BT-203 · Basic Mechanical Engineering/Unsolved PYQ Paper
BT-203 Basic Mechanical Engineering - Jun 2025 Question Paper
Under each question, How to answer lists the points an answer should cover, outlined by CampusPrep from the syllabus. Check the details against your textbook.
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8 MarksaClassify engineering materials. What do you mean by alloys? Write some applications of alloys.
How to answer
- Classification chart of engineering materials: metals, polymers, ceramics, composites
- Definition of alloy (solid solution or compound of two or more elements with metallic properties)
- Key reasons for alloying (enhance strength, corrosion resistance, hardness)
- Important engineering applications (steel in construction, brass/bronze in marine/bushings, duralumin in aerospace)
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6 MarksbDefine the following Mechanical properties:
- i)Toughness
- ii)Brittleness
- iii)Tensile strength
- iv)Ductility
How to answer
- Toughness: Ability of a material to absorb energy and plastically deform before fracturing
- Brittleness: Tendency to fracture with little to no prior plastic deformation when stressed
- Tensile strength: Maximum tensile stress a material can withstand before breaking/necking
- Ductility: Measure of a material's ability to undergo significant plastic deformation under tensile stress before rupture (e.g., drawing into wires)
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8 MarksaDescribe the construction and use of sine bar. How will you measure taper of a job with the help of a sine bar.
How to answer
- Construction: High-carbon chromium steel body, precision ground rollers of equal diameter at known distance $L$
- Principle: Trigonometric relation $\sin\theta = h / L$
- Setup for taper measurement: Place job on surface plate, sine bar over job or job on sine bar, slip gauges beneath one roller
- Procedure: Use dial test indicator across the taper surface until reading is parallel/zero, calculate angle using formula
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6 MarksbDescribe the procedure of a tensile test. Explain the stress-strain curve for a ductile material.
How to answer
- Tensile test procedure on UTM: Specimen preparation, gripping, applying tensile load gradually until fracture
- Draw engineering stress-strain curve for mild steel
- Label salient points: Proportional limit, elastic limit, upper & lower yield points, UTS, and fracture/rupture point
- Brief explanation of elastic region, plastic region, necking phenomenon
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8 MarksaWith a neat diagram explain the main parts of a drilling machine? Explain any two operations performed on drilling machine.
How to answer
- Neat sketch of drilling machine (upright or radial type)
- Key parts: Base, column, work table, spindle head, spindle, feed mechanism, drill chuck
- Explanation of any two operations: Drilling, reaming, boring, counterboring, countersinking, or tapping
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6 MarksbWhat is the basic principle of turbine? Classify various types of turbines according to type of energy, direction of flow head and specific speed.
How to answer
- Basic working principle: Conversion of hydraulic energy (kinetic + pressure) into mechanical energy via rotating runner blades
- Classification based on action of water: Impulse (Pelton wheel) vs Reaction (Francis, Kaplan)
- Classification based on direction of flow: Tangential, radial, axial, mixed flow
- Classification based on head: High head (>250 m), medium head (60-250 m), low head (<60 m)
- Classification based on specific speed: Low, medium, high specific speed
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7 MarksaExplain working of a thermocouple and radiation pyrometer with neat sketches.
How to answer
- Thermocouple: Working based on Seebeck effect (emf generated across hot and cold junctions of dissimilar metals), circuit diagram
- Radiation pyrometer: Non-contact measurement based on thermal radiation emitted by a hot body ($E = \sigma T^4$)
- Optical/radiation pyrometer diagram and functional description of lens, target, receiving element/filament
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7 MarksbThe water is flowing through a pipe having diameters $25\text{ cm}$ and $10\text{ cm}$ at section 1 and 2 respectively. The rate of flow of water through the pipe is $30\text{ lit/sec}$. Section 1 is $10\text{ m}$ above the ground and section 2 is $2\text{ m}$ above the ground. If pressure at section 1 is $40\text{ N/cm}^2$, find the pressure at section 2.
How to answer
- Convert units: $d_1 = 0.25\text{ m}$, $d_2 = 0.10\text{ m}$, $Q = 0.03\text{ m}^3/\text{s}$, $P_1 = 40 \times 10^4\text{ N/m}^2$, $\rho = 1000\text{ kg/m}^3$
- Calculate areas $A_1 = \frac{\pi}{4}(0.25)^2$, $A_2 = \frac{\pi}{4}(0.10)^2$
- Calculate velocities $V_1 = Q/A_1 \approx 0.611\text{ m/s}$, $V_2 = Q/A_2 \approx 3.82\text{ m/s}$
- Apply Bernoulli's equation: $\frac{P_1}{\rho g} + \frac{V_1^2}{2g} + z_1 = \frac{P_2}{\rho g} + \frac{V_2^2}{2g} + z_2$
- Substitute values and solve for $P_2$ in $\text{N/m}^2$ or $\text{N/cm}^2$
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7 MarksaDescribe the construction and working principle of the pelton wheel?
How to answer
- Introduction: High-head, low-discharge tangential flow impulse turbine
- Main components: Nozzle with spear mechanism, runner with hemispherical double-cup buckets, casing, breaking jet
- Working principle: High velocity water jet strikes splitter of the bucket, momentum change drives runner rotation
- Schematic sketch showing nozzle, runner, and bucket cross-section
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7 MarksbWhat is constant volume process? Derive expressions for the work done, change in internal energy heat transfer and change in enthalpy.
How to answer
- Definition of constant volume (isochoric) process ($V_1 = V_2$)
- Work done: $W = \int P dV = 0$ since $dV = 0$
- Change in internal energy: $\Delta U = m c_v (T_2 - T_1)$
- Heat transfer from first law: $Q = \Delta U + W = \Delta U = m c_v (T_2 - T_1)$
- Change in enthalpy: $\Delta H = m c_p (T_2 - T_1)$
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7 MarksaDefine internal energy and prove that energy is a property of a system?
How to answer
- Definition of internal energy as microscopic kinetic and potential energy of molecules
- Consider two different cycles between states 1 and 2: Cycle 1 via Path A & Path B, Cycle 2 via Path A & Path C
- Apply $\oint (\delta Q - \delta W) = 0$ to both cycles
- Show $(\delta Q - \delta W)_B = (\delta Q - \delta W)_C$, proving $dE$ depends only on end states and not on path
- Conclusion: Energy is a point function and thus a property of the system
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7 MarksbState the first law of thermodynamics for a closed system undergoing a cyclic process and non-cyclic process.
How to answer
- First law for cyclic process: The cyclic integral of heat transfer is equal to the cyclic integral of work transfer, $\oint \delta Q = \oint \delta W$
- First law for non-cyclic process: Heat added to a system equals increase in internal energy plus work done by the system, $Q = \Delta U + W$ (or $\delta Q = dU + \delta W$)
- Sign conventions and physical significance of energy conservation
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8 MarksaExplain the structure and working of two stroke diesel engine with a neat sketch?
How to answer
- Structure: Cylinder, piston with deflector crown, crankcase, inlet port, transfer port, exhaust port, fuel injector
- Working: Upward stroke (compression of air in cylinder, suction of air into crankcase) and fuel injection near TDC
- Downward stroke (power/expansion, exhaust blowdown, scavenging through transfer port)
- Neat schematic sketch showing ports and piston movement
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6 MarksbWith the help of a neat sketch describe the construction and working of a steam engine?
How to answer
- Construction: Cylinder, piston, piston rod, crosshead, connecting rod, crank, flywheel, steam chest, D-slide valve, eccentric
- Working principle: High-pressure steam enters through D-slide valve alternately to either side of double-acting cylinder, pushing piston
- Conversion of reciprocating motion into rotary motion through slider-crank mechanism
- Neat labeled sketch of double-acting steam engine
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14 MarksWrite short note on any three
- i)Newton's law of viscosity
- ii)Zeroth law of thermodynamics
- iii)Micrometer
- iv)Centrifugal compressor
How to answer
- Newton's law of viscosity: Shear stress is proportional to velocity gradient, $\tau = \mu \frac{du}{dy}$
- Zeroth law of thermodynamics: If two bodies are in thermal equilibrium with a third body, they are in thermal equilibrium with each other; basis of temperature measurement
- Micrometer: Precision measuring instrument using screw and nut principle, parts (anvil, spindle, sleeve, thimble, ratchet), least count calculation
- Centrifugal compressor: Dynamic compressor using rotating impeller to add kinetic energy followed by diffuser to convert kinetic energy into pressure rise
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