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EC-503 (A) · Communication Network and Transmission Lines (CNTL)/Quick Revision Short Notes

Communication Network and Transmission Lines (CNTL) (EC-503 (A)) - Unit 1 Short Notes

1.0 TRANSMISSION LINE FUNDAMENTALS

1.1 Transmission Line Parameters & Primary Constants

Transmission lines are modeled using distributed parameters per unit length:

  • R (Ω/m): Resistance due to conductor loss.

  • L (H/m): Inductance due to magnetic field energy storage.

  • G (S/m): Conductance representing dielectric leakage loss.

  • C (F/m): Capacitance due to electric field energy storage.

These are called primary constants. They determine the secondary constants: propagation constant (γ), attenuation constant (α), phase constant (β), characteristic impedance (Z₀), and velocity (v).

[!TIP]

Common Exam Question: "Define R, L, G, C and give their units."

Remember: R and G cause power loss; L and C store energy.


1.2 Transmission Line Equations & Wave Propagation

Consider an infinitesimal length dx of a transmission line. Applying Kirchhoff's laws:

Voltage equation:
$$\displaystyle V(x) - V(x+dx) = (R + j\omega L)dx \cdot I(x) $$

$$\frac{\partial V}{\partial x} = -(R + j\omega L)I \quad (1)$$

Current equation:
$$\displaystyle I(x) - I(x+dx) = (G + j\omega C)dx \cdot V(x) $$

$$\frac{\partial I}{\partial x} = -(G + j\omega C)V \quad (2)$$

Differentiating (1) w.r.t. x and substituting (2) yields the wave equation:

$$\frac{\partial^2 V}{\partial x^2} = \gamma^2 V$$

where the propagation constant is:

$$\gamma = \alpha + j\beta = \sqrt{(R + j\omega L)(G + j\omega C)}$$

Similarly for current. The general solutions are:

$$V(x) = V^+ e^{-\gamma x} + V^- e^{\gamma x}$$

$$I(x) = \frac{V^+}{Z_0} e^{-\gamma x} - \frac{V^-}{Z_0} e^{\gamma x}$$

Characteristic impedance (Z₀):

$$Z_0 = \sqrt{\frac{R + j\omega L}{G + j\omega C}} \quad \boxed{Z_0 = \frac{V^+}{I^+} = \frac{V^-}{-I^-}}$$

For a lossless line (R=0, G=0):

$$\gamma = j\omega\sqrt{LC}, \quad Z_0 = \sqrt{\frac{L}{C}}, \quad v = \frac{1}{\sqrt{LC}}$$

Velocity of propagation:

$$v = \frac{\omega}{\beta} = \frac{1}{\sqrt{LC}} \text{ (lossless)}$$

Wavelength:

$$\lambda = \frac{2\pi}{\beta} = \frac{v}{f}$$

[!TIP]

Very High Priority: Derivation of transmission line equations is frequently asked.

Key Insight: γ describes wave attenuation (α) and phase shift (β); Z₀ is the ratio of voltage to current for a traveling wave.


1.3 Line Types & Special Cases

Case Condition Propagation Constant (γ) Characteristic Impedance (Z₀) Input Impedance (Z_in)
Lossless R=0, G=0 $j\omega\sqrt{LC}$ $\sqrt{L/C}$ $$\displaystyle Z_{in} = jZ_0 \tan(\beta l) $$ (general)
Distortionless R/L = G/C $$\displaystyle \alpha = R\sqrt{C/L} $$, $$\displaystyle \beta = \omega\sqrt{LC} $$ $\sqrt{L/C}$ Same as lossless but with α
Quarter-wave $$\displaystyle l = \lambda/4 $$ — — $$\displaystyle \boxed{Z_{in} = \frac{Z_0^2}{Z_L}} $$
Half-wave $$\displaystyle l = \lambda/2 $$ — — $$\displaystyle \boxed{Z_{in} = Z_L}} $$
Short-circuited $$\displaystyle Z_L = 0 $$ — — $$\displaystyle Z_{in} = jZ_0 \tan(\beta l) $$
Open-circuited $$\displaystyle Z_L = \infty $$ — — $$\displaystyle Z_{in} = -jZ_0 \cot(\beta l) $$

[!TIP]

High Priority: Quarter-wave line inverts impedance; half-wave repeats it.

Short/Open lines act as reactances: $$\displaystyle Z_{in} \propto \tan(\beta l) $$ or $\cot(\beta l)$.


1.4 Power Flow & Losses

For a lossless line ($$\displaystyle \alpha=0 $$) with matched load ($$\displaystyle Z_L = Z_0 $$), average power is:

$$P_{avg} = \frac{|V|^2}{2Z_0} = \frac{|I|^2 Z_0}{2}$$

With mismatch, incident power $$\displaystyle P_i $$, reflected power $$\displaystyle P_r $$, and forward power $$\displaystyle P_f $$:

$$P_r = |\Gamma|^2 P_i, \quad P_f = (1 - |\Gamma|^2) P_i$$

Reflection coefficient (Γ):

$$\Gamma = \frac{Z_L - Z_0}{Z_L + Z_0} \quad \boxed{|\Gamma| \leq 1 \text{ for passive } Z_L}$$

Voltage Standing Wave Ratio (VSWR):

$$S = \frac{1 + |\Gamma|}{1 - |\Gamma|} \quad \boxed{S \geq 1}$$

Inverse: $$\displaystyle |\Gamma| = \frac{S-1}{S+1} $$

Reflection loss (mismatch loss):

$$L_r = -10 \log_{10}(1 - |\Gamma|^2) \text{ dB}$$

Insertion loss (when source and load are matched to Z₀) equals reflection loss.

[!TIP]

Very High Priority: VSWR and Γ are interconvertible. Always check if load is passive (|Γ| ≤ 1).

Common Pitfall: Insertion loss ≠ reflection loss if source/load not matched.


1.5 Line Analysis & Measurement

Smith Chart
DiagramCANVAS: A polar plot with constant resistance circles (centered on real axis) and constant reactance arcs (curved lines). The outermost circle represents |Γ|=1. Normalized impedance z = Z/Z₀ is plotted. The chart also includes a wavelength scale around the periphery for transmission line solutions. Admittance chart is obtained by rotating 180°.

Construction:

  • Based on normalized impedance $$\displaystyle z = Z / Z_0 = r + jx $$.

  • Constant resistance circles: $$\displaystyle r = \text{constant} $$, centers at $(r/(r+1), 0)$.

  • Constant reactance arcs: $$\displaystyle x = \text{constant} $$, arcs intersecting real axis.

  • Wavelength scale: clockwise rotation corresponds to moving toward load.

Applications:

  1. Impedance matching: Using lumped elements or stubs.

  2. Finding Γ and VSWR: Distance from center to point gives |Γ|; intersection with real axis gives VSWR.

  3. Admittance transformation: Rotate 180° or use admittance chart.

  4. Determining electrical length: Move along constant |Γ| circle.

[!TIP]

Very High Priority: Smith Chart is essential for impedance matching problems. Practice reading normalized impedances and moving toward load/generator.

Determination of Primary & Secondary Constants

Given open-circuit impedance $$\displaystyle Z_{oc} $$ and short-circuit impedance $$\displaystyle Z_{sc} $$:

Characteristic impedance:

$$Z_0 = \sqrt{Z_{oc} Z_{sc}} \quad \boxed{Z_0 = \sqrt{Z_{oc} Z_{sc}}}$$

Propagation constant:

$$\gamma = \cosh^{-1}\left(\frac{Z_{oc}}{Z_0}\right) = \cosh^{-1}\left(\frac{Z_{sc}}{Z_0}\right)$$

Then $$\displaystyle \alpha = \text{Re}(\gamma) $$, $$\displaystyle \beta = \text{Im}(\gamma) $$.

Primary constants from $\gamma$ and $$\displaystyle Z_0 $$:

$$R + j\omega L = \gamma Z_0, \quad G + j\omega C = \frac{\gamma}{Z_0}$$

If given attenuation A (dB/km) and phase constant β (rad/km):

$$\alpha = \frac{A \ln(10)}{20} \text{ (Np/km)}$$

Then $$\displaystyle \gamma = \alpha + j\beta $$, and compute R, L, G, C as above.

[!TIP]

Common Exam Problem: "Find R, L, G, C from Z_oc, Z_sc, and frequency." Use the boxed formulas step-by-step.


Summary of High-Priority Formulas (Unit 1)

  1. Transmission line equations:

    $$\displaystyle \frac{\partial V}{\partial x} = -(R+j\omega L)I $$, $$\displaystyle \frac{\partial I}{\partial x} = -(G+j\omega C)V $$

  2. Propagation constant:

    $$\displaystyle \gamma = \sqrt{(R+j\omega L)(G+j\omega C)} = \alpha + j\beta $$

  3. Characteristic impedance:

    $$\displaystyle Z_0 = \sqrt{\frac{R+j\omega L}{G+j\omega C}} $$

  4. Quarter-wave input impedance:

    $$\displaystyle Z_{in} = Z_0^2 / Z_L $$

  5. Reflection coefficient:

    $$\displaystyle \Gamma = \frac{Z_L - Z_0}{Z_L + Z_0} $$

  6. VSWR:

    $$\displaystyle S = \frac{1+|\Gamma|}{1-|\Gamma|} $$

  7. From Z_oc and Z_sc:

    $$\displaystyle Z_0 = \sqrt{Z_{oc} Z_{sc}} $$, $$\displaystyle \gamma = \cosh^{-1}(Z_{oc}/Z_0) $$

[!TIP]

Exam Strategy: For derivation questions, start with the infinitesimal model and apply KVL/KCL. For calculation problems, first identify given/required constants and use the appropriate formula chain.

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