflection/Expansion:
$$\delta_i = \delta_{st} \left(1 + \sqrt{1 + \frac{2h}{\delta_{st}}}\right)$$
where $$\displaystyle \delta_{st} = \frac{PL}{EA} $$ is static deflection under load $P$.
- Derivation: Conserve energy: $$\displaystyle P h = \frac{1}{2} P \delta_i - \frac{1}{2} P \delta_{st} $$ (assuming no rebound).
Volumetric Strain ($$\displaystyle \epsilon_v $$):
$$\boxed{\epsilon_v = \epsilon_x + \epsilon_y + \epsilon_z}$$
For hydrostatic pressure $p$: $$\displaystyle \epsilon_v = -\frac{p}{K} $$.
Shear Modulus from E and ν:
$$G = \frac{E}{2(1+\nu)}$$
10. Short Notes & Definitions (Frequently Asked)
Principal Planes and Principal Stresses:
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Principal Planes: Planes on which shear stress is zero.
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Principal Stresses: Normal stresses on principal planes ($$\displaystyle \sigma_1 \geq \sigma_2 \geq \sigma_3 $$). They are the extreme values of normal stress.
Mohr’s Stress Circle:
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Construction: Plot $(\sigma, \tau)$ for two perpendicular planes. Circle center at $$\displaystyle (\frac{\sigma_x+\sigma_y}{2}, 0) $$, radius $$\displaystyle \sqrt{((\sigma_x-\sigma_y)/2)^2 + \tau_{xy}^2} $$.
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Utility: Graphical method to find normal/shear stress on any inclined plane, principal stresses, max shear stress, and their orientations without solving equations.
Theories of Failure (List):
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Maximum Principal Stress (Rankine): Brittle materials.
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Maximum Shear Stress (Tresca): Ductile materials.
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Maximum Distortion Energy (Von Mises): Ductile materials (more accurate).
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Maximum Normal Strain, Total Strain Energy (less common).
Equivalent Length of Columns:
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Definition: Length of a hypothetical pin-ended column with same $$\displaystyle P_{cr} $$ as the given column with actual end conditions.
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Values:
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Both ends pinned: $$\displaystyle L_e = L $$
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Both ends fixed: $$\displaystyle L_e = L/2 $$
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One fixed, one free: $$\displaystyle L_e = 2L $$
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One fixed, one pinned: $$\displaystyle L_e = 0.7L $$
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Macaulay’s Method:
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Definition: Method for beam deflection using step functions (Macaulay brackets) to write bending moment equation as a single continuous expression for the entire beam.
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Advantages over Direct Integration:
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Handles multiple point loads easily.
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Single integration constant set for each boundary condition.
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No need to write separate moment equations for each segment.
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Area-Moment Method:
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Theorems:
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First Theorem: Change in slope between two points = $$\displaystyle \frac{1}{EI} \times $$ (Area of M diagram between points).
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Second Theorem: Deflection of a point relative to tangent at another point = $$\displaystyle \frac{1}{EI} \times $$ (Moment of area of M diagram about that point).
-
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Advantages: Quick for standard cases, no integration.
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Limitations: Less convenient for varying $I$ or complex loading compared to other methods.
Crippling Load:
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Definition: The critical buckling load ($$\displaystyle P_{cr} $$) at which a column becomes unstable and deflects laterally.
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Euler’s Critical Load: $$\displaystyle P_{cr} = \pi^2 EI / L_e^2 $$ for pin-ended column.
Thermal Stresses:
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Definition: Stresses induced in a body due to restraint against free thermal expansion or contraction.
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Cause: When temperature change occurs but the body is prevented from expanding/contracting freely (e.g., fixed supports, composite bars with different $\alpha$).
Poisson’s Ratio ($\nu$):
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Definition: $$\displaystyle \nu = -\frac{\text{lateral strain}}{\text{longitudinal strain}} $$.
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Typical Values: 0.25-0.35 for metals, ~0.5 for rubber (incompressible), negative for some auxetics.
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Relationship: $$\displaystyle G = E/[2(1+\nu)] $$, $$\displaystyle K = E/[3(1-2\nu)] $$.
Composite Beams:
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Definition: Beams made of two or more different materials (e.g., steel-reinforced concrete, bimetallic strips).
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Analysis Method: Transformed Section Method (see Section 9). Transform all materials to equivalent section of one material using modular ratio $$\displaystyle n = E_{material}/E_{reference} $$.
Quarter-Fourth Rule:
- Brief: Approximate method to find moment of inertia ($I$) of built-up sections (like I-beams). Assume $$\displaystyle I \approx \frac{1}{12} b h^3 $$ for the flanges only, ignoring the web's contribution, or use $$\displaystyle \frac{1}{12}(b_f h_f^3 + b_w h_w^3) $$. Useful for quick estimates.