Skip to content
EX-404 · Power System-I/Quick Revision Short Notes

Power System-I (EX-404) - Unit 5 Short Notes

1.0 ECONOMICS OF POWER GENERATION & LOAD ANALYSIS

1.1 Load Curves & Load Duration Curves

  • Load Curve: Graph of load (kW/MW) versus time (hours/days). Shows variation.

    • Chronological Load Curve: Load vs. time of day (e.g., daily curve).

    • Load Duration Curve (LDC): Load values arranged in descending order vs. time (percentage of period). Area under LDC = Total energy.

  • Utility: Determines Maximum Demand, Load Factor, Plant Capacity Factor, and helps in economic dispatch and scheduling.

1.2 Key Performance Factors & Definitions

Term Definition Formula
Maximum Demand (MD) Peak load during a given period. --
Demand Factor (DF) Ratio of maximum demand to connected load. $$\displaystyle \text{DF} = \frac{\text{MD}}{\text{Connected Load}} $$
Load Factor (LF) Ratio of average load to maximum demand. $$\displaystyle \text{LF} = \frac{\text{Avg. Load}}{\text{MD}} = \frac{\text{Total Energy (kWh)}}{\text{MD} \times \text{Time}} $$
Diversity Factor (DFt) Ratio of sum of individual max demands to system max demand. $$\displaystyle \text{DFt} = \frac{\sum \text{Individual MD}}{\text{System MD}} $$
Plant Capacity Factor (PCF) Ratio of actual energy produced to maximum possible energy. $$\displaystyle \text{PCF} = \frac{\text{Actual Energy}}{\text{Installed Capacity} \times \text{Time}} $$
Utilization Factor (UF) Ratio of maximum demand to installed capacity. $$\displaystyle \text{UF} = \frac{\text{MD}}{\text{Installed Capacity}} $$

[!TIP] Proof: Diversity Improves System LF

System LF = (Total Energy) / (System MD × Time). Since System MD < Σ Individual MD (due to DFt > 1), for same total energy, a higher DFt reduces System MD, thus improving System LF.

1.3 Interconnection of Power Stations

  • Advantages:

    • Reduces Reserve Capacity (standby plants).

    • Enables Economic Load Dispatch (cheapest stations loaded first).

    • Improves Reliability & Stability.

    • Facilitates sharing of Peak Loads.

  • Disadvantages:

    • High Initial Cost (new lines, substations).

    • Complex Protection & Control.

    • Risk of Fault Propagation.

  • Methods of Controlling Power Transfer (between Station A & B with slack bus):

    • Active Power (kW): Controlled by Scheduled Power (P<sub>AB</sub>) setting. ΔP<sub>A</sub> = -ΔP<sub>B</sub>.

    • Reactive Power (kVAR): Controlled by Voltage Schedule at the interconnecting point. ΔQ<sub>A</sub> = -ΔQ<sub>B</sub>.

1.4 Effect of Load & Diversity Factors on Generation Cost

  • Good Load Factor (LF → 1): Reduces Maximum Demand for same energy → Smaller plant capacity → Lower Fixed Costs (capital, interest, depreciation).

  • Good Diversity Factor (DFt → large): Reduces System MD for same sum of individual MDs → Lower Fixed Costs for system.

  • Overall Cost per kWh ↓ when LF & DFt ↑, as fixed cost component per unit decreases.

1.5 Energy Cost Analysis

Total Annual Cost = Fixed Cost (A) + Variable Cost (B × Energy).

Cost per kWh = $$\displaystyle \frac{A}{\text{Annual kWh}} + B $$.

  • Impact of LF: If LF ↑, Annual kWh ↑ for same MD → $$\displaystyle \frac{A}{\text{kWh}} $$ ↓ → Cost/kWh ↓.

  • Example (Jun 2023): Cost at 40% LF = 12 paise/kWh. If LF ↑ to 60%, fixed cost/kWh ↓. Given fuel cost ↑ 5%, net effect = New Cost = 12 × (40/60) × 1.05 = 8.4 paise/kWh.

1.6 Types of Loads

Type Characteristics Examples
Industrial High, steady, often 3-phase, poor PF. Motors, furnaces.
Commercial Daytime peak, moderate PF. Shops, offices, AC.
Residential Morning/evening peaks, low PF. Lighting, appliances.
Agricultural Seasonal, daytime. Pumps.

1.7 Power System Structure

  • Conventional: Thermal (coal, gas), Hydro, Nuclear.

  • Non-Conventional (Renewable): Solar PV, Wind, Biomass, Geothermal, Tidal.

  • Distributed Generation (DG): Small, modular sources (solar rooftops, small wind) located near load centers.


2.0 TRANSMISSION LINE PARAMETERS: INDUCTANCE & CAPACITANCE

2.1 Fundamental Concepts

  • Flux Linkage (λ): Total flux linking a conductor.

  • Inductance (L): $$\displaystyle L = \frac{\lambda}{I} $$ (H).

  • Geometrical Mean Distance (GMD): For a set of distances D<sub>1</sub>, D<sub>2</sub>..., GMD = $$\displaystyle (D_1 \cdot D_2 \cdot ...)^{1/n} $$.

  • Geometrical Mean Radius (GMR) / Self-GMD: For a solid round conductor of radius r, GMR = 0.7788r. For bundled conductors, GMR = $$\displaystyle (r' \cdot D)^{1/2} $$ for 2-conductor bundle, where $$\displaystyle r' = 0.7788r $$.

  • Transposition: Periodic swapping of conductor positions to equalize inductance/capacitance of each phase over the line length.

2.2 Inductance Calculations

  • Single-Phase Two-Wire Line:

$$L = 2 \times 10^{-7} \ln\left(\frac{D}{r'}\right) \text{ H/m}$$

where D = distance between conductors, r' = GMR.
  • Three-Phase Lines:

    • Symmetrically Spaced (D<sub>12</sub>=D<sub>23</sub>=D<sub>31</sub>=D):

      $$\displaystyle L = 2 \times 10^{-7} \ln\left(\frac{D}{r'}\right) \text{ H/m per phase} $$.

    • Unsymmetrically Spaced: Use GMD (D<sub>s</sub>) for mutual distances and GMR (r') for self.

$$L = 2 \times 10^{-7} \ln\left(\frac{D_s}{r'}\right) \text{ H/m per phase}$$

    where $$\displaystyle D_s = (D_{12} D_{23} D_{31})^{1/3} $$.

*   **Double Circuit (Regular Hexagonal)**: Phase conductors on circle of radius R. GMD between phases of same circuit = D (side of hexagon). GMD between circuits = 2R. Equivalent GMD for inductance = $$\displaystyle (D \cdot D \cdot 2R \cdot 2R \cdot 2R \cdot 2R)^{1/6} = (4R^4 D^2)^{1/6} $$.

*   **Bundled Conductors (2 per phase)**: GMR<sub>bundle</sub> = $\sqrt{r' \cdot D}$ (D = spacing between conductors in bundle). Phase GMD (D<sub>s</sub>) as per configuration.
  • Effect of Conductor Material: $$\displaystyle L \propto \mu_r $$ (relative permeability). Steel (μ<sub>r</sub>≈50-100) has higher inductance than copper/aluminum (μ<sub>r</sub>≈1).

  • Skin Effect: Non-uniform current distribution at high freq. (AC) → current concentrates at surface → Effective AC resistance > DC resistance, Internal inductance decreases.

  • Proximity Effect: Magnetic field of one conductor distorts current distribution in adjacent conductor → increases AC resistance.

2.3 Capacitance Calculations

  • Single-Phase System (with Earth):

$$C = \frac{2\pi\epsilon_0}{\ln\left(\frac{2h}{r}\right)} \text{ F/m}$$

(h = height, r = radius). Earth effect increases capacitance.
  • Three-Phase Overhead Line:

    • Symmetrical Spacing: $$\displaystyle C = \frac{2\pi\epsilon_0}{\ln(D/r')} $$ F/m per phase to neutral.

    • Unsymmetrical: Use GMD (D<sub>s</sub>). $$\displaystyle C = \frac{2\pi\epsilon_0}{\ln(D_s/r')} $$.

  • Single-Core Underground Cable:

$$C = \frac{2\pi\epsilon}{\ln(D_i/d)} \text{ F/m}$$

where ε = ε<sub>0</sub>ε<sub>r</sub>, d = conductor diameter, D<sub>i</sub> = internal sheath diameter.

2.4 Transmission Line Configurations

Feature Bundled Conductor 3-φ Line Double Circuit 3-φ Line
Purpose Reduce reactance, increase surge impedance loading (SIL), reduce corona. Increase power transfer capacity, improve reliability.
Conductors/Phase 2 or more in close bundle (D<sub>bundle</sub> small). 2 separate circuits, each with 3 conductors.
GMD (Phase-Phase) Larger (phase spacing large) → Lower Inductance. Smaller (within circuit spacing) → Higher Inductance.
GMR Larger (bundle GMR) → Lower Inductance. Same as single conductor.
Net Effect Lower L, Lower C than equivalent single conductor. Higher L, Higher C than bundled line for same phase spacing.

3.0 TRANSMISSION LINE PERFORMANCE & MODELS

3.1 Classification of Lines

Type Length (approx.) Dominant Parameter Model
Short < 80 km, < 100 kV R, X only. C negligible. $$\displaystyle \boxed{Z = R + jX} $$
Medium 80-250 km, < 100 kV R, X, B/2 (distributed). Nominal-T or Nominal-Π
Long > 250 km, > 100 kV All parameters (R, L, G, C) distributed. Rigorous (wave equation).

3.2 Short Transmission Line Model

  • Phasor Diagram: V<sub>R</sub> + I<sub>R</sub> drop in series with V<sub>S</sub>. For lagging PF, V<sub>S</sub> > V<sub>R</sub>.

  • Voltage Regulation (VR):

$$\text{VR} = \frac{|V_S| - |V_R|}{|V_R|} \times 100\%$$

**Approximate VR** (for small R):

$$\text{VR} \approx \frac{I R \cos\phi_R + I X \sin\phi_R}{V_R} \times 100\%$$

  • Transmission Efficiency (η):

$$\eta = \frac{P_R}{P_S} \times 100\% = \frac{V_R I \cos\phi_R}{V_R I \cos\phi_R + I^2 R} \times 100\%$$

3.3 Medium Transmission Line Models

  • Nominal-T Model:

    • Total shunt admittance (Y = jωC) placed at midpoint.

    • Series impedance (Z = R + jX) split equally at ends.

    • ABCD Constants:

$$A = D = 1 + \frac{YZ}{2}, \quad B = Z, \quad C = Y\left(1 + \frac{YZ}{4}\right)$$

  • Nominal-Π Model:

    • Total series impedance (Z) in middle.

    • Shunt admittance (Y/2) at both ends.

    • ABCD Constants:

$$A = D = 1 + \frac{YZ}{2}, \quad B = Z\left(1 + \frac{YC}{4}\right) \approx Z \text{ (if Y small)}, \quad C = Y$$

*   **Phasor Diagram**: V<sub>R</sub> → drop across Z → V'<sub>S</sub> → add shunt current drop → V<sub>S</sub>.

3.4 Long Transmission Line

  • Rigorous Solution (Telegrapher's Equation):

$$\frac{d^2 V}{dx^2} = ZY V, \quad \frac{d^2 I}{dx^2} = ZY I$$

Solution: $$\displaystyle V = A_1 e^{\gamma x} + A_2 e^{-\gamma x} $$, $$\displaystyle I = \frac{1}{Z_0}(A_1 e^{\gamma x} - A_2 e^{-\gamma x}) $$

where $$\displaystyle \gamma = \sqrt{ZY} = \alpha + j\beta $$ (propagation constant), $$\displaystyle Z_0 = \sqrt{Z/Y} $$ (surge impedance).
  • Interpretation: Traveling waves with attenuation (α) and phase shift (β).

  • Equivalent Equation (for length l):

$$\begin{bmatrix} V_S \\ I_S \end{bmatrix} = \begin{bmatrix} \cosh\gamma l & Z_0 \sinh\gamma l \\ \frac{1}{Z_0}\sinh\gamma l & \cosh\gamma l \end{bmatrix} \begin{bmatrix} V_R \\ I_R \end{bmatrix}$$

ABCD constants: $$\displaystyle A = D = \cosh\gamma l $$, $$\displaystyle B = Z_0\sinh\gamma l $$, $$\displaystyle C = \frac{1}{Z_0}\sinh\gamma l $$.
  • Tuned Power Line: Line is "tuned" when $$\displaystyle \omega L = \frac{1}{\omega C} $$ (reactive power balance) → SIL (Surge Impedance Loading) = $$\displaystyle \frac{V^2}{Z_0} $$.

3.5 Performance Calculations

  • Sending End Quantities: From ABCD: $$\displaystyle V_S = A V_R + B I_R $$, $$\displaystyle I_S = C V_R + D I_R $$.

  • Voltage Regulation & Efficiency: As for short line, but using computed V<sub>S</sub>, I<sub>S</sub>.

  • Power Circle Diagram:

    • Real Power Circle: $$\displaystyle P_S = \frac{|V_S|^2}{B} \cos\theta - \frac{|V_S||V_R|}{B} \cos(\delta + \theta) $$.

    • Reactive Power Circle: $$\displaystyle Q_S = \frac{|V_S|^2}{B} \sin\theta - \frac{|V_S||V_R|}{B} \sin(\delta + \theta) $$.

    • Construction: Plot center at $$\displaystyle (\frac{|V_S|^2}{B}\cos\theta, \frac{|V_S|^2}{B}\sin\theta) $$, radius = $$\displaystyle \frac{|V_S||V_R|}{B} $$.

    • Interpretation: Intersection with axes gives max P<sub>S</sub> (at unity PF) and max Q<sub>S</sub>.

3.6 Special Phenomena

  • Ferranti Effect: Voltage rise at receiving end (V<sub>R</sub> < V<sub>S</sub>) for lightly loaded or no-load long/medium lines due to dominant capacitive charging current.

    • Derivation (No-load): I<sub>R</sub> = 0, I<sub>C</sub> = jωCV<sub>R</sub>/2 (Π model). V<sub>S</sub> = V<sub>R</sub> + I<sub>C</sub>(Z/2) → V<sub>S</sub> > V<sub>R</sub>.
  • Power Loss in Open-Circuited Line:

$$P_{\text{loss}} = \frac{|V_R|^2}{2} \left( \frac{R}{Z^2} \right) \text{ (per phase)}$$

(From I<sub>C</sub> = jωCV, P<sub>loss</sub> = I<sub>C</sub>²R).

4.0 MECHANICAL DESIGN OF OVERHEAD LINES

4.1 Supports & Sag

  • Types of Supports:

    • Wooden: Low voltage, short spans, cheap.

    • Steel Tubular/Poles: Medium voltage, urban.

    • Concrete: Medium/long spans, rural.

    • Lattice Steel Towers: EHV, long spans, high wind/ice.

  • Shape of Sag Curve: Parabola (for small sag/span ratio). Proof: Differential equation $$\displaystyle y'' = \frac{w}{H} $$, where w = load/unit length, H = horizontal tension ≈ constant.

  • Sag for Level Supports (weight only):

$$\boxed{S = \frac{w l^2}{8 T_m}}$$

where l = span, T<sub>m</sub> = tension at lowest point.

**Maximum Tension**: T<sub>max</sub> = T<sub>m</sub> + wS.
  • Effect of Wind & Ice Loading:

    • Total load per unit length: $$\displaystyle w' = \sqrt{(w + w_{ice})^2 + w_{wind}^2} $$.

    • Sag: $$\displaystyle S' = \frac{w' l^2}{8 T_m} $$ (assuming T<sub>m</sub> unchanged).

    • Where $$\displaystyle w_{ice} = \frac{\pi}{4} \rho_{ice} [(d+2t)^2 - d^2] $$, $$\displaystyle w_{wind} = \text{wind pressure} \times (d+2t) $$.

  • Sag Template & String Chart:

    • Sag Template: Full-scale template of sag curve for a standard conductor & tension. Used to check tower height and ground clearance.

    • String Chart: Plot of sag vs. span for various temperatures (tension changes). Used for stringing conductors.

4.2 Conductor Material & Sizing

  • Kelvin's Law for Economical Conductor Size:

    • Statement: The most economical conductor size is that for which annual interest & depreciation on capital cost equals annual energy loss cost.

    • Derivation:

      Let a = cross-sectional area (m²).

      Capital cost ∝ a. Annual cost = C₁a.

      Resistance R ∝ 1/a. Annual loss cost ∝ I²R ∝ I²/a.

      Total annual cost = C₁a + C₂/a.

      For minimum cost: $$\displaystyle \frac{d}{da}(C_1a + C_2/a) = 0 $$ → $$\displaystyle C_1 = C_2/a^2 $$ → a² = C₂/C₁.

    • Limitations:

      1. Assumes constant load factor & current.

      2. Interest/depreciation rates may vary.

      3. Does not consider mechanical strength (minimum area required for strength may be larger).

      4. Voltage drop not considered.

4.3 Tension & Safety

  • Maximum Allowable Tension:

$$T_{\text{allow}} = \frac{\text{Ultimate Strength}}{\text{Factor of Safety}}$$

  • Required Height/Height of Support:

$$H = S + \text{Ground Clearance}$$

(Ensure H ≥ minimum clearance).

5.0 INSULATION SYSTEMS FOR OVERHEAD LINES

5.1 Types of Insulators

Type Construction Application Advantages/Disadvantages
Pin Porcelain shell, pin cemented. Low voltage (< 33 kV). Simple, cheap. Low mechanical strength.
Suspension Series of porcelain discs (2-3 per kV) with metal caps/pins. High voltage (> 33 kV). Flexible, cheaper for high voltage, each disc replaceable.
Strain Similar to suspension but for high tensile load. Dead-end supports, river crossings. High mechanical strength.
Shackle Small, used for low voltage distribution. Service connections, street lighting. Can be used horizontally/vertically.

5.2 Insulator String Analysis

  • Capacitances:

    • Self-Capacitance (C): Capacitance between metal pin & cap of each unit.

    • Pin-to-Earth Capacitance (C<sub>1</sub>): Typically 0.1C to 0.2C.

  • Voltage Distribution (n identical units):

    Let V<sub>1</sub>, V<sub>2</sub>...V<sub>n</sub> be voltages across units from top (line) to bottom (earth).

    Using KCL at each node: $$\displaystyle C(V_i - V_{i+1}) = C_1 V_i + C(V_{i-1} - V_i) $$.

    With $$\displaystyle k = C_1/C $$, solution: $$\displaystyle V_i = V_1 \frac{\sinh[(n-i+1)\theta]}{\sinh\theta} $$, where $$\displaystyle \cosh\theta = 1 + k $$.

    Top unit voltage is maximum.

  • String Efficiency:

$$\boxed{\eta_{\text{string}} = \frac{V_{\text{string}}}{n \times V_{\text{bottom unit}}} \times 100\%}$$

(V<sub>string</sub> = line-to-earth voltage). Always < 100% due to non-uniform distribution.

5.3 Methods to Improve String Efficiency

  • Grading of Insulator Units: Use different capacitance units (longer discs at bottom, shorter at top) to equalize voltage drop.

  • Guard Ring (Grading Ring): Metallic ring electrically connected to line side & earth side, shields pin-to-earth capacitance, making it more uniform → more uniform voltage distribution.

5.4 Testing: Flash-over Voltage

  • Flash-over: Unintended arc over insulator surface due to excessive voltage.

  • Test: Apply increasing voltage until flash-over occurs. Critical Flash-over Voltage (CFOV) is noted.

5.5 Insulator Pollution & Grading

  • Pollution: Deposition of salt, dust, industrial fumes → conductive layer → leakage current → flash-over.

  • Grading (in context of pollution): Using silicone or hydrophobic materials that repel water, preventing continuous conductive layer.


6.0 UNDERGROUND CABLES & COMPARISONS

6.1 Construction & Types

  • Single-Core: One conductor + insulation + sheath + armouring.

  • Three-Core: Three conductors + common insulation + sheath + armouring.

  • Insulation: Paper (impregnated), Rubber, XLPE (cross-linked polyethylene), PILC (paper-insulated lead-covered).

  • Sheathing: Lead or aluminum for moisture barrier.

  • Armouring: Steel tape/wires for mechanical protection.

6.2 Electric Stress in Cables

  • Dielectric Stress (g): Electric field intensity (V/m).

$$g = \frac{V}{x \ln(D_i/d)} \text{ (radial, for coaxial cable)}$$

where x = radial distance from conductor center, d = conductor dia, D<sub>i</sub> = internal sheath dia.
  • Maximum Stress (g<sub>max</sub>): At conductor surface (x = d/2).

$$g_{\text{max}} = \frac{V}{d/2 \ln(D_i/d)} = \frac{2V}{d \ln(D_i/d)}$$

  • Minimum Stress (g<sub>min</sub>): At sheath inner surface (x = D<sub>i</sub>/2).

$$g_{\text{min}} = \frac{V}{D_i/2 \ln(D_i/d)} = \frac{2V}{D_i \ln(D_i/d)}$$

  • Operating Voltage: Must be ≤ g<sub>max</sub> (breakdown strength of insulation).

  • Insulation Thickness: From given g<sub>max</sub>, g<sub>min</sub> and d:

$$\frac{g_{\text{max}}}{g_{\text{min}}} = \frac{D_i}{d} \Rightarrow D_i = d \left(\frac{g_{\text{max}}}{g_{\text{min}}}\right)$$

Thickness t = (D<sub>i</sub> - d)/2.

6.3 Methods of Grading in Cables

To achieve uniform stress (g = constant):

  1. Capacitance Grading: Use multiple layers of dielectric with different permittivities (ε<sub>r</sub> decreasing radially).

  2. Intersheath Grading: Use metallic intersheaths at specific voltages to control potential distribution.

6.4 Comparison: Overhead Lines (OHL) vs. Underground Cables (UGC)

Feature Overhead Lines Underground Cables
Cost Low initial cost. Very high initial cost (excavation, insulation).
Installation Easy, quick. Difficult, time-consuming.
Fault Detection Easy, visible. Difficult, time-consuming.
Repair Quick. Slow, expensive.
Suitability Rural, long distance. Urban, congested areas, sea crossings.
Weather Impact High (wind, ice, lightning). Low.
Inductance Lower (larger spacing). Higher (smaller spacing).
Capacitance Lower. Higher (close conductors, high ε<sub>r</sub>) → limits long-distance AC power.
Lifetime Longer (30-50 yrs). Shorter (20-30 yrs).

6.5 Comparison: AIS vs. GIS

Feature AIS (Air Insulated Substation) GIS (Gas Insulated Substation)
Insulation Air, porcelain insulators. SF<sub>6</sub> gas (high dielectric strength).
Footprint Large. Very compact (1/10th area).
Cost Lower for EHV. Higher initial cost.
Maintenance Frequent (insulator cleaning). Low (sealed, gas monitoring).
Reliability Lower (exposed to environment). High (protected from pollution, salt, birds).
Application Rural, conventional substations. Urban, indoor, harsh environments, space-constrained.

7.0 DISTRIBUTION SYSTEMS & SUBSTATIONS

7.1 Distribution System Configurations

  • Radial: Single source → feeders → loads. Simple, cheap, but low reliability (single point failure).

  • Ring Main: Sources at both ends → closed loop. Loads tapped along ring. Higher reliability (supply from either end).

  • Interconnected: Multiple interconnections → Highest reliability (multiple supply paths), complex protection.

7.2 Distribution Practices

  • Why 3-φ, 3-wire Transmission? For high voltage, no neutral needed → saves one conductor (cheaper for long distance). Only balanced 3-φ loads.

  • Why 3-φ, 4-wire Distribution? To provide phase voltage (230V) for single-phase loads (lighting, domestic) along with line voltage (415V) for 3-φ loads. Neutral carries unbalanced current.

  • Copper Efficiency Comparison (same max voltage to earth):

    • 3-φ, 3-wire: Power $$\displaystyle P = \sqrt{3} V_L I_L \cos\phi $$. Resistance per phase $$\displaystyle R = \frac{\rho l}{A} $$. Loss = 3I<sub>L</sub>²R.

    • 3-φ, 4-wire: Same line voltage V<sub>L</sub>, but neutral present. For same power & losses, required area A<sub>4w</sub> > A<sub>3w</sub>. 3-wire is more economical.

7.3 Bus Bar Systems in Substations

  • Single Bus Bar with Sectionalization:

    • Arrangement: Single bus divided by a circuit breaker.

    • Merits: Can isolate a section without interrupting others. Some redundancy.

    • Demerits: Bus fault affects entire bus; breaker failure isolates section.

  • Sectionalized Double Bus Bar:

    • Arrangement: Two parallel buses, each with its breaker, and coupling breaker between them.

    • Merits: High reliability (maintenance on one bus, transfer via coupling breaker). Flexible.

    • Demerits: Costly, complex protection.

  • Ring Mains: Bus bars arranged in a ring. Similar reliability to double bus but with different switching.

7.4 Substation Equipment (Brief)

Equipment Function
Power Transformer Steps voltage up/down.
Circuit Breaker (CB) Makes/breaks normal & fault currents.
Isolator / Disconnecting Switch Isolates circuit under no-load for maintenance.
Current Transformer (CT) Steps down current for metering/protection (secondary 5A/1A).
Potential Transformer (PT) / CVT Steps down voltage for metering/protection (secondary 110V). CVT used for EHV.
Lightning Arrester Protects equipment from overvoltages (lightning, switching).
Bus Bars Collects/distributes power.
Control & Relay Panel Houses relays, meters, control switches.

7.5 Single Line Diagram (Typical A.C. Distribution)

DiagramSEARCH: "typical AC distribution substation single line diagram"
  • Shows: Incoming transmission line → CTs/PTs → CB → Isolators → Main Bus → Power Transformer → Outgoing feeders with CBs/Isolators → Distribution lines.

  • Key: All equipment represented by standard symbols; shows connectivity, not physical layout.


8.0 ECONOMIC DESIGN OF CONDUCTORS & SYSTEMS

8.1 Transmission Voltage Selection

  • Higher Voltage → Lower Current for same power → Lower I²R losses and Smaller conductor size.

  • Trade-off: Higher voltage requires more expensive insulation, larger tower size, higher clearance → Higher capital cost.

  • Economic Voltage: Chosen where total cost (capital + losses) is minimized. Typically, long distances → higher voltage.

8.2 Conductor Material Comparison: DC 2-wire vs. Single-Phase AC

  • Given: Same length (l), same power (P), same voltage (V<sub>L</sub>), same % losses.

  • DC 2-wire: P = V I<sub>dc</sub>, Loss = 2 I<sub>dc</sub>² R<sub>dc</sub>.

  • 1-φ AC: P = V I<sub>ac</sub> cosφ, Loss = 2 I<sub>ac</sub>² R<sub>ac</sub> (R<sub>ac</sub> > R<sub>dc</sub> due to skin effect).

  • For same losses & power:

    $$\displaystyle I_{ac} \cos\phi = I_{dc} $$ and $$\displaystyle I_{ac}^2 R_{ac} = I_{dc}^2 R_{dc} $$.

    → $$\displaystyle R_{ac} \cos^2\phi = R_{dc} $$.

    Since R<sub>ac</sub> > R<sub>dc</sub>, cosφ must be high (near 1) for AC to be competitive.

    Cross-sectional area A ∝ 1/R → A<sub>ac</sub> / A<sub>dc</sub> = R<sub>dc</sub>/R<sub>ac</sub> = cos²φ.

    → AC requires larger area than DC for same losses if cosφ < 1.

8.3 System Conversion Problem: 1-φ 2-wire to 3-φ 3-wire

  • Given: Same voltage (V<sub>L</sub>), same % losses, same length.

  • 1-φ 2-wire: P<sub>1</sub> = V I<sub>1</sub> cosφ, Loss = 2 I<sub>1</sub>² R<sub>1</sub>.

  • 3-φ 3-wire: P<sub>3</sub> = √3 V I<sub>3</sub> cosφ, Loss = 3 I<sub>3</sub>² R<sub>3</sub>.

  • Same losses: 2 I<sub>1</sub>² R<sub>1</sub> = 3 I<sub>3</sub>² R<sub>3</sub>.

    Same conductor material & length → R ∝ 1/A → R<sub>3</sub>/R<sub>1</sub> = A<sub>1</sub>/A<sub>3</sub>.

  • Additional load transmissible:

$$\frac{P_3}{P_1} = \frac{\sqrt{3} V I_3 \cos\phi}{V I_1 \cos\phi} = \sqrt{3} \frac{I_3}{I_1}$$

From loss equality: $$\displaystyle \frac{I_3}{I_1} = \sqrt{\frac{2 R_1}{3 R_3}} = \sqrt{\frac{2}{3} \frac{A_3}{A_1}} $$.

But for **same conductor size** (A<sub>3</sub> = A<sub>1</sub>), $$\displaystyle \frac{I_3}{I_1} = \sqrt{\frac{2}{3}} $$.

→ $$\displaystyle \frac{P_3}{P_1} = \sqrt{3} \times \sqrt{\frac{2}{3}} = \sqrt{2} \approx 1.414 $$.

→ **3-φ system transmits 41.4% more power** than 1-φ with same conductors, voltage, and losses.

8.4 Volume of Conductor Calculation

  • Given: Load (P), Voltage (V), Efficiency (η), Length (l), System type, ρ.

  • Step 1: Find P<sub>loss</sub> = P(1/η - 1).

  • Step 2: For system, find total resistance (R<sub>total</sub>) from loss formula.

    • 1-φ 2-wire: Loss = 2 I² R → R = P<sub>loss</sub> / (2 I²), I = P/(V cosφ).

    • 3-φ 3-wire: Loss = 3 I² R → R = P<sub>loss</sub> / (3 I²), I = P/(√3 V cosφ).

  • Step 3: R = ρ l / A → A = ρ l / R.

  • Step 4: Volume = A × l × (number of conductors).

    • 1-φ 2-wire: Volume = 2 × A × l.

    • 3-φ 3-wire: Volume = 3 × A × l.

[!TIP] Common Pitfall: Forgetting number of conductors (2 for 1-φ, 3 for 3-φ) when calculating total volume/cost. Also, ensure consistent units (ρ in Ω·m, l in m, A in m²).

Go to where you left off?

Quick Add to Notes

Save questions, your own notes and screenshots into notes filed by unit. It takes a free account.

Create free account

Have an account? Log in