CE-403 · Structural Analysis-I/Unsolved PYQ Paper
CE-403 Structural Analysis-I - Jun 2023 Question Paper
Under each question, How to answer lists the points an answer should cover, outlined by CampusPrep from the syllabus. Check the details against your textbook.
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14 MarksDetermine the forces in the members of the pin-jointed truss shown in figure 1.

How to answer
- Calculate support reactions at A and B from equilibrium
- Analyse joints D/C/A/B using equilibrium $\sum F_x=0, \sum F_y=0$
- Determine magnitude in each member (CA, CB, AB)
- Identify tensile vs compressive nature
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14 MarksDetermine the forces in all the members of the truss shown in figure 2 by using method of joints.

How to answer
- Find reactions at pin and roller supports
- Apply method of joints joint by joint
- Compute forces in top chord, bottom chord and vertical/diagonal members
- State tension/compression for all members
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14 MarksA mild steel bar 100 mm diameter is bent as shown in figure 3. It is fixed horizontally at A and a load of 500 N hangs at D. Draw the bending moment diagram for the parts AB, BC and CD, indicating the maximum values. Find the maximum bending stress. also find the deflection at D. Take $E = 2\times10^5$ $N/mm^2$.

How to answer
- Draw bending moment diagram for AB, BC, CD with maximum values
- Calculate maximum bending moment and section modulus for 100 mm diameter
- Compute maximum bending stress $\sigma = M/Z$
- Compute deflection at D by strain energy / Castigliano considering bending and torsion
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14 MarksA three hinged arch has span 20 m and a rise 4 m. The arch carries a uniformly distributed load of 20 kN/m on the left half of the span. Find the horizontal thrust at each support and location and magnitude of the maximum bending moment of the arch.
How to answer
- Calculate reactions and horizontal thrust for UDL on left half
- Write bending moment equation for arch vs beam moment
- Locate zero shear / maximum moment position
- Compute maximum bending moment magnitude
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14 MarksDetermine the prop reaction and the deflection at mid-span of a propped cantilever beam shown in figure 4. The prop sinks by 30 mm. Take EI = 15,000 $kNm^2$.

How to answer
- Treat prop reaction as redundant with settlement 30 mm downward
- Use compatibility: upward deflection due to R minus downward due to 100 kN equals settlement
- Solve for prop reaction R using $EI = 15000$ $kNm^2$
- Find mid-span deflection from superposition
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7 MarksaDetermine the fixed end moments for the loaded beam shown in figure 5. Also draw BMD for the beam of span 'l'.

How to answer
- Calculate fixed end moments due to W at l/4, l/2, 3l/4 using superposition
- Apply equilibrium and symmetry to get FEM at A and B
- Draw free and fixed BMD and combine
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7 MarksbA beam 10 m long fixed at both ends carries a uniformly distributed load of 4500 N/m over the entire span. Find the maximum bending and maximum bending deflection. Take E = 200 $kN/m^2$, I = $5\times10^7$ $mm^4$.
How to answer
- Recall fixed beam with full UDL: $M_{end}=wL^2/12$, $M_{mid}=wL^2/24$
- Compute maximum bending moment value
- Compute maximum deflection $wL^4/(384EI)$
- Substitute $E, I, w, L$ with unit conversion
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14 MarksThe support B of a continuous beam shown in figure 6 has settled by 12 mm. Find out the moments at supports.

How to answer
- Model AB as propped/fixed with UDL and BC with point load plus 12 mm settlement at B
- Apply slope-deflection / moment distribution with settlement term $6EI\Delta/L^2$
- Solve for moments at A, B, C
- Check equilibrium at joint B
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14 MarksConstruct the influence line for a diagonal member $U_5L_4$ of a Warren truss with verticals shown in figure 7.

How to answer
- Identify panel and section cutting U5L4
- Place unit load at successive lower joints and compute force in U5L4
- Plot ordinates to get influence line diagram
- Mark maximum positive and negative ordinates
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