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EX-404 · Power System-I/Quick Revision Short Notes

Power System-I (EX-404) - Unit 4 Short Notes

UNIT 4: Power Transmission and Distribution Systems


1. Power System Economics and Load Analysis

Load Curves and Load Duration Curves
  • Chronological Load Curve: Plot of load (kW or MW) versus time (hours/days/years). Shows variation of load with time.

  • Load Duration Curve (LDC): Load values arranged in descending order vs. time (percentage of total period). Obtained from chronological curve.

  • Utility: LDC directly gives:

    • Maximum Demand (peak of curve).

    • Load Factor = (Area under LDC) / (Area of rectangle with height = Max Demand).

    • Capacity Factor = (Area under LDC) / (Area of rectangle with height = Installed Capacity).

    • Economic Generation Planning: Helps in scheduling units (base, peak) and assessing reserve requirements.

[!TIP] Exam Tip: Be able to convert a given chronological table into an LDC and compute load factor/capacity factor.

Load Factors (Definitions & Interrelation)
Factor Definition Formula Impact on Cost
Demand Factor Ratio of maximum demand to connected load. $$\displaystyle k_d = \frac{P_{max}}{P_{connected}} $$ Lower value means under-utilization of connected load.
Load Factor Ratio of average load to maximum demand. $$\displaystyle LF = \frac{P_{avg}}{P_{max}} = \frac{\text{Energy (kWh)} }{P_{max} \times T} $$ Higher LF ➔ Lower cost/kWh (fixed costs spread over more units).
Diversity Factor Ratio of sum of individual max demands to station max demand. $$\displaystyle DF = \frac{\sum P_{max(i)}}{P_{max(station)}} $$ Higher DF ➔ Lower P_{max(station)} ➔ Lower capital cost.
Utilization Factor Ratio of maximum demand to installed capacity. $$\displaystyle UF = \frac{P_{max}}{P_{installed}} $$ Indicates spare capacity.
Plant Capacity Factor Ratio of actual energy produced to max possible energy. $$\displaystyle PCF = \frac{\text{Energy produced}}{P_{installed} \times T} $$ Measures overall plant utilization.

Key Relationship: $$\displaystyle P_{max(station)} = \frac{\sum P_{max(i)}}{DF} $$. A high DF reduces the required station capacity.

Interconnection of Power Stations
  • Advantages:

    1. Economy: Shared reserve, optimal dispatch (economic load sharing), reduced installed capacity.

    2. Reliability: Mutual aid during emergencies, improved load factor.

    3. Efficiency: Can use larger, more efficient units.

  • Disadvantages:

    1. High Initial Cost: Transmission lines, substations.

    2. Complexity: Protection, control, stability issues.

    3. Fault Propagation: Trouble in one area can cascade.

  • Control of Active & Reactive Power:

    • Active Power (kW): Controlled by governor settings (prime mover input). Increased mechanical power → increased electrical output. Tie-line power exchange is monitored and adjusted.

    • Reactive Power (kVAR): Controlled by excitation systems (field current). Increased excitation → increased voltage & reactive power output. Also via tap-changing transformers, shunt capacitors/reactors.

Economic Operation & Cost Analysis
  • Effect of LF & DF on Cost:

    • High LF → More energy sold → Fixed cost per unit ↓.

    • High DF → Lower P_{max} → Smaller/cheaper plant & equipment → Lower capital cost.

  • Annual Cost Components:

    • Fixed Cost: Interest, depreciation, taxes, insurance (independent of output).

    • Running Cost: Fuel, operation & maintenance (dependent on output).

  • Kelvin’s Law for Economic Conductor Size:

    • Statement: The most economical conductor size is that for which the annual cost of energy wasted equals the annual interest and depreciation on the capital cost of the conductor.

    • Derivation:

      Let $k$ = cost per kg of conductor, $r$ = resistivity, $l$ = length, $a$ = cross-sectional area.

      Capital Cost $$\displaystyle C_c = k \cdot a \cdot l $$.

      Annual Interest & Depreciation $$\displaystyle = C_c \cdot (i + d) = k a l (i+d) $$.

      Resistance $$\displaystyle R = \frac{\rho l}{a} $$.

      Annual Energy Loss $$\displaystyle E_{loss} = I^2 R \times \text{hours} \times LF_{loss} $$.

      Annual Cost of Loss $$\displaystyle C_l = \text{Cost per kWh} \times E_{loss} $$.

      Total Annual Cost $$\displaystyle C = C_c + C_l $$.

      For minimum $C$, $$\displaystyle \frac{dC}{da} = 0 \Rightarrow k l (i+d) - \frac{I^2 \rho l \cdot T \cdot LF_{loss}}{a^2} = 0 $$.

      \boxed{a = \sqrt{\frac{I^2 \rho T \cdot LF_{loss}}{k (i+d)}}}

    • Limitations:

      1. Ignores physical constraints (voltage drop, current density limits).

      2. Interest/depreciation rates & energy cost are estimates.

      3. Load factor for losses ($$\displaystyle LF_{loss} $$) is difficult to determine accurately.

      4. Does not account for future load growth.

  • Effect of Transmission Voltage:

    • For same power $P$, $$\displaystyle I = P/(\sqrt{3} V \cos\phi) $$. Higher $V$ → Lower $I$.

    • Lower $I$ → Smaller conductor size (area $\propto I$) → Lower material cost.

    • Lower $$\displaystyle I^2R $$ loss → Higher efficiency.

    • Trade-off: Higher voltage requires more expensive insulators, towers, and substation equipment. There is an optimum voltage for a given power and distance.

Renewable and Non-Conventional Energy Sources
  • Classification:

    • Conventional: Thermal (coal, gas, nuclear), Hydro.

    • Non-Conventional / Renewable: Solar, Wind, Geothermal, Biomass, Tidal.

    • Distributed Generation (DG): Small-scale generation (solar panels, small wind) located near the load center.

  • Wind Power:

    • Power Developed: $$\displaystyle P = \frac{1}{2} \rho A C_p V_w^3 $$

      • $\rho$: Air density (kg/m³)

      • $$\displaystyle A = \pi R^2 $$: Swept area (m²)

      • $$\displaystyle C_p $$: Power coefficient (Betz limit = 0.593)

      • $$\displaystyle V_w $$: Wind velocity (m/s)

    • Horizontal Axis Wind Mill (HAWM): Axis parallel to ground. Higher efficiency, needs yaw mechanism, more common.

    • Vertical Axis Wind Mill (VAWM): Axis perpendicular to ground. Omnidirectional, no yaw needed, lower efficiency, higher mechanical stress.


2. Transmission Line Parameters

Resistance and Skin Effect
  • Skin Effect: Non-uniform current distribution at high AC frequencies. Current density is higher near the surface, reducing effective cross-section → AC resistance > DC resistance. Increases with frequency, conductor size, and material permeability.

  • Proximity Effect: Distortion of current distribution due to magnetic fields from adjacent conductors. Increases AC resistance further. Significant in bundled conductors and closely spaced cables.

Inductance Calculations
  • Geometrical Mean Distance (GMD): For a group of conductors, it is the $$\displaystyle n^{th} $$ root of the product of all mutual distances between conductors.

$$GMD = \left( \prod_{i=1}^{n} \prod_{j=1, j\neq i}^{n} D_{ij} \right)^{1/n}$$

  • Geometrical Mean Radius (GMR) / Self-GMD: For a single conductor (stranded), it is the $$\displaystyle n^{th} $$ root of the product of all mutual distances between strands. For a round conductor of radius $r$: $GMR \approx 0.7788 r$. For a bundle of $n$ conductors with spacing $d$: $$\displaystyle GMR_{bundle} = (n \cdot d \cdot r)^{1/n} $$.

  • Single-Phase Two-Wire Line:

$$L = \frac{\mu_0}{2\pi} \ln\left(\frac{D}{GMR}\right) \text{ H/m}$$

where $D$ = distance between conductors.
  • Three-Phase Lines:

    • Symmetrically Spaced: $$\displaystyle L = \frac{\mu_0}{2\pi} \ln\left(\frac{GMD}{GMR}\right) $$.

    • Unsymmetrically Spaced: Transpose conductors to balance inductance. Equivalent $$\displaystyle GMD = \sqrt[3]{D_{12} D_{23} D_{31}} $$.

  • Bundled Conductors: Reduces inductance & capacitance, increases critical corona voltage. $$\displaystyle GMR_{phase} = (n \cdot d \cdot r)^{1/n} $$, $$\displaystyle GMD_{phase} = \sqrt[3]{D_{12} D_{23} D_{31}} $$ (where $$\displaystyle D_{ij} $$ are distances between bundle centers).

  • Transposition: Periodically exchanging conductor positions to make inductance & capacitance of all three phases equal. Necessary for unsymmetrical spacing.

Capacitance Calculations
  • Single-Phase Transmission System:

$$C = \frac{\pi \epsilon_0}{\ln(D/r)} \text{ F/m}$$

(Assuming earth is infinitely far, effect negligible).
  • Three-Phase Lines:

    • Equilateral Spacing: $$\displaystyle C = \frac{2\pi \epsilon_0}{\ln(GMD/GMR)} $$.

    • Unsymmetrical Spacing: Use method of images or transposition to find equivalent $C$.

  • Effect of Earth: Increases capacitance. Using method of images, the presence of earth is equivalent to an image conductor below. The capacitance becomes:

$$C_{with earth} = \frac{2\pi \epsilon_0}{\ln\left(\frac{\sqrt{D_{12} D_{13} D_{23}}}{r \cdot \sqrt{D_{1'2'} D_{1'3'} D_{2'3'}}}\right)}$$

where primed distances are to image conductors.
  • Single-Core Cable:

$$C = \frac{2\pi \epsilon}{\ln(r_i/r_c)} \text{ F/m}$$

where $$\displaystyle \epsilon = \epsilon_0 \epsilon_r $$, $$\displaystyle r_c $$ = conductor radius, $$\displaystyle r_i $$ = internal radius of sheath.
Conductor Selection and Economic Sizing
System Power Transmitted ($P$) Voltage ($V$) Current ($I$) Conductor Resistance ($R$) Conductor Area ($a \propto I$) Losses ($$\displaystyle I^2R $$)
Single-Phase 2-Wire $$\displaystyle P = 2 V I \cos\phi $$ $V$ (phase-neutral) $$\displaystyle I = P/(2V\cos\phi) $$ $2R$ (loop) $$\displaystyle a_{1\phi} \propto 1/V $$ $$\displaystyle \propto 1/V^2 $$
3-Phase 3-Wire $$\displaystyle P = \sqrt{3} V I \cos\phi $$ $V$ (line-line) $$\displaystyle I = P/(\sqrt{3} V \cos\phi) $$ $R$ (per phase) $$\displaystyle a_{3\phi} \propto 1/V $$ $$\displaystyle \propto 1/V^2 $$
3-Phase 4-Wire Same as 3-wire for phase loads $V$ (line-line) Same as 3-wire for phase loads Same Same for phase conductors Same

Conclusion: For same $P$, $V$, $\cos\phi$, and losses, 3-phase 3-wire requires least copper (only 3 conductors vs 4 in 4-wire, and lower current per conductor than single-phase).


3. Transmission Line Models and Performance

Short Transmission Lines (< 80 km)
  • Equivalent Circuit: Series impedance $$\displaystyle Z = R + jX $$ only. Shunt capacitance neglected.

  • Phasor Diagram: $$\displaystyle \vec{V}_s = \vec{V}_r + I \vec{Z} $$.

  • Voltage Regulation:

$$VR\% = \frac{|V_s|_{no-load} - |V_r|_{full-load}}{|V_r|_{full-load}} \times 100$$

Approximate formula (for lagging pf):

$$VR \approx \frac{I R \cos\phi_r + I X \sin\phi_r}{V_r} \times 100$$

  • Transmission Efficiency:

$$\eta = \frac{P_r}{P_s} \times 100 = \frac{V_r I \cos\phi_r}{V_r I \cos\phi_r + I^2 R} \times 100$$

Medium Transmission Lines (80-250 km)
  • Nominal-T Model: Shunt admittance ($Y/2$) placed in middle, series impedance ($Z$) split equally.

    • Sending end: $$\displaystyle I_s = I_r + \frac{Y}{2} V_r $$

    • $$\displaystyle \vec{V}_s = \vec{V}_r + I_r Z + \frac{Y}{2} V_r \cdot \frac{Z}{2} $$ (approx: $$\displaystyle \vec{V}_s = \vec{V}_r + I_r Z + \frac{Y}{2} V_r $$)

  • Nominal-π Model: Shunt admittance split ($Y/2$ at each end), series impedance ($Z$) in middle.

    • $$\displaystyle I_s = I_r + \frac{Y}{2} V_s + \frac{Y}{2} V_r $$

    • $$\displaystyle \vec{V}_s = \vec{V}_r + I_r Z $$

  • Generalized Circuit Constants (ABCD Parameters):

    For π-model:

$$A = D = 1 + \frac{YZ}{2}, \quad B = Z, \quad C = Y\left(1 + \frac{YZ}{4}\right) \approx Y$$

Relations: $$\displaystyle V_s = A V_r + B I_r $$, $$\displaystyle I_s = C V_r + D I_r $$.
  • Sending End Calculations: Given $$\displaystyle V_r $$, $$\displaystyle I_r $$, $$\displaystyle \phi_r $$, and line parameters, find $$\displaystyle V_s $$, $$\displaystyle I_s $$, $$\displaystyle P_s $$, $$\displaystyle pf_s $$ using ABCD constants.

  • Power Circle Diagram:

    • Construction: Plot $$\displaystyle P_r $$ vs $$\displaystyle Q_r $$ or $$\displaystyle P_s $$ vs $$\displaystyle Q_s $$ for constant $$\displaystyle |V_r| $$ or $$\displaystyle |V_s| $$. Circle equation derived from $$\displaystyle |V_s|^2 = |A V_r + B I_r|^2 $$.

    • Interpretation: Shows regions of power transfer for given voltages, limits for stability ($$\displaystyle dP_s/d\delta $$), and reactive power requirements.

Long Transmission Lines (> 250 km)
  • Rigorous Solution: Use telegrapher's equation. Voltage & current are traveling waves.

$$\frac{\partial^2 V}{\partial x^2} = Z Y V, \quad \frac{\partial^2 I}{\partial x^2} = Z Y I$$

Solution: $$\displaystyle V = V_1 e^{-\gamma x} + V_2 e^{\gamma x} $$, $$\displaystyle I = \frac{V_1}{Z_c} e^{-\gamma x} - \frac{V_2}{Z_c} e^{\gamma x} $$

where **Propagation constant** $$\displaystyle \gamma = \sqrt{ZY} = \alpha + j\beta $$, **Surge impedance** $$\displaystyle Z_c = \sqrt{Z/Y} $$.
  • Interpretation:

    • $$\displaystyle e^{-\gamma x} $$: Surge traveling toward receiving end (attenuated & phase-shifted).

    • $$\displaystyle e^{\gamma x} $$: Surge traveling toward sending end.

    • For lossless line ($$\displaystyle \alpha=0 $$): Pure sinusoid propagation, $$\displaystyle Z_c $$ is real.

  • Ferranti Effect: Voltage rise at the receiving end of a long, lightly-loaded line compared to sending end. Caused by the capacitive charging current flowing through the line inductance ($$\displaystyle I_c jX $$ voltage drop adds to $$\displaystyle V_r $$). More pronounced in cables and EHV/UHV lines.

  • Tuned Power Line: A long line designed so that its reactance is tuned (resonates) with its shunt capacitance at the operating frequency. Condition: $$\displaystyle X = 1/(\omega C) $$ or $$\displaystyle X \cdot \omega C = 1 $$. Results in $$\displaystyle Z_c = \infty $$ and $$\displaystyle \gamma = \sqrt{ZY} \approx \sqrt{jX \cdot j\omega C} = \sqrt{-\omega^2 X C} $$ → purely real? Actually, for tuned line, $$\displaystyle B = \omega C $$, $$\displaystyle X = 1/(\omega C) $$ so $$\displaystyle XY = -1 $$, $$\displaystyle \gamma = j\alpha $$? Careful: Tuned line means $$\displaystyle X = 1/(\omega C) $$ → $$\displaystyle Z = jX $$, $$\displaystyle Y = j\omega C $$, so $$\displaystyle ZY = -1 $$, $$\displaystyle \gamma = \sqrt{-1} = j $$, $$\displaystyle \alpha=0 $$, $$\displaystyle \beta=1 $$. The surge impedance $$\displaystyle Z_c = \sqrt{jX / j\omega C} = \sqrt{X / \omega C} = \sqrt{1/(\omega^2 C^2)} = 1/(\omega C) $$, finite. The key is that the line behaves like a pure resistance? Actually, a tuned line has constant voltage magnitude along its length. It's used in HVDC converter stations and some AC applications for power flow control.

Voltage Control Methods
  • Overview:

    1. Tap-Changing Transformers: On-load (OLTC) or off-load. Adjusts $V$ ratio.

    2. Shunt Compensation: Shunt capacitors (raise voltage), shunt reactors (lower voltage).

    3. Series Compensation: Series capacitors (reduce line reactance, increase power transfer, improve stability).

    4. Synchronous Condensers: Over-excited synchronous motor (acts as capacitor), under-excited (acts as inductor).

    5. Static VAR Compensators (SVC)/STATCOM: Fast-acting power electronics.

  • Detailed Example: Shunt Capacitors:

    • Purpose: Compensate for lagging reactive power of inductive loads/lines.

    • Connection: Delta or wye at substation or along the line.

    • Effect: Supplies leading current, reducing net reactive power flow from source → voltage rise at point of connection.

    • Calculation: Required $$\displaystyle Q_c = P (\tan\phi_{initial} - \tan\phi_{desired}) $$.


4. Mechanical Design of Overhead Lines

Sag and Tension Calculations (Level Supports)
  • Shape: Parabolic approximation (valid for sag << span). Exact shape is catenary.

  • Derivation:

    Let $L$ = span length, $w$ = weight per unit length, $$\displaystyle T_m $$ = tension at lowest point (horizontal tension), $x$ = horizontal distance from lowest point, $y$ = vertical sag at $x$.

    Equilibrium: $$\displaystyle T_m \frac{d^2 y}{dx^2} = w \sqrt{1 + (dy/dx)^2} \approx w $$ (for small sag).

    Integrating: $$\displaystyle \frac{dy}{dx} = \frac{w}{T_m} x $$, $$\displaystyle y = \frac{w}{2T_m} x^2 $$.

    At support ($$\displaystyle x = L/2 $$, $$\displaystyle y = S $$): $$\displaystyle S = \frac{w L^2}{8 T_m} $$.

    \boxed{S = \frac{w L^2}{8 T_m}} \quad \text{and} \quad \boxed{T_m = \frac{w L^2}{8 S}}

    Total tension at support: $$\displaystyle T_s = \sqrt{T_m^2 + (w L/2)^2} \approx T_m + \frac{w^2 L^2}{8 T_m} $$.

  • Effect of Wind and Ice Loading:

    • Total weight per unit length becomes: $$\displaystyle w' = \sqrt{(w + w_{ice})^2 + (w_{wind})^2} $$

    • where $$\displaystyle w_{ice} = \text{volume of ice per unit length} \times \text{density of ice} $$.

    • Wind load $$\displaystyle w_{wind} = \text{pressure} \times \text{projected diameter} $$ (conductor dia + 2×ice thickness).

    • Sag $$\displaystyle S' = \frac{w' L^2}{8 T_m} $$ (use maximum tension $$\displaystyle T_m $$ from safety criteria).

    • Maximum Sag occurs at the point of maximum $w'$ and maximum temperature (minimum $$\displaystyle T_m $$).

Sag Templates and String Charts
  • Sag Template: A full-scale drawing of the sag curve for a specific conductor, span, tension, and temperature. Used on profile drawings to:

    1. Check clearance at any point.

    2. Determine required support height for given terrain.

    3. Find stringing tension for a given clearance.

  • String Chart: Graph of tension vs. temperature for a fixed span and initial condition. Shows how tension changes with temperature (thermal expansion). Used to find stringing tension for a given temperature to achieve desired sag at maximum temperature.

  • Difference: Sag template is a spatial tool (sag vs. distance). String chart is a tension-temperature relationship tool.

Line Supports and Structures
Support Type Typical Voltage Span Length Features / Suitability
Wooden Poles LT Distribution (< 11 kV) Short (< 50 m) Cheap, insulating, low strength.
Steel Poles LT/HT Distribution (11-33 kV) Medium Stronger, longer life than wood.
H-Frame/Steel Towers Sub-Transmission (33-132 kV) Medium-Long Two poles with cross-arm.
Tower Structures EHV/Transmission (> 132 kV) Long (> 300 m) Self-supporting, various types (Suspension, Tension, Transposition). Designed for heavy loads, wind, ice.

5. Insulators and Insulation Coordination

Types of Insulators (with Construction)
Type Construction Application Sketch Key Feature
Pin Type Single porcelain/glass shell, pin cemented. LT distribution (< 33 kV). Pin mounted on cross-arm.
Suspension Type Series of discs (cap & pin) linked by hardware. HT/EHV transmission. Hangs from cross-arm, flexible.
Strain Type Similar to suspension but stronger, for dead-ends. Heavy tension points, river crossings. Reinforced, often with guy wires.
Shackle Type Small, for LT, can be clamped directly. LT distribution, service connections. No pin, clamped to pole.
  • Advantage of Suspension for HV: Economical (cheaper discs), flexible (reduces mechanical stress), easy to replace single disc, can be used for any voltage by adding discs.
Voltage Distribution in Insulator Strings
  • Capacitance Model:

    • $C$: Self-capacitance (capacitance to earth) of each unit.

    • $$\displaystyle C_1 $$: Pin-to-earth (or cap-to-earth) capacitance of each unit (due to metal fittings).

    • Usually $$\displaystyle C_1 = mC $$, where $m \approx 0.1 - 0.2$.

  • Derivation (for $n$ units):

    Let $$\displaystyle V_1, V_2, ..., V_n $$ be voltages across units from top (line side) to bottom (earth side).

    By Kirchhoff's current law at each node (except ends):

$$C(V_1 - V_2) + mC V_1 = C(V_2 - V_3) + mC V_2 \quad \Rightarrow \quad V_2 = \frac{1}{1+m} V_1 + \frac{m}{1+m} V_3$$

Solving recursively gives: $$\displaystyle V_k = V_1 \left[ \frac{\sinh((n-k)\theta)}{\sinh(n\theta)} \right] $$ where $$\displaystyle \cosh\theta = 1 + 2m $$.

For $$\displaystyle m << 1 $$, $\theta \approx \sqrt{2m}$.

**Top unit voltage** is highest.
  • String Efficiency:

$$\eta_{string} = \frac{\text{Voltage across string}}{\sum \text{Voltage across each unit}} \times 100 = \frac{V_1 + V_2 + ... + V_n}{n \cdot V_n} \times 100$$

(Often defined as $$\displaystyle V_{line} / (n \cdot V_{bottom}) $$ where $$\displaystyle V_{bottom} $$ is voltage on lowest unit).

\boxed{\eta_{string} = \frac{n}{1 + (n-1)m} \times 100\%} \quad (\text{for } m<<1, \text{ approximate})
Methods to Improve String Efficiency
  1. Grading of Insulator Units:

    • Use discs with different capacitances (e.g., larger diameter for lower units).

    • Aim: Make voltage distribution uniform. $$\displaystyle C_{top} < C_{bottom} $$.

    • Capacitance Grading: Vary disc size.

    • Intersheath Grading: Insert metallic sheaths between discs (rarely used).

  2. Guard Rings (Corona Rings):

    • Large diameter ring connected to top of string and to tower arm.

    • Increases capacitance from top units to earth ($m$ increases for top units), equalizing voltage distribution.

    • Also reduces corona on hardware.

Insulator Testing
  • Flash-Over Voltage Testing:

    1. Apply increasing AC voltage to insulator string until flash-over occurs.

    2. Record voltage at flash-over.

    3. Repeat to get average (dry, wet conditions specified).

    4. Critical Flash-Over Voltage (CFOV): Voltage at which flash-over probability is high.

    5. Withstand Voltage: Voltage the insulator can sustain for a specified time without flash-over.


6. Underground Cables

Construction and Types
  • Single-Core Cable: One conductor + insulation + sheath. Used for high voltage.

  • Multi-Core Cable: 3 or 4 cores in common sheath. Used for distribution (3-phase 4-wire).

  • Insulation Materials:

    • Paper (impregnated with oil): Traditional for HV.

    • Rubber (natural/synthetic): Flexible, LT.

    • PVC: General purpose, good mechanical properties.

    • XLPE (Cross-Linked Polyethylene): Modern, high dielectric strength, high temperature rating.

  • Sheath: Lead or aluminum for moisture/chemical protection.

Capacitance and Insulation Resistance
  • Capacitance (single-core, cylindrical): $$\displaystyle C = \frac{2\pi \epsilon}{\ln(r_i/r_c)} $$ F/km.

    • High capacitance → high charging current → limitation for long cables.
  • Insulation Resistance: $$\displaystyle R_{ins} = \frac{\rho_l \ln(r_i/r_c)}{2\pi l} $$ (for radial geometry). Decreases with length.

Dielectric Stress in Cables
  • Expression (radial, cylindrical symmetry):

$$E(r) = \frac{V}{r \ln(r_i/r_c)} \quad \text{(for r_c ≤ r ≤ r_i)}$$

where $V$ = conductor voltage (to sheath), $$\displaystyle r_c $$ = conductor radius, $$\displaystyle r_i $$ = insulation outer radius.
  • Maximum Stress: At conductor surface ($$\displaystyle r = r_c $$).

$$E_{max} = \frac{V}{r_c \ln(r_i/r_c)}$$

  • Minimum Stress: At insulation outer surface ($$\displaystyle r = r_i $$).

$$E_{min} = \frac{V}{r_i \ln(r_i/r_c)}$$

  • Calculation:

    Given $$\displaystyle E_{max} $$ (material limit), $$\displaystyle r_c $$, find $$\displaystyle r_i $$: $$\displaystyle r_i = r_c e^{V/(r_c E_{max})} $$.

    Operating voltage $V$ is phase-neutral for single-core.

Grading of Cables
  1. Capacitance Grading (Intersheath Grading):

    • Use multiple insulation layers of different $$\displaystyle \epsilon_r $$.

    • Place high $$\displaystyle \epsilon_r $$ material near conductor (where $E$ is high), low $$\displaystyle \epsilon_r $$ outside.

    • Homogeneous Dielectric: $E \propto 1/r$.

    • Graded Dielectric: $E$ becomes more uniform.

  2. Inter-sheath Grading: Insert thin metallic intersheaths at specific potentials between insulation layers. Each layer operates at lower voltage gradient.

Comparison: Overhead Lines vs. Underground Cables
Feature Overhead Lines Underground Cables
Cost Low (per km) Very high (installation, insulation)
Installation Easy, quick Difficult, time-consuming
Faults More (weather, pollution) Less, but hard to locate/repair
Appearance Visible, requires ROW Hidden, aesthetically better
Voltage Drop Low inductance, moderate capacitance Very high capacitance (charging current)
Suitable For Rural, long distance, high voltage Urban, congested areas, submarine

7. Distribution Systems and Substations

Types of Distribution Systems
System Description Advantages Disadvantages
Radial Single source, feeders radiate out. Simple, cheap, easy protection. Poor reliability (single point failure).
Ring Main Feeder forms a loop, supply from both ends. Better reliability, voltage regulation. More complex protection, higher cost.
Interconnected Multiple interconnections, meshed. Highest reliability, flexibility. Most complex, expensive, difficult protection.
Three-Phase Systems: 3-Wire vs. 4-Wire
  • Transmission (3-Wire): Only line conductors. No neutral needed as loads are balanced (or single-phase loads not connected). Saves one conductor (25% saving in copper for same voltage between phases).

  • Distribution (4-Wire): Includes neutral conductor. Allows:

    1. Single-phase loads (phase-to-neutral, 230 V) for domestic/commercial.

    2. Three-phase loads (phase-to-phase, 415 V) for industrial.

    3. Neutral carries unbalanced current & provides path for zero-sequence currents.

  • Copper Efficiency Comparison:

    • For same power $P$, voltage between phases $$\displaystyle V_L $$, power factor $\cos\phi$, and losses:

    • 3-Wire System: $$\displaystyle I = P/(\sqrt{3} V_L \cos\phi) $$. Conductor area $$\displaystyle a_{3w} \propto I $$.

    • 4-Wire System: For balanced 3-phase load, same $I$ per phase. But neutral may carry some current. Roughly, 4-wire requires about 33% more copper than 3-wire for same phase-to-phase voltage and balanced 3-phase load. The trade-off is the ability to serve single-phase loads.

Substation Equipment and Layout (Single Line Diagram)
  • Main Equipment:

    1. Power Transformer: Steps voltage up/down.

    2. Circuit Breaker (CB): Makes/breaks normal & fault currents.

    3. Isolator/Disconnecting Switch: Isolates equipment for maintenance (no load breaking).

    4. Current Transformer (CT): Steps down current for metering/protection.

    5. Potential Transformer (PT): Steps down voltage for metering/protection.

    6. Lightning Arrester: Protects against overvoltages (lightning, switching).

    7. Capacitor Bank: For power factor correction.

    8. Bus Bars: Collect and distribute power.

    9. Relays & Control Panels: Protection and control logic.

  • Typical SLD: Shows incoming lines → Isolators → CTs → CB → Transformer → Bus Bars → Outgoing CBs/Isolators → feeders. All major equipment represented by standard symbols.

Bus Bar Arrangements
Arrangement Description Merits Demerits
Single Bus Bar All circuits connected to one bus. Simple, cheap, minimal CBs. Bus fault → total shutdown. Maintenance difficult.
Single Bus with Sectionalization Bus split by a CB or isolator. Sectional fault → partial shutdown. Can isolate section for maintenance. More CBs, protection complex.
Double Bus Bar Two parallel buses, each circuit connected to both via CBs. One bus can be maintained without interruption. High reliability. Expensive (2x bus, more CBs), complex operation.
Sectionalized Double Bus Double bus with sectional CBs. Very high reliability & flexibility. Most expensive, most complex.
Ring Main Bus arranged in ring, often with sectionalizing. Alternate supply paths, good reliability. Protection coordination complex.

8. Special Topics and Comparative Studies

Bundle Conductors vs Double Circuit Lines
Feature Bundle Conductors (2+ per phase) Double Circuit Line (2 separate 3-phase circuits)
Configuration Multiple conductors per phase on same tower. Two complete 3-phase circuits on same tower.
Inductance Lower (due to larger GMR). Lower than single circuit, but higher than equivalent bundle? Actually, double circuit has mutual inductance between circuits, net inductance per phase can be lower.
Capacitance Higher (smaller GMD to other phases? Actually, bundling increases GMD to other phases? Wait: For same phase spacing, bundling increases GMR → decreases inductance, but for capacitance, $C \propto 1/\ln(GMD/GMR)$. Increasing GMR increases denominator → decreases capacitance? Let's think: $C \propto 1/\ln(GMD/GMR)$. If GMR increases (bundle), $\ln(GMD/GMR)$ decreases → $C$ increases. Yes, capacitance increases. Higher than single circuit due to presence of second circuit (mutual capacitance).
Corona & RI Better (larger effective diameter → higher critical voltage). Similar benefit from larger total conductor diameter per circuit? But separate circuits don't bundle.
Reliability Single circuit failure → total loss of that circuit. One circuit can be maintained/outaged, other supplies. Higher reliability.
Cost & Complexity More complex stringing, higher tower cost (wider). Much taller/wider towers, more insulators, hardware. Higher cost.
Application EHV/UHV (400 kV+) to reduce losses & improve stability. High reliability required routes, or to increase transfer capacity on existing corridor.
Air-Insulated Substations (AIS) vs Gas-Insulated Substations (GIS)
Feature AIS GIS
Insulation Air (atmospheric). SF₆ gas (high dielectric strength).
Footprint Large (clearances needed). Very Small (1/10th of AIS).
Cost Lower equipment cost, higher land cost. Higher equipment cost, lower land cost.
Maintenance Simple, visual inspection. Less frequent, but gas monitoring needed.
Environmental Visible, affected by pollution, birds. Enclosed, immune to pollution, salt fog.
Reliability Lower (exposed to weather, faults). Higher (encapsulated, less faults).
Application Rural, areas with cheap land. Urban, industrial, coastal, polluted areas, space-constrained.
Problems in Modern Large Interconnected Power Systems
  1. Stability Issues: Angle stability (transient, steady-state), voltage stability. Complex dynamics.

  2. Frequency Control: Need for automatic generation control (AGC) across regions.

  3. Protection Challenges: Faults affect large areas, need coordinated relaying, distance protection with communication.

  4. Power Flow Control: Congestion management, loop flows.

  5. Blackouts: Cascading failures, need for wide-area monitoring (WAMS) and control.

  6. Renewable Integration: Variability, uncertainty, inverter-based resources reducing inertia.

  7. Market Operations: Transmission congestion management, locational marginal pricing (LMP).

Tuned Power Lines (Brief)
  • A long transmission line where the inductive reactance ($X$) is tuned to the capacitive reactance ($1/\omega C$) such that $$\displaystyle X \cdot \omega C = 1 $$.

  • Characteristics:

    • Surge impedance $$\displaystyle Z_c = \sqrt{X / \omega C} = 1/(\omega C) $$ (pure resistive).

    • Propagation constant $$\displaystyle \gamma = \sqrt{ZY} = \sqrt{jX \cdot j\omega C} = \sqrt{-\omega^2 X C} = j \omega \sqrt{X C} $$? Wait: $$\displaystyle ZY = (jX)(j\omega C) = -\omega^2 X C $$. If $$\displaystyle X = 1/(\omega C) $$, then $$\displaystyle ZY = -1 $$, $$\displaystyle \gamma = \sqrt{-1} = j $$. So $$\displaystyle \alpha=0 $$, $$\displaystyle \beta=1 $$ rad/km. No attenuation, only phase shift.

    • Voltage magnitude remains constant along the line.

  • Application: Used in HVDC converter stations (as AC filter/tuned filter) and some special AC applications for power flow control.

Isolated vs Interconnected Power Systems
Aspect Isolated System Interconnected System
Reserve Capacity High (each station has own spinning reserve). Low (shared reserve, mutual assistance).
Economy Poor (smaller units, less optimal dispatch). Better (economical load sharing, use of large efficient units).
Reliability Low (single station failure causes blackout). High (alternative sources, redundancy).
Stability Easier to control (smaller). Difficult (complex dynamics, oscillations).
Capital Cost Lower initial (no interconnectors). Higher (transmission links, substations).
Operational Flexibility Low. High (power can flow as needed).
Frequency Control Simple, local. Complex, requires AGC & coordination.
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