EX-402 · Electrical Machine-I/Unsolved PYQ Paper
EX-402 Electrical Machine - I - Dec 2024 Question Paper
Under each question, How to answer lists the points an answer should cover, outlined by CampusPrep from the syllabus. Check the details against your textbook.
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7 MarksaDiscuss the constructional features of transformers. Draw neat diagrams.
How to answer
- Core, windings, insulation, tank and cooling arrangements
- Types of cores - core type vs shell type construction
- Winding types - concentric, sandwich, LV/HV placement
- Neat labelled diagrams of core and shell type
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7 MarksbWhat is the SC test on transformer is conducted at rated Current and also draw circuit diagram.
How to answer
- Purpose of SC test - determine copper loss and equivalent impedance
- Test conditions - LV shorted, rated current on HV side, low voltage applied
- Circuit diagram with supply, ammeter, voltmeter, wattmeter
- Procedure and observations
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7 MarksaWith relevant phasor diagrams, explain the operation of a practical single phase transformer under no load condition.
How to answer
- No-load equivalent circuit with shunt branch R0, X0
- Phasor diagram with V1, I0, Iw, Imu, phi0
- Working vs magnetizing component explanation
- Effect of core loss and magnetizing reactance
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7 MarksbA $230/2300V$ transformer takes a no load current of $6.5A$ and absorbs $187W$. If the resistance of primary is $0.06\Omega$, find (a) Core loss (b) no load power factor (c) active component of current and (d) magnetizing current.
How to answer
- No-load input $W_0 = V_0 I_0 \cos\phi_0$ to find $\cos\phi_0$
- Subtract primary $I_0^2 R_1$ to get core loss
- Calculate $I_w = I_0 \cos\phi_0$ and $I_m = I_0 \sin\phi_0$
- Numerical values for all four quantities
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7 MarksaIn a transformer, derive the condition for maximum efficiency and thus find the load current at which the efficiency is maximum.
How to answer
- Efficiency expression $\eta = V_2 I_2 \cos\phi / (V_2 I_2 \cos\phi + P_i + I_2^2 R_{e2})$
- Condition $d\eta/dI_2 = 0$ gives $P_i = I_2^2 R_{e2}$
- Copper loss equals iron loss for maximum efficiency
- Load current $I_{2m} = \sqrt{P_i/R_{e2}}$
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7 MarksbA $20KVA$, $2000/200V$ single phase transformer has the following parameters: H.V. winding: $R_1 = 3\Omega$, $X_1 = 5.3\Omega$, L.V. winding: $R_2 = 0.05\Omega$, $X_2 = 0.1\Omega$. Find the Voltage Regulation at
- i)pp. of 0.8 lagging
- ii)UPF
- iii)0.707 p.f leading
How to answer
- Refer $R_1, X_1$ to LV or $R_2, X_2$ to HV to get $R_e, X_e$
- Voltage regulation formula $(I_e R_e \cos\phi \pm I_e X_e \sin\phi)/V$
- Calculate for 0.8 lagging, UPF and 0.707 leading
- Comment on sign for leading pf
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7 MarksaExplain the Scott connection of two single phase transformers with neat circuit diagram.
How to answer
- Purpose - 3-phase to 2-phase / 2-phase to 3-phase conversion
- Two transformers - main and teaser with 86.6% tapping
- Neat circuit diagram with connections
- Voltage relationships explanation
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7 MarksbDescribe the parallel operation of three phase transformers with unequal voltage ratios.
How to answer
- Conditions for parallel operation with unequal ratios
- Circulating current due to voltage difference
- Load sharing and equivalent circuit
- Effects on currents and losses
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7 MarksaDraw and explain the equivalent circuit of a three-phase induction motor.
How to answer
- Stator and rotor per-phase equivalent circuit
- Parameters R1, X1, R2/s, X2, Xm, Rc
- Explanation of slip-dependent load resistance
- Diagram with all components labelled
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7 MarksbA three phase induction motor is wound for 4 poles and is supplied from 50 Hz system. Calculate:
- i)Synchronous speed
- ii)Speed of the motor when slip is 4% and
- iii)Rotor current frequency when the motor runs at 600 rpm.
How to answer
- Synchronous speed $N_s = 120f/P$
- Rotor speed $N_r = N_s(1-s)$ for 4% slip
- Slip from 600 rpm to find rotor frequency $f_r = s f$
- Numerical values
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7 MarksaFrom fundamentals, deduce a relationship between Rotor power input, rotor copper loss and mechanical power developed in case of Induction motor.
How to answer
- Air-gap power $P_g$, rotor copper loss $sP_g$
- Mechanical power $P_m = (1-s)P_g$
- Ratio $P_g : P_{cu2} : P_m = 1 : s : (1-s)$
- Derivation from rotor equivalent circuit
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7 MarksbA 6-pole, 50HZ, 3-phase induction motor runs at 960 rpm when the torque on the shaft is 200 Nm. If the stator losses are 1500 W and the friction and windage losses are 500 W. Find;
- i)Rotor copper loss
- ii)The efficiency of the motor
How to answer
- Synchronous speed and slip from 960 rpm
- Shaft power $P_{sh} = 2\pi N T/60$
- Air-gap power and rotor copper loss $sP_g$
- Efficiency $\eta = P_{sh}/P_{in}$ with given losses
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7 MarksaExplain the various schemes of starting squirrel cage induction motor.
How to answer
- Need for reduced voltage starting
- DOL, star-delta, auto-transformer starters
- Rotor resistance and soft starter methods
- Circuit diagrams and comparison
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7 MarksbExplain the various techniques of speed control of induction motor from rotor side control.
How to answer
- Speed control by rotor resistance, slip power recovery
- Kramer and Scherbius schemes
- Rotor voltage injection principle
- Advantages, limitations and applications
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5 MarksaGive the classification of single phase motors. Explain any two types of single phase induction motors.
How to answer
- Classification - split phase, capacitor, shaded pole, etc.
- Construction and working of any two types
- Torque-speed characteristics
- Applications of each type
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5 MarksbDevelop equivalent circuit of a single phase induction motor ignoring core losses.
How to answer
- Double revolving field theory basis
- Forward and backward equivalent circuits
- Combining to get total impedance neglecting Rc
- Final equivalent circuit diagram
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4 MarkscExplain the principle of operation and applications of Linear Induction motor.
How to answer
- Construction - primary and secondary separated by air gap
- Travelling magnetic field and thrust production
- Slip concept in linear motor
- Applications - traction, conveyors, actuators
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