ME-304 · Strength of Material/Unsolved PYQ Paper
ME-304 Strength of Materials - Dec 2025 Question Paper
Under each question, How to answer lists the points an answer should cover, outlined by CampusPrep from the syllabus. Check the details against your textbook.
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7 MarksaTwo rods, one of steel and the other of aluminium, are connected in parallel and carry a total load of 100 kN, Areas are 1000 mm$^2$ (steel) and 1500 mm$^2$ (aluminium). Find the stress in each rod. Take $E_s = 200$ GPa, $E_a = 70$ GPa.
How to answer
- Compatibility: equal elongation/deformation in parallel rods
- Equilibrium: P_s + P_a = 100 kN with P = sigma*A
- Compatibility using sigma*L/E to relate stresses: sigma_s/E_s = sigma_a/E_a
- Solve for sigma_s and sigma_a
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7 MarksbDraw and explain stress-strain diagram for mild steel.
How to answer
- Draw stress-strain curve with proportional limit, elastic limit, yield points, ultimate stress, fracture
- Explain elastic, yielding, strain hardening, necking regions
- Mark salient points for mild steel
- Distinguish upper/lower yield and ductile behaviour
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7 MarksaA Steel bar of 1.5 m length and 25 mm dimeter is subjected to an axial tensile load of 40 kN. Determine the strain energy stored in the bar. Take E = 200 GPa.
How to answer
- Volume and cross-section: A = pi*d^2/4
- Axial stress sigma = P/A and elongation delta = P*L/(A*E)
- Strain energy formula U = P^2*L/(2*A*E)
- Substitute values to get U in joules
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7 MarksbDescribe the bending of composite sections and derive the expression for bending stress.
How to answer
- Concept of composite/flitched section and neutral axis
- Strain compatibility and modular ratio m = E1/E2
- Transformed section method
- Derivation of bending stress sigma = -M*y*E/(EI)_equivalent
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7 MarksaDraw shear force and bending moment diagrams for the cantilever shown in fig.1.
Given: Cantilever beam fixed at A (left), free at E (right). From A: 1 m to B with 3 kN downward at B, 1.5 m further to C, 2 m UDL of 1 kN/m from C to D, 0.5 m overhang D to E with 2.5 kN downward at E. How to answer
- Calculate support reactions at fixed end A
- Write SF equations for segments AB, BC, CD, DE including UDL
- Write BM equations and evaluate at A,B,C,D,E
- Draw SFD and BMD with values and shapes (linear/parabolic)
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7 MarksbExplain the concept of deflection of beams. List the factors affecting deflection.
How to answer
- Definition of beam deflection and elastic curve
- Governing differential equation EI d2y/dx2 = M
- Factors: load, span, EI, support, cross-section
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7 MarksaExplain the advantages of hollow shafts over solid shafts for power transmission applications.
How to answer
- Higher strength-to-weight and stiffness-to-weight ratio
- Larger polar moment for same area, efficient shear stress distribution
- Material saving and ease for internal services
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7 MarksbDerive the torsion equation for a circular shaft and explain the terms involved.
How to answer
- Assumptions: circular, homogeneous, elastic, plane sections remain plane
- Shear strain variation gamma = r*theta/L
- Equilibrium leading to T/J = tau/r = G*theta/L
- Meaning of T, J, tau, r, G, theta, L
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7 MarksaIn a tensile test, a test piece 25 mm in diameter, 200 mm gauge length stretched 0.0975 mm under a pull of 50,000 N. In a torsion test, the same rod twisted 0.025 radian over a length of 200 mm, when a torque of 400 Nm was applied. Evaluate the Poisson's ratio and the three elastic moduli for the material.
How to answer
- Tensile test: E = P*L/(A*deltaL) from stress/strain
- Torsion test: G = T*L/(J*theta) with J = pi*d^4/32
- Relate E,G,nu: E = 2G(1+nu) to get Poisson's ratio
- Compute K = E/(3(1-2nu)) for bulk modulus
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7 MarksbExplain the Maximum Distortion Energy Theory (Von Mises theory) and derive the failure condition.
How to answer
- Distortion energy concept and von Mises stress
- Strain energy decomposition into volumetric and distortional parts
- Failure condition in terms of principal stresses
- Expression for plane stress and uniaxial equivalence
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7 MarksaA bolt is subjected to an axial pull of 8 kN and a transverse shear force of 3 kN. Determine the diameter of the bolt required based on
- (i))The maximum principal stress theory
- (ii))The maximum shear stress theory
How to answer
- Compute axial stress sigma = P/A and shear stress tau = V/A
- Principal stresses sigma1,2 = sigma/2 +/- sqrt((sigma/2)^2+tau^2)
- Apply max principal stress <= sigma_allow = 270/3
- Apply max shear stress (Tresca) with FOS to solve diameter
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7 MarksbDiscuss the selection of appropriate failure theories for different materials and loading conditions.
How to answer
- Brittle vs ductile criteria (Rankine, Tresca, von Mises)
- Effect of hydrostatic vs biaxial/triaxial loading
- Temperature, strain rate and stress concentration considerations
- Examples of selection for shafts, pressure vessels, cast iron
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7 MarksaExplain slenderness ratio. Discuss its significance in determining the behaviour of columns.
How to answer
- Definition lambda = effective length / radius of gyration
- Euler buckling dependence on slenderness
- Short vs intermediate vs long column classification
- Critical slenderness and end-condition effects
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7 MarksbDerive Rankine's formula for columns and explain the significance of constants used.
How to answer
- Combine crushing and Euler buckling loads: 1/PR = 1/Pc + 1/PE
- Derive PR = sigma_c*A/(1+a*(Le/k)^2)
- Meaning of Rankine constant a and crushing stress
- Applicability to short/long columns and end conditions
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14 MarksWrite short notes on the any **two** of the following:
- (a))Column and strut.
- (b))Maximum Shear Strain Theory
- (c))Elastic curve of a beam
- (d))Hooke's law
How to answer
- Select any two topics with definition and key points
- Give relevant formula/theory and assumptions
- Add illustrative example or diagram where applicable
- Conclude with application/significance
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