UNIT 2: RCC DESIGN & DETAILING - SHORT NOTES
(Aligned with CE-601 Past Papers 2022-2025)
1. FUNDAMENTALS OF LIMIT STATE DESIGN (LSD)
Philosophy: LSD is a probabilistic method ensuring structure does not reach limit states (collapse, serviceability) during design life. Contrasts with Working Stress Method (WSM) which uses elastic theory with constant safety factors.
Key Parameters:
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Characteristic Loads ($$\displaystyle F_k $$): Loads with 95% survival probability (dead, live, wind, seismic).
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Characteristic Strengths ($$\displaystyle f_{ck} $$, $$\displaystyle f_{yk} $$): Material strengths with 5% defect probability.
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Partial Safety Factors:
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Load factors ($$\displaystyle \gamma_f $$): 1.5 (DL+LL), 1.2 (DL only), 0.9 (earthquake).
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Material factors ($$\displaystyle \gamma_m $$): 1.5 (concrete), 1.15 (steel).
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Stress-Strain Curves (IS 456):
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Concrete: Parabolic-rectangular for LSM. For WSM, modulus of elasticity $$\displaystyle E_c = 5000\sqrt{f_{ck}} $$.
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Steel: Linear elastic up to yield, then plastic. $$\displaystyle E_s = 2 \times 10^5 $$ N/mm².
Assumptions in Flexure (IS 456):
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Plane sections remain plane.
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Tensile strength of concrete ignored.
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Perfect bond between steel & concrete.
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Strain in steel & concrete at same level is equal.
[!TIP] Exam Focus: Difference between balanced section in LSM (x_u = x_{u,lim}) vs. WSM (σ_c = σ_{c,max}, σ_st = f_s).
2. FLEXURAL DESIGN OF BEAMS
Singly Reinforced Rectangular Section (LSM)
Balanced Section: NA at limiting depth $$\displaystyle x_{u,lim} = 0.48d $$ (Fe415). Strain in steel = 0.87f_y/Es + 0.002. Moment Capacity:
$$M_u = 0.36 f_{ck} b x_u (d - 0.42 x_u) \quad \text{or} \quad M_u = 0.87 f_y A_{st} z$$
where $$\displaystyle z = d - 0.42 x_u $$ (lever arm).
Design Steps for Given $$\displaystyle M_u $$:
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Compute $$\displaystyle M_u = 1.5 \times M $$ (service load moment).
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Find $$\displaystyle R_u = \frac{M_u}{b d^2} $$.
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From $$\displaystyle R_u $$ chart, get $$\displaystyle p_t = \frac{A_{st}}{bd} \times 100 $$.
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Compute $$\displaystyle A_{st} = \frac{p_t}{100} b d $$.
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Check: $$\displaystyle x_u = \frac{0.87 f_y A_{st}}{0.36 f_{ck} b} < 0.48d $$.
Under/Over-Reinforced:
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Under: $$\displaystyle A_{st} < A_{st,lim} $$ → $$\displaystyle x_u < x_{u,lim} $$ (ductile failure).
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Over: $$\displaystyle A_{st} > A_{st,lim} $$ → $$\displaystyle x_u > x_{u,lim} $$ (brittle, avoid).
Doubly Reinforced Beams
Necessity: When $$\displaystyle M_u > M_{u,lim} $$ for given $b,d$. Design:
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Compute $$\displaystyle M_{u1} = M_{u,lim} $$ for section with $$\displaystyle A_{st,lim} $$.
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Additional moment $$\displaystyle M_{u2} = M_u - M_{u1} $$.
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Additional steel $$\displaystyle A_{sc} = \frac{M_{u2}}{0.87 f_y (d - d')} $$.
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Total $$\displaystyle A_{st} = A_{st,lim} + A_{sc} $$ (since both steels at same stress).
T-Beams
Effective Flange Width ($$\displaystyle b_f $$):
$$b_f = b_w + \frac{l_o}{6} \quad \text{or} \quad b_f = b_w + 4D_f \quad \text{or} \quad b_f = \text{spacing of beams}$$
Take least.
Analysis:
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If $$\displaystyle x_u \leq D_f $$: NA in flange → treat as rectangular with $$\displaystyle b = b_f $$.
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If $$\displaystyle x_u > D_f $$: NA in rib → consider flange contribution as $$\displaystyle C_{f} = 0.45 f_{ck} (b_f - b_w) D_f $$.
3. SHEAR AND TORSION IN BEAMS
Shear Design
Critical Sections: At support face & at $d$ from support face for simply supported beams. Nominal Shear Stress:
$$\tau_v = \frac{V_u}{b d}$$
Design Shear Strength: $$\displaystyle \tau_{c} $$ from Table 19 (IS 456) based on $$\displaystyle p_t $$ and $$\displaystyle f_{ck} $$.
Shear Reinforcement:
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If $$\displaystyle \tau_v > \tau_{c,max} $$: Redesign section.
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If $$\displaystyle \tau_c < \tau_v < \tau_{c,max} $$: Provide stirrups.
$$A_{sv} = \frac{(\tau_v - \tau_c) b s}{0.87 f_y} \quad \text{or} \quad \frac{V_{us}}{0.87 f_y d}$$
where $s$ = spacing.
Maximum Spacing: $$\displaystyle s_{max} = 0.75d $$ (stirrups), $d$ (bent-up bars).
Torsion
Ultimate Torsional Moment $$\displaystyle T_u $$:
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Longitudinal steel: $$\displaystyle A_{st} = \frac{T_u}{f_y} \times \frac{u}{2p_t d} $$ (approx).
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Transverse (stirrups): $$\displaystyle A_{sv} \times \frac{s_v}{p_{hov}} = \frac{T_u}{f_y} $$.
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Reinforcement Detailing: Closed ties along entire length, additional longitudinal bars at corners.
[!TIP] Common Pitfall: For torsion, provide both longitudinal & transverse reinforcement. Ignoring transverse leads to failure.
4. COMPRESSION MEMBERS (COLUMNS)
Short Columns (Uni-axial Bending)
Design using Interaction Diagram (IS 456):
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Compute $$\displaystyle P_u / (f_{ck} b D) $$ and $$\displaystyle M_u / (f_{ck} b D^2) $$.
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Get $$\displaystyle p_t $$ from chart.
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Calculate $$\displaystyle A_{sc} = \frac{p_t}{100} b D $$.
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Provide bars along column face parallel to bending (2 sides) or all four sides.
Limits: $$\displaystyle p_{t,min} = 0.8\% $$, $$\displaystyle p_{t,max} = 4\% $$ (ties), $6\%$ (spiral).
Bi-axial Bending
Use IS 456 Eq. 39:
$$\frac{M_{ux}}{M_{ux1}} + \frac{M_{uy}}{M_{uy1}} \leq 1$$
where $$\displaystyle M_{ux1}, M_{uy1} $$ are moments for same $$\displaystyle P_u $$ from interaction diagram about x & y axes.
Bar Arrangement: Place bars at corners for equal moment resistance about both axes. Minimum 4 bars for rectangular, 6 for circular.
Circular Columns
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Lateral Ties: Diameter ≥ 8 mm, spacing ≤ least lateral dimension, ≥ 300 mm.
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Helical Reinforcement: Pitch ≤ 75 mm, ≥ 25 mm, ≥ 6 times core dia. Helical confinement increases load capacity by 10% if pitch criteria met.
5. FOOTINGS
Isolated Rectangular Footing
Design Steps:
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Load: $$\displaystyle P_u = 1.5 \times (P_{col} + self-weight) $$.
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Base area: $$\displaystyle A = \frac{P_u}{q_{safe}} $$ (consider eccentricity if any).
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Thickness: For shear, $$\displaystyle h \geq \frac{V_u}{\tau_c b} $$; for moment, $$\displaystyle M_u = \frac{P_u e}{2} $$.
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Critical Sections:
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Shear: At $d$ from face of column (one-way) & at $d$ from face in both directions (two-way).
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Bending: At face of column.
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Reinforcement: $$\displaystyle M_u = 0.87 f_y A_{st} (d - a/2) $$.
Stepped Footing
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For heavy loads, provide steps to reduce punching shear.
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Each step designed as individual footing.
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Total depth = sum of step heights + top slab thickness.
[!TIP] Soil Pressure: For eccentric loading, $$\displaystyle q_{max/min} = \frac{P}{A} \pm \frac{M}{Z} $$. Check $$\displaystyle q_{max} \leq SBC $$.
6. SLABS
One-Way Slab
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$$\displaystyle l_y / l_x > 2 $$.
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Moment Coefficients (IS 456): Simply supported: $+0.083$, $-0.083$; Continuous: $+0.063$, $-0.075$ (end), $-0.05$ (int).
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Design: $$\displaystyle M_u = \text{coeff} \times w l_x^2 $$. Provide main bars along short span, distribution along long span.
Two-Way Slab
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$$\displaystyle l_y / l_x \leq 2 $$.
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Coefficients (Table 26, IS 456): For restrained corners, $+0.076$, $-0.075$ (edges), $-0.063$ (corners).
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Thickness: $l/d \leq 35$ (simply supported), 32 (continuous) for Fe415.
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Critical Sections: At support faces for negative moments, mid-span for positive.
Flat Slabs
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Drop panel depth ≥ 1/4 slab thickness.
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Column head diameter ≤ 2/3 column size.
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Use direct design method (not in syllabus focus).
7. STAIRCASES
Dog-Legged Stair:
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Waist slab acts as simply supported beam over flights.
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Effective Span: Horizontal distance between landings.
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Loads: Dead (self-weight), live (4 kN/m² office), finishes (1 kN/m²).
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Design Moment: $$\displaystyle M_u = \frac{w l^2}{8} $$ (if simply supported).
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Reinforcement: Main bars (longitudinal) along slope, distribution bars perpendicular.
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Landing: Cantilevered or supported on walls/beams.
Design Steps:
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Determine number of risers $$\displaystyle N = H/R $$, treads $N-1$.
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Horizontal length $$\displaystyle L = (N-1) \times T $$.
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Thickness $t \geq 100$ mm, $l/d \leq 25$.
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Calculate $$\displaystyle A_{st} $$ for $$\displaystyle M_u $$, check shear.
[!TIP] Sketch: Show waist slab as inclined beam, reinforcement in both directions, landing support details.
8. BOND, DEVELOPMENT LENGTH & LAP SPLICES
Bond Failure Mechanisms
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Pull-out: Bar slips out (good bond).
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Splitting: Concrete splits along bar (poor bond, high confinement needed).
Factors Affecting Bond:
- Concrete strength, bar surface (deformed > plain), bar diameter, confinement, loading type.
Development Length ($$\displaystyle L_d $$)
$$L_d = \frac{\phi \sigma_{st}}{4 \tau_{bd}}$$
where $$\displaystyle \tau_{bd} = k \sqrt{f_{ck}} $$ (k=1.6 for mild steel, 1.4 for HYSD), $$\displaystyle \sigma_{st} = 0.87 f_y $$.
Modifications:
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For compression: $$\displaystyle L_d $$ reduced by 25%.
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For epoxy-coated bars: increase by 50%.
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For >12 mm bars: increase by 20%.
Lap Splices
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Tension Lap Length: $$\displaystyle L_{lap} = L_d \times \frac{\text{area of larger bar}}{\text{area of smaller bar}} $$ (but ≥ $$\displaystyle L_d $$ of larger bar).
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Staggering: Lap length ≥ $75\phi$ or $600$ mm, whichever more. Stagger by ≥ $75\phi$ or $600$ mm.
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Compression Lap: $$\displaystyle 0.5 L_d $$ (but ≥ $24\phi$).
[!TIP] Common Error: Lap length for different bar sizes—use larger bar's $$\displaystyle L_d $$ as base, multiply by area ratio.
9. DEFLECTION & CRACKING CONTROL
Span/Effective Depth Ratio (IS 456 Table 19)
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Cantilever: 7
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Simply supported: 20
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Continuous: 26
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For Fe415, modify by factor $$\displaystyle k_t = \frac{0.25}{0.25 + \frac{M_t}{M}} \leq 1.5 $$.
Measures to Reduce Deflection:
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Increase effective depth.
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Use higher grade steel (Fe500 > Fe415).
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Add compression steel (doubly reinforced).
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Use smaller bar spacing.
Cracking Control:
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Minimum Reinforcement: $$\displaystyle A_{st,min} = 0.12\% bD $$ (Fe415) for slabs.
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Bar Spacing: ≤ 3D or 300 mm (whichever less) for slabs; ≤ 300 mm for beams.
10. DETAILING & DRAWING
Cross-Sections (Sketches Required):
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Singly/doubly reinforced beam (show $$\displaystyle A_{st} $$, $$\displaystyle A_{sc} $$, cover, stirrups).
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T-beam (flange width, NA position).
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Column (uni-axial: bars on two faces; bi-axial: bars at corners).
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Isolated footing (plan: column location, bars; section: depth, bars, cover).
Critical Sections Summary:
| Element | Flexure | Shear |
|---|---|---|
| Beam | At mid-span (pos), supports (neg) | At $d$ from support face |
| Slab | Mid-span (pos), supports (neg) | At $d$ from support (one-way) |
| Footing | At column face | At $d$ from column face (both dir.) |
| Column | At top/bottom for moments | Not critical (axial) |
Bar Bending Schedule (BBS) Items:
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Bar mark, diameter, cutting length, number, total length.
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Cutting length = clear span + 2 × hook length - bends (4d per bend).
Cover (IS 456):
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Moderate exposure: 20 mm (beams), 30 mm (slabs).
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Severe: 45 mm (beams), 30 mm (slabs).
11. COMPARATIVE STUDIES
LSM vs. WSM
| Feature | LSM | WSM |
|---|---|---|
| Approach | Probabilistic, ultimate load | Deterministic, working load |
| Safety | Partial factors on loads & materials | Single factor of safety |
| Balanced Section | $$\displaystyle x_u = 0.48d $$ (Fe415) | $$\displaystyle \sigma_c = \sigma_{c,max} $$, $$\displaystyle \sigma_{st} = f_s $$ |
| Stress Block | Parabolic-rectangular (0.36f_ck) | Linear (σ_c = (σ_{c,max}/x) × depth) |
| Moment Capacity | $$\displaystyle M_u = 0.36 f_{ck} b x_u (d - 0.42 x_u) $$ | $$\displaystyle M = (σ_c b x/2)(d - x/3) $$ |
WSM Example:
Given $$\displaystyle σ_c $$, $$\displaystyle σ_{st} $$, $m$:
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$$\displaystyle C = T $$ → $$\displaystyle \frac{σ_c}{m} b x = σ_{st} A_{st} $$.
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$$\displaystyle M = \frac{σ_c}{m} b x \left(d - \frac{x}{3}\right) $$.
12. SPECIAL TOPICS FROM PAST PAPERS
Composite Beam-Slab (Hall Design)
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Effective Flange Width: $$\displaystyle b_f = b_w + \frac{l_o}{6} $$ or $$\displaystyle b_f = b_w + 4D_f $$ (min).
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Design: Treat as T-beam. Compute $$\displaystyle x_u $$: if $$\displaystyle x_u \leq D_f $$, use $$\displaystyle b_f $$; else, subtract flange contribution.
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Safe Superimposed Load: Find $$\displaystyle M_{u,allow} $$ for given steel, then $$\displaystyle w_{allow} = \frac{8M_{allow}}{l^2} $$ minus self-weight.
Two-Way Slab Design Steps (Complete)
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Check $$\displaystyle l_y/l_x \leq 2 $$.
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Determine slab thickness: $l/d \leq 32$ (continuous, Fe415).
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Compute total load $$\displaystyle w = DL + LL + finish $$.
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Find $$\displaystyle M_u = \text{coeff} \times w l_x^2 $$.
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Calculate $$\displaystyle A_{st} = \frac{M_u}{0.87 f_y z} $$ (z=0.9d).
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Check for shear: $$\displaystyle \tau_v = \frac{V_u}{b d} < \tau_c $$.
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Provide distribution steel (min 0.12%).
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Detailing: main bars in both directions, crank at supports.
Types of Footings (with Sketches)
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Isolated: For single column.
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Combined: For two columns.
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Stepped: For heavy loads, in stages.
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Raft: For poor soil, covers entire area.
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Mat: Similar to raft, with beams.
Final Exam Strategy:
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Numericals: Start with $$\displaystyle M_u = 1.5M $$, check $$\displaystyle x_u $$ limit, use IS 456 tables for $$\displaystyle \tau_c $$, $$\displaystyle p_t $$.
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Theoretical: Define terms, draw strain diagrams, list assumptions.
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Detailing: Always show clear cover, bar labels, stirrup spacing.
\boxed{\text{Master LSM fundamentals, T-beam flange width, shear critical sections, and column interaction diagrams for high marks.}}