UNIT 2: GEOTECHNICAL ENGINEERING - EXAM-FOCUSED NOTES
1. FUNDAMENTAL SOIL PROPERTIES & RELATIONSHIPS
Three-Phase Diagram & Volume-Mass Relationships
A soil mass consists of solids, water, and air. The three-phase diagram visually represents volume and mass relationships.
Key Definitions:
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Unit Weights:
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Moist unit weight, $$\displaystyle \gamma = \frac{W}{V} $$
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Dry unit weight, $$\displaystyle \gamma_d = \frac{W_s}{V} $$
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Saturated unit weight, $$\displaystyle \gamma_{sat} = \frac{W_{sat}}{V} $$
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Submerged unit weight, $$\displaystyle \gamma' = \gamma_{sat} - \gamma_w $$
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Water Content: $$\displaystyle w = \frac{W_w}{W_s} \times 100\% $$
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Void Ratio: $$\displaystyle e = \frac{V_v}{V_s} $$
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Porosity: $$\displaystyle n = \frac{V_v}{V} \times 100\% $$, $$\displaystyle n = \frac{e}{1+e} \times 100\% $$
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Degree of Saturation: $$\displaystyle S_r = \frac{V_w}{V_v} \times 100\% $$
Fundamental Relationship:
$$e = \frac{w G_s}{S_r}$$
Derivation: From $$\displaystyle w = \frac{W_w}{W_s} $$, $$\displaystyle S_r = \frac{V_w}{V_v} = \frac{W_w/\gamma_w}{e V_s} = \frac{w W_s / \gamma_w}{e V_s} $$. But $$\displaystyle G_s = \frac{\rho_s}{\rho_w} = \frac{W_s/V_s}{\gamma_w} \Rightarrow W_s = G_s \gamma_w V_s $$. Substituting gives $$\displaystyle S_r = \frac{w G_s}{e} \Rightarrow e = \frac{w G_s}{S_r} $$.
Interrelationships Table:
| Given | Find | Formula |
|---|---|---|
| $$\displaystyle w, G_s, e $$ | $$\displaystyle S_r $$ | $$\displaystyle S_r = \frac{w G_s}{e} $$ |
| $$\displaystyle w, G_s, S_r $$ | $e$ | $$\displaystyle e = \frac{w G_s}{S_r} $$ |
| $$\displaystyle \gamma, w, G_s $$ | $$\displaystyle \gamma_d $$ | $$\displaystyle \gamma_d = \frac{\gamma}{1+w} $$ |
| $$\displaystyle \gamma_d, G_s $$ | $e$ | $$\displaystyle e = \frac{G_s \gamma_w}{\gamma_d} - 1 $$ |
| $e, n$ | $n$ | $$\displaystyle n = \frac{e}{1+e} \times 100\% $$ |
Problem-Solving Approach:
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Draw a three-phase diagram with knowns.
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Use $$\displaystyle G_s = \frac{\rho_s}{\rho_w} $$ (or $$\displaystyle \gamma_w $$).
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Apply $$\displaystyle e = \frac{w G_s}{S_r} $$ and $$\displaystyle n = \frac{e}{1+e} $$.
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For mass of water to saturate: $$\displaystyle W_{w,add} = W_s \left( \frac{e_{final} - e_{initial}}{G_s} \right) $$, where $$\displaystyle e_{final} $$ corresponds to $$\displaystyle S_r = 100\% $$.
Exam Tip: Always check units: $w$ in decimal, $$\displaystyle \gamma_w = 9.81 $$ kN/m³ or 9.81×10⁻⁶ kN/mm³. For saturation, $$\displaystyle S_r $$ must be in decimal in formula.
2. SOIL CLASSIFICATION
Grain Size Analysis
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Sieve Analysis: For coarse-grained soils (>0.075 mm). Results plotted on semi-log graph.
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Hydrometer Analysis: For fine-grained soils (<0.075 mm). Based on Stokes' law.
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Grain Size Distribution Curve: $$\displaystyle D_{10}, D_{30}, D_{60} $$ are diameters at 10%, 30%, 60% finer by weight.
Gradation Parameters:
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Uniformity Coefficient: $$\displaystyle C_u = \frac{D_{60}}{D_{10}} $$
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Coefficient of Curvature: $$\displaystyle C_c = \frac{(D_{30})^2}{D_{60} \cdot D_{10}} $$
Criteria for Well-Graded Soils:
| Soil Type | $$\displaystyle C_u $$ | $$\displaystyle C_c $$ |
|---|---|---|
| Gravels (GW, GP) | $$\displaystyle C_u > 4 $$ | $$\displaystyle 1 \leq C_c \leq 3 $$ |
| Sands (SW, SP) | $$\displaystyle C_u > 6 $$ | $$\displaystyle 1 \leq C_c \leq 3 $$ |
Plasticity Characteristics
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Liquid Limit (LL): Water content at 25 blows in Casagrande cup.
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Plastic Limit (PL): Water content when soil crumbles.
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Plasticity Index (PI): $$\displaystyle I_p = LL - PL $$
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Liquidity Index (LI): $$\displaystyle I_L = \frac{w - PL}{I_p} $$ (indicates consistency)
Unified Soil Classification System (USCS)
Major Divisions:
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Coarse-Grained: >50% retained on No. 200 sieve. Classified by $$\displaystyle C_u $$, $$\displaystyle C_c $$, and grain shape.
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Gravels (G): $$\displaystyle D_{10} > 0.075 $$ mm
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Sands (S): $$\displaystyle 0.075 < D_{10} < 4.75 $$ mm
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Well-graded (W), Poorly-graded (P)
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Fine-Grained: >50% passes No. 200 sieve. Classified by Plasticity Chart (LL vs $$\displaystyle I_p $$).
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Inorganic: ML, CL, MH, CH (A-line: $$\displaystyle I_p = 0.73(LL-20) $$)
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Organic: OL, OH (dark color, odor)
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Silts (M): Low plasticity, $$\displaystyle I_p < 0.4(LL-20) $$ below A-line? Actually silts are ML/MH.
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Clays (C): High plasticity, above A-line.
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Highly Organic: Pt (peat).
Dual Notation: e.g., SC-SM (silty clay with sand).
IS Classification (Brief): Similar to USCS but uses group symbols like GW, SP, CL, CH, MI, CI, etc.
Textural Classification (Triangular Diagram)
Used for fine-grained soils (<0.075 mm) based on % sand, silt, clay. Boundaries separate sand, loam, silt, clay.
Exam Tip: For classification, first check coarse vs fine fraction. If coarse, use $$\displaystyle C_u $$, $$\displaystyle C_c $$. If fine, plot LL vs $$\displaystyle I_p $$ on plasticity chart. Remember A-line equation.
3. PERMEABILITY & SEEPAGE
Darcy's Law
$$\displaystyle Q = k i A = k \frac{h}{L} A $$
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$k$: coefficient of permeability (cm/s, m/day)
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$i$: hydraulic gradient
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Valid for laminar flow (Reynolds number < 1).
Factors Affecting $k$:
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Pore size (largest $k$ for gravels)
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Viscosity (decreases with temperature)
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Soil structure (layered vs isotropic)
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Entrapped air (reduces $k$)
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Degree of saturation (unsaturated $k$ << saturated)
Laboratory Determination
Constant Head Test (Coarse-grained):
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$$\displaystyle k = \frac{QL}{A h t} $$
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Procedure: Maintain constant head $h$, measure $Q$ in time $t$.
Falling Head Test (Fine-grained):
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$$\displaystyle k = \frac{aL}{A t} \ln \frac{h_1}{h_2} $$
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$a$ = area of standpipe, $A$ = cross-section of specimen.
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Procedure: Record head drop from $$\displaystyle h_1 $$ to $$\displaystyle h_2 $$ in time $t$.
Permeability of Stratified Deposits
Parallel to Flow (Horizontal):
$$k_{avg} = \frac{\sum k_i H_i}{\sum H_i}$$
Derivation: Total discharge $$\displaystyle Q = \sum q_i = \sum k_i i H_i = i \sum k_i H_i $$. But $$\displaystyle Q = k_{avg} i \sum H_i $$, so $$\displaystyle k_{avg} = \frac{\sum k_i H_i}{\sum H_i} $$.
Normal to Flow (Vertical):
$$k_{avg} = \frac{\sum H_i}{\sum \frac{H_i}{k_i}}$$
Derivation: Total head loss $$\displaystyle h = \sum h_i = \sum \frac{q H_i}{k_i} = q \sum \frac{H_i}{k_i} $$. But $$\displaystyle h = \frac{q}{k_{avg}} \sum H_i $$, so $$\displaystyle k_{avg} = \frac{\sum H_i}{\sum \frac{H_i}{k_i}} $$.
Seepage Pressure & Quick Sand Condition
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Seepage Pressure: $$\displaystyle p_s = \gamma_w i $$ (force per unit volume)
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Effective Stress with Seepage: $$\displaystyle \sigma' = \sigma - u + p_s $$ (downward flow increases $\sigma'$, upward decreases).
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Critical Hydraulic Gradient:
$$i_c = \frac{\gamma'}{\gamma_w} = \frac{G_s - 1}{1 + e}$$
Derivation: At boiling, $$\displaystyle \sigma'_{critical} = 0 $$. $$\displaystyle \sigma' = \gamma_{sub} z - \gamma_w i z = 0 \Rightarrow i = \gamma_{sub}/\gamma_w = (G_s-1)/(1+e) $$.
- Factor of Safety against Boiling: $$\displaystyle FS = \frac{i_c}{i_{actual}} $$
Exam Tip: Quick sand is a phenomenon, not a soil type. Occurs in saturated loose fine sands/silts under upward seepage.
Flow Nets
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Flow lines & equipotentials are orthogonal.
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Each flow channel carries equal discharge.
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Each drop between equipotentials is equal head loss.
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Curvilinear squares (aspect ratio ~1).
Discharge Calculation (per unit width):
$$q = k H \frac{n_f}{n_d}$$
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$$\displaystyle n_f $$: number of flow channels
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$$\displaystyle n_d $$: number of equipotential drops
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$H$: total head loss.
Effective Stress under Seepage
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Total Stress, $\sigma$: Weight of all material above.
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Neutral Stress, $u$: Pore water pressure.
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Effective Stress, $\sigma'$: $$\displaystyle \sigma' = \sigma - u $$.
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With Seepage: $$\displaystyle \sigma' = \sigma - u \pm \gamma_w i z $$ (plus for downward flow, minus for upward).
Common Pitfall: In upward seepage, effective stress decreases, can reach zero (quick condition). Always check direction of flow.
4. CONSOLIDATION
Concepts
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Primary Consolidation: Expulsion of water from pores under sustained load (time-dependent).
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Secondary Consolidation: Rearrangement of soil skeleton after primary consolidation (plastic deformation).
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Preconsolidation Pressure ($$\displaystyle \sigma'_p $$): Maximum past effective stress.
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Overconsolidation Ratio (OCR): $$\displaystyle OCR = \frac{\sigma'_p}{\sigma'_0} $$ (normally consolidated if OCR=1).
One-Dimensional Consolidation (Terzaghi)
Assumptions:
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Soil is homogeneous, fully saturated.
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Water & solids are incompressible.
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Flow is one-dimensional (vertical).
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Darcy's law valid.
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Small strains, constant $k$ and $$\displaystyle m_v $$.
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Load is instantaneous and uniform.
Differential Equation:
$$\frac{\partial u}{\partial t} = c_v \frac{\partial^2 u}{\partial z^2}$$
where $$\displaystyle c_v = \frac{k}{m_v \gamma_w} $$ (coefficient of consolidation).
Ultimate Settlement:
$$S = \frac{C_c}{1 + e_0} H \log \frac{\sigma'_0 + \Delta \sigma'}{\sigma'_0}$$
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$$\displaystyle C_c $$: compression index (from $e$-log$\sigma'$ curve, normally consolidated range).
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$$\displaystyle C_r $$: recompression index (reloading/unloading).
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$H$: thickness of compressible layer.
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$$\displaystyle \sigma'_0 $$: initial effective stress.
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$\Delta \sigma'$: increase in effective stress.
Compression Characteristics:
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$$\displaystyle C_c = \frac{\Delta e}{\log \sigma'_f - \log \sigma'_i} $$ (slope of virgin curve)
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$$\displaystyle m_v = \frac{\Delta e}{1 + e_0} \frac{1}{\Delta \sigma'} $$ (coefficient of compressibility)
Coefficient of Consolidation ($$\displaystyle c_v $$)
Determined from laboratory oedometer test using:
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Square-root of Time Method: $$\displaystyle T_v = \frac{c_v t}{H_{dr}^2} $$, plot $\sqrt{t}$ vs. $U$ or settlement.
- $$\displaystyle T_v = 0.197 $$ for $$\displaystyle U=50\% $$ (double drainage), $$\displaystyle H_{dr} = H/2 $$.
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Log-time Method: $$\displaystyle T_v = \frac{c_v t}{H_{dr}^2} $$, plot $\log t$ vs. $U$ or settlement.
- $$\displaystyle T_v = 0.197 $$ for $$\displaystyle U=50\% $$.
Time Factor ($$\displaystyle T_v $$) for Various U:
| U (%) | $$\displaystyle T_v $$ (double drainage) |
|---|---|
| 50 | 0.197 |
| 60 | 0.287 |
| 90 | 0.848 |
| 95 | 1.129 |
| 100 | ∞ |
Time for Consolidation:
$$t = \frac{T_v H_{dr}^2}{c_v}$$
- $$\displaystyle H_{dr} $$: longest drainage path (single drainage: $$\displaystyle H_{dr}=H $$, double drainage: $$\displaystyle H_{dr}=H/2 $$).
Exam Tip: Always identify drainage conditions first. Use appropriate $$\displaystyle H_{dr} $$. For $$\displaystyle U=50\% $$, $$\displaystyle T_v=0.197 $$ is standard.
5. STRESS DISTRIBUTION IN SOILS
Theories
Boussinesq's Theory (1885):
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Assumptions: Homogeneous, isotropic, semi-infinite elastic medium; point load applied at surface; no shear strength.
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Vertical Stress at Depth $z$:
$$\sigma_z = \frac{3P}{2\pi z^2} \frac{1}{\left[1 + (r/z)^2\right]^{5/2}}$$
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$r$: radial distance from axis.
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Directly below load ($$\displaystyle r=0 $$): $$\displaystyle \sigma_z = \frac{3P}{2\pi z^2} $$.
Westergaard's Theory (1938):
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Assumptions: Soil with vertical cracks (like clay), incompressible, no lateral strain.
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Vertical Stress:
$$\sigma_z = \frac{P}{z^2} \frac{1}{\left[1 + 2(r/z)^2\right]^{3/2}}$$
- More appropriate for clays (layered, anisotropic).
Comparison:
| Feature | Boussinesq | Westergaard |
|---|---|---|
| Soil Model | Isotropic elastic | Anisotropic (vertical cracks) |
| Lateral Strain | Allowed | Zero |
| Applicability | Cohesionless soils, sands | Clays, stratified deposits |
| Stress Distribution | More spread | Concentrated vertically |
Stress Beneath Loaded Areas
Point Load: Use Boussinesq equation directly. Uniformly Loaded Area:
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Equivalent Point Load Method: Replace area with point load at center, use Boussinesq for $$\displaystyle \sigma_z $$ at depth $z$.
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2:1 Distribution Method: $$\displaystyle \sigma_z = \frac{q \cdot B \cdot L}{(B+z)(L+z)} $$ (assumes 2:1 spread).
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Influence Charts: (e.g., Newmark's) for irregular shapes.
Total, Neutral, and Effective Stress
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Total Stress ($\sigma$): Sum of all weights above.
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Neutral Stress ($u$): Pore water pressure.
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Effective Stress ($\sigma'$): $$\displaystyle \sigma' = \sigma - u $$.
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With Water Table:
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Below WT: $$\displaystyle u = \gamma_w \cdot \text{depth below WT} $$ (if WT at surface).
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Above WT (unsaturated): $u$ may be negative (suction) or zero; if $$\displaystyle S_r < 100\% $$, $u$ is less than $$\displaystyle \gamma_w h $$.
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Exam Tip: For stress distribution problems, sketch soil profile, mark loads, and use superposition for multiple loads (as in Jun 2025 Q1).
6. SHEAR STRENGTH
Mohr-Coulomb Failure Criterion
$$\tau = c' + \sigma' \tan \phi' \quad \text{(effective stress)}$$
$$\tau = c_u \quad \text{(undrained, $$\displaystyle \phi_u=0 $$ for saturated clays)}$$
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$c'$: effective cohesion
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$\phi'$: effective friction angle
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$$\displaystyle c_u $$: undrained cohesion
Triaxial Shear Tests
| Test Type | Drainage During | Drainage During | Parameters Measured | Field Simulation |
|---|---|---|---|---|
| UU (Unconsolidated Undrained) | No | No | $$\displaystyle c_u $$, $$\displaystyle \phi_u \approx 0 $$ | Rapid loading, saturated clay |
| CU (Consolidated Undrained) | Yes | No | $$\displaystyle c'_{app} $$, $$\displaystyle \phi'_{app} $$ (with pore pressure) | Partially drained |
| CD (Consolidated Drained) | Yes | Yes | $c'$, $\phi'$ | Slow loading, drained |
Significance:
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UU: Quick test, no consolidation, measures undrained strength.
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CU: Consolidation allowed, undrained failure; with pore pressure measurement gives effective parameters.
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CD: Most realistic for long-term stability, but time-consuming.
Determination of Strength Parameters
Given confining pressures $$\displaystyle \sigma_3 $$ and failure deviator stresses $$\displaystyle (\sigma_1 - \sigma_3) $$:
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Compute $$\displaystyle \sigma_1 = \sigma_3 + (\sigma_1 - \sigma_3) $$.
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Plot Mohr's circles (center at $$\displaystyle \frac{\sigma_1+\sigma_3}{2} $$, radius $$\displaystyle \frac{\sigma_1-\sigma_3}{2} $$).
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Draw failure envelope tangent to circles.
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For UU: envelope horizontal at $$\displaystyle \tau = c_u $$.
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For CU/CD: envelope slope = $\tan \phi'$, intercept = $c'$.
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Example (Nov 2023):
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$$\displaystyle \sigma_3 = 150 $$ kN/m², failure load (deviator) = 500 kN/m² → $$\displaystyle \sigma_1 = 650 $$ kN/m².
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$$\displaystyle \sigma_3 = 300 $$ kN/m², failure load = 800 kN/m² → $$\displaystyle \sigma_1 = 1100 $$ kN/m².
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Plot circles, find envelope: $$\displaystyle c'_{app} $$ and $$\displaystyle \phi'_{app} $$ (since CU without pore pressure gives apparent values).
Liquefaction
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Definition: Loss of shear strength in saturated, loose, fine-grained soils (sands/silts) due to cyclic or rapid loading, causing pore pressure buildup and effective stress reduction to zero.
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Occurs When: $$\displaystyle S_r \approx 100\% $$, loose structure ($e$ high), cyclic loading (earthquakes), or rapid loading.
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Resistance: Increases with density, confining pressure, fines content.
Exam Tip: For triaxial tests, remember drainage conditions. UU: no drainage at all stages. CU: consolidation with drainage, then undrained failure. CD: drainage throughout.
7. COMPACTION
Definition vs Consolidation
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Compaction: Mechanical densification by expulsion of air (dry/wet). Immediate, volume change due to air compression/expulsion.
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Consolidation: Volume change due to expulsion of water under sustained load. Time-dependent.
Compaction Tests
| Feature | Standard Proctor (IS Light) | Modified Proctor (IS Heavy) |
|---|---|---|
| Energy (kN-m/m³) | 600 | 2700 |
| Mold volume | 944 cm³ | 944 cm³ (same) |
| Layers | 3 | 5 |
| Blows per layer | 25 | 25 |
| Hammer weight | 2.5 kg | 4.5 kg |
| Drop height | 30.5 cm | 45.7 cm |
| $$\displaystyle \rho_{dmax} $$ | Lower | Higher |
| $$\displaystyle w_{opt} $$ | Higher | Lower |
Compaction Curve
Plot dry density $$\displaystyle \rho_d $$ vs water content $w$.
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Optimum Moisture Content (OMC): $w$ at $$\displaystyle \rho_{dmax} $$.
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Zero Air Void Line: Theoretical $$\displaystyle \rho_d $$ at $$\displaystyle S_r=100\% $$: $$\displaystyle \rho_d = \frac{G_s \gamma_w}{1 + w \cdot G_s / 100} $$.
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Relative Compaction: $\%$ of $$\displaystyle \rho_{dmax} $$ achieved in field.
Field Compaction Methods
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Sheepsfoot Roller: For clays (kneading action).
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Smooth-wheel Roller: For sands/gravels.
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Pneumatic-tire Roller: For uniform compaction.
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Vibratory Roller: For granular soils.
Exam Tip: Modified Proctor gives higher $$\displaystyle \rho_{dmax} $$ and lower $$\displaystyle w_{opt} $$ due to higher energy.
8. SOIL STABILIZATION & GEOSYNTHETICS
Soil Stabilization Methods
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Mechanical: Compaction, blending with better soils.
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Chemical:
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Cement: Works for silts/clays/sands. Hydration products bind particles. Increases strength, reduces swell.
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Lime: For clayey soils. Reduces plasticity, increases strength via pozzolanic reactions.
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Bitumen: For waterproofing and binding (roads).
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Fly Ash: Pozzolanic, improves strength and reduces swelling.
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Geosynthetics
Types:
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Geotextiles: Woven (high strength) or non-woven (filtration/drainage).
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Geomembranes: Impermeable liners (HDPE, PVC).
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Geogrids: High tensile strength for reinforcement.
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Geocells: 3D honeycomb for confinement.
Functions:
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Separation: Prevent mixing of layers (e.g., soft soil and aggregate).
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Reinforcement: Tensile strength to resist loads (slopes, walls).
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Filtration: Allow water flow but retain fines.
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Drainage: Transmit water (geocomposites).
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Protection: Prevent puncture (geomembranes).
Applications:
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Slopes: Reinforcement with geogrids.
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Retaining Walls: Reinforcement in MSE walls.
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Pavements: Separation/filtration layers.
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Landfills: Liners (geomembranes) and leachate collection (geocomposites).
9. MISCELLANEOUS DEFINITIONS & COMPARISONS
Quick Sand Condition vs Boiling:
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Quick Sand: Upward seepage reduces effective stress to zero, soil loses shear strength, behaves like fluid.
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Boiling: Appearance of water at ground surface due to upward seepage exceeding $$\displaystyle i_c $$. Quick sand is the mechanism, boiling is the symptom.
Seepage Pressure: $$\displaystyle p_s = \gamma_w i $$ (force per unit volume). Acts in direction of flow.
Stresses:
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Total Stress ($\sigma$): Weight of everything above.
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Neutral Stress ($u$): Pore water pressure.
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Effective Stress ($\sigma'$): $$\displaystyle \sigma' = \sigma - u $$ (governs strength & deformation).
Coefficient of Consolidation ($$\displaystyle c_v $$) vs Coefficient of Compressibility ($$\displaystyle m_v $$):
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$$\displaystyle c_v = \frac{k}{m_v \gamma_w} $$ (rate of consolidation, m²/s).
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$$\displaystyle m_v = \frac{\Delta e}{(1+e_0)\Delta \sigma'} $$ (volume compressibility, m²/kN).
Coefficient of Compression ($$\displaystyle C_c $$) vs Compression Index: Same parameter; $$\displaystyle C_c $$ is slope of $e$-log$\sigma'$ curve for normally consolidated range.
Shear Strength vs Shear Stress:
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Shear Stress: Applied stress causing deformation.
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Shear Strength: Maximum shear stress soil can resist (governed by $c'$, $\phi'$ or $$\displaystyle c_u $$).
Assumptions in Terzaghi’s Consolidation Theory:
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Homogeneous, fully saturated soil.
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Water & solids incompressible.
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One-dimensional flow (vertical).
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Darcy's law valid.
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Small strains, constant $k$ & $$\displaystyle m_v $$.
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Instantaneous, uniform load.
Assumptions in Boussinesq’s Theory:
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Homogeneous, isotropic, elastic, semi-infinite medium.
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Point load at surface.
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No shear strength.
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Gravity stresses initially absent.
Unconfined Compression Test:
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Procedure: Apply axial load to cylindrical specimen (no confining pressure) until failure. Measure unconfined compressive strength (UCS) = $$\displaystyle q_u $$.
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Suitable for: Cohesive soils (clays) with $\phi \approx 0$. $$\displaystyle c_u = q_u/2 $$ for undrained condition.
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Limitation: Not for sands or coarse soils.
Exam Tip: Know key formulas: $$\displaystyle i_c = (G_s-1)/(1+e) $$, $$\displaystyle S = \frac{C_c}{1+e_0} H \log \frac{\sigma'_0+\Delta \sigma'}{\sigma'_0} $$, $$\displaystyle q = k H n_f/n_d $$, $$\displaystyle c_v = \frac{k}{m_v \gamma_w} $$.
END OF UNIT 2 NOTES
Always cross-check with problem-solving approaches from past papers. Practice numericals on permeability, consolidation time, stress distribution, and classification.